Dear Peter
Thank you
Lo and behold
Now I've got it
In code
aggregate(.~ id, lapply(df, as.character), FUN =
function(x)paste(sort(x), collapse = ''), na.action = na.pass)
there are no contradictions with NAs.
na.action = na.pass is applied to aggregate where default is na.omit.
And afterwards th
Den wrote:
Dear Dennis
Thank you very much for your comprehensive reply and for time you've
spent dealing with my e-mail.
Your kindly explanation made things clearer for me.
After your explanation it looks simple.
lapply with chosen options takes small part of cycle with same id
(eg. df[df$id==
Dear Dennis
Thank you very much for your comprehensive reply and for time you've
spent dealing with my e-mail.
Your kindly explanation made things clearer for me.
After your explanation it looks simple.
lapply with chosen options takes small part of cycle with same id
(eg. df[df$id==3,"cycle2"] an
Den wrote:
Dear R community
Recently, dear Henrique Dallazuanna literally saved me solving one
problem on data transformation which follows:
(n_, _n, j_, k_ signify numbers)
SOURCE DATA:
id cycle1 cycle2 cycle3 … cycle_n
1 c c c c
1 m
Dear R community
Recently, dear Henrique Dallazuanna literally saved me solving one
problem on data transformation which follows:
(n_, _n, j_, k_ signify numbers)
SOURCE DATA:
id cycle1 cycle2 cycle3 … cycle_n
1 c c c c
1 m m m
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