On Tue, 2008-07-29 at 11:28 -0500, Edna Bell wrote:
> Hi again!
>
>
> Suppose I have the following:
>
> > xy <- round(rexp(20),1)
> > xy
> [1] 0.1 3.4 1.6 0.4 1.0 1.4 0.2 0.3 1.6 0.2 0.0 0.1 0.1 1.0 2.0 0.9
> 2.5 0.1 1.5 0.4
> > table(xy)
> xy
> 0 0.1 0.2 0.3 0.4 0.9 1 1.4 1.5 1.6 2 2.5 3
On 29-Jul-08 16:28:26, Edna Bell wrote:
> Hi again!
> Suppose I have the following:
>
>> xy <- round(rexp(20),1)
>> xy
> [1] 0.1 3.4 1.6 0.4 1.0 1.4 0.2 0.3 1.6 0.2 0.0 0.1 0.1 1.0 2.0 0.9
> 2.5 0.1 1.5 0.4
>> table(xy)
> xy
> 0 0.1 0.2 0.3 0.4 0.9 1 1.4 1.5 1.6 2 2.5 3.4
> 1 4 2 1
# is that what you want?
table(cut(xy,seq(0,max(xy)+.4,by=.4)))
# or this
table(cut(xy,hist(xy)$breaks)) # not the same
regards,
PF
+-
| Patrizio Frederic
| Research associate in Statistics,
| Department of Economics,
| University of Modena and
Hi again!
Suppose I have the following:
> xy <- round(rexp(20),1)
> xy
[1] 0.1 3.4 1.6 0.4 1.0 1.4 0.2 0.3 1.6 0.2 0.0 0.1 0.1 1.0 2.0 0.9
2.5 0.1 1.5 0.4
> table(xy)
xy
0 0.1 0.2 0.3 0.4 0.9 1 1.4 1.5 1.6 2 2.5 3.4
1 4 2 1 2 1 2 1 1 2 1 1 1
>
Is there a way to s
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