I did have the problem of not having two continuous variables and this
approach circumvents this, allowing me in fact to plot the rownames.
Prof Brian Ripley wrote:
>
> On Tue, 27 May 2008, T.D.Rudolph wrote:
>
>>
>> In the following example:
>> x <- rnorm(1:100)
>> y <- seq(from=-2.5, to=3.
On Tue, 27 May 2008, T.D.Rudolph wrote:
In the following example:
x <- rnorm(1:100)
y <- seq(from=-2.5, to=3.5, by=0.5)
z <- as.matrix(table(cut(x,c(-Inf, y, +Inf
## I wish to transform the values in z
j <- log(z)
## Yet retain the row names
row.names(j)<-row.names(z)
Hmm. The rownames
In the following example:
x <- rnorm(1:100)
y <- seq(from=-2.5, to=3.5, by=0.5)
z <- as.matrix(table(cut(x,c(-Inf, y, +Inf
## I wish to transform the values in z
j <- log(z)
## Yet retain the row names
row.names(j)<-row.names(z)
Now, how can I go about creating a scatterplot with row.names(
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