On Fri, Nov 9, 2012 at 5:21 PM, tesssa wrote:
> How do you lm throw away excess data points. I am following the
> documentation with no success
Why would you want to throw away this data? I think that's generally
considered sub-optimal model-fitting technique, thought it might
explain your diffi
ox.com
Subject: Re: [R] lm function - strange error
Hi Tessa, I agree with John. I think you've made a typo, but looking at your
data I think the zero concentration should not be there. Try plotting it.
conc = c(10, 20, 30, 40, 50)
signal = c (4, 22, 44, 60, 82)
plot(
> -Original Message-
> From: sarah.gos...@gmail.com
> Sent: Fri, 9 Nov 2012 14:34:57 -0500
> To: jrkrid...@inbox.com
> Subject: Re: [R] lm function - strange error
>
> On Fri, Nov 9, 2012 at 2:20 PM, John Kane wrote:
>>
>>> -Original Message--
60, 82, NA)
> lm.r <- lm( signal ~ conc)
> summary(lm.r)
>
> I hope this helps.
> John Kane
> Kingston ON Canada
>
>
> > -Original Message-
> > From: tesara...@gmail.com
> > Sent: Fri, 9 Nov 2012 09:36:23 -0800 (PST)
> > To: r-he
On Fri, Nov 9, 2012 at 2:20 PM, John Kane wrote:
>
>> -Original Message-
>> From: dwinsem...@comcast.net
>> Sent: Fri, 9 Nov 2012 10:56:48 -0800
>> To: tesara...@gmail.com
>> Subject: Re: [R] lm function - strange error
>>
>>
>> On Nov 9,
> -Original Message-
> From: dwinsem...@comcast.net
> Sent: Fri, 9 Nov 2012 10:56:48 -0800
> To: tesara...@gmail.com
> Subject: Re: [R] lm function - strange error
>
>
> On Nov 9, 2012, at 9:16 AM, tesssa wrote:
>
>> Sorry it is not a comma but a t
lm.r)
I hope this helps.
John Kane
Kingston ON Canada
> -Original Message-
> From: tesara...@gmail.com
> Sent: Fri, 9 Nov 2012 09:36:23 -0800 (PST)
> To: r-help@r-project.org
> Subject: Re: [R] lm function - strange error
>
> Here is the document
>
> http://
On Nov 9, 2012, at 9:16 AM, tesssa wrote:
> Sorry it is not a comma but a tilda. The R.help message editor Please
> replace the dash with a tilda as lm function requires
It might be interesting to have such a supernatural entity zooming around the
Rhelp Universe answering prayers from newbi
Here is the document
http://www.montefiore.ulg.ac.be/~kvansteen/GBIO0009-1/ac20092010/Class8/Using%20R%20for%20linear%20regression.pdf
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How do you lm throw away excess data points. I am following the
documentation with no success
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___
Sorry it is not a comma but a tilda. The R.help message editor Please
replace the dash with a tilda as lm function requires
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anada
> -Original Message-
> From: tesara...@gmail.com
> Sent: Fri, 9 Nov 2012 08:37:13 -0800 (PST)
> To: r-help@r-project.org
> Subject: [R] lm function - strange error
>
> I am following a document teaching how to use regression and right at the
> onset I get a
On Fri, Nov 9, 2012 at 4:37 PM, tesssa wrote:
> I am following a document teaching how to use regression and right at the
> onset I get an R error. I understand that variables "conc" and "signal"
> should have the same length but I am using the what R manual suggests to
> drop the error and it i
I am following a document teaching how to use regression and right at the
onset I get an R error. I understand that variables "conc" and "signal"
should have the same length but I am using the what R manual suggests to
drop the error and it is not cooperating. What gives? The manual says
that
I don't know if you've gotten any follow up, but here are some quick reactions:
1) You make reference to the columns of y but your dput(y) does not
provide columns,
2) It's still not clear to me what all this data actually means? Do
you have multiple observations of the dependent variable corresp
When I tried dput function, the result was this:
> dput(x)
c(20, 200, 2000, 2)
> dput(y)
c(0.45, 0.05, 0.5, 0.4, 0, 0.5, 0.4, 0.05, 0.4, 0.25, 0.35, 0.5,
0.05, 0.4, 0.5, 0.5, 0.5, 0.25, 0.85, 0.5, 0.5, 0.5, 0.25, 0.4,
0.25, 0.25, 0.4, 0.25, 0.5, 0.15, 0.25, 0.1, 0.25, 0.25, 0.015,
0.4, 0.5
Could you dput() the structure of x and y: I'm having trouble
visualizing how your data is set up.
Michael
On Mon, Oct 24, 2011 at 12:07 PM, Julie wrote:
> The variable y is made of four columns, each paired to 20, 200, 2000 or 20
> 000.
>> y <- c(rdiktator20, rDiktator200, rDikt2000, rDikt2
The variable y is made of four columns, each paired to 20, 200, 2000 or 20
000.
> y <- c(rdiktator20, rDiktator200, rDikt2000, rDikt2)
So I guess the problem is in the fact that I did not specify it correctly,
is it so? How can I tell R properly that one part of y matches to one part
of x?
Th
X and y must have the same number of elements, and NA values must be removed
(?na.omit)
---
Jeff Newmiller The . . Go Live...
DCN: Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar
You are trying to regress ~372 observations of the dependent against
~4 observations of the independent variable. Ask yourself again if
this makes sense.
A further hint might be given by this
y = rnorm(5); x = y[1:4]
lm(y~x)
Michael
On Mon, Oct 24, 2011 at 11:13 AM, Julie wrote:
> Hello,
> I a
Hello,
I am trying to get a linear model of y ~ log(x).
*> lm (y~log(x))*
However, I always get an error report:
/Error in model.frame.default(formula = y ~ log(x), drop.unused.levels =
TRUE) :
variable lengths differ (found for 'log(x)')/
*Here was my y:*
> y
[1]0.4500.050
PM
To: kMan
Subject: Re: [R] lm function in R
Thank you so much, kMan. That makes sense. Only one question, how can I
see the value of 'error'? Here's what I see:
Call:
lm(formula = Y ~ X1 * X2 * X3, na.action = na.exclude)
Coefficients:
(Intercept)
turday, February 13, 2010 5:04 PM
> To: Bert Gunter
> Cc: r-help@r-project.org
> Subject: Re: [R] lm function in R
>
> I tried..
>
> mod = lm(Y ~ X1*X2*X3, na.action = na.exclude)
> formula(mod)
>
> This produced
> Y ~ X1 * X2 * X3
>
>
> When I typ
;>> Is it correct to assume then that...
>>>>
>>>> When I put + R evaluates the following equation:
>>>> Y-Hat = b0 + b1X1 + b2X2 + . . . bkXk + 7 7 7 + bkXk
>>>>
>>>>
>>>> But when I put * R evaluates the following equa
iscussurus
-
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Something Something
Sent: Saturday, February 13, 2010 5:04 PM
To: Bert Gunter
Cc: r-help@r-project.org
Subject: Re: [R] lm function in R
I tried..
mod = lm
ia, which is surprisingly good for that sort
> of question these days.
>
> --
> David.
>
>>
>>
>>
>>
>>
>> On Sat, Feb 13, 2010 at 1:30 PM, Bert Gunter
>> wrote:
>>
>> ?formula
>>>
>>>
>>> Bert Gunter
Feb 13, 2010 at 1:30 PM, Bert Gunter wrote:
>
>> ?formula
>>
>>
>> Bert Gunter
>> Genentech Nonclinical Statistics
>>
>> -Original Message-
>> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
>> On
>> Behalf
ordlund
Cc: r-help@r-project.org
Subject: Re: [R] lm function in R
Thanks Dan. Yes that was very helpful. I didn't see the change
from '*'
to
'+'.
Seems like when I put * it means - interaction & when I put + it's
not an
interaction.
Is it correct to assum
> Genentech Nonclinical Statistics
>
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On
> Behalf Of Something Something
> Sent: Saturday, February 13, 2010 1:24 PM
> To: Daniel Nordlund
> Cc: r-help@r-project.org
> Subjec
oject.org [mailto:r-help-boun...@r-project.org]
> > On Behalf Of Something Something
> > Sent: Friday, February 12, 2010 5:28 PM
> > To: Phil Spector; r-help@r-project.org
> > Subject: Re: [R] lm function in R
> >
> > Thanks for the replies everyone. Greatly app
g [mailto:r-help-boun...@r-project.org]
> > On Behalf Of Something Something
> > Sent: Friday, February 12, 2010 5:28 PM
> > To: Phil Spector; r-help@r-project.org
> > Subject: Re: [R] lm function in R
> >
> > Thanks for the replies everyone. Greatly appreciate it.
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Something Something
> Sent: Friday, February 12, 2010 5:28 PM
> To: Phil Spector; r-help@r-project.org
> Subject: Re: [R] lm function in R
>
> Thanks
Thanks for the replies everyone. Greatly appreciate it. Some progress, but
now I am getting the following values when I don't use "as.factor"
13.14167 25.11667 28.34167 49.14167 40.39167 66.86667
Is that what you guys get?
On Fri, Feb 12, 2010 at 5:00 PM, Phil Spector wrote:
> By converting
Hello,
I am trying to learn how to perform Multiple Regression Analysis in R. I
decided to take a simple example given in this PDF:
http://www.utdallas.edu/~herve/abdi-prc-pretty.pdf
I created a small CSV called, students.csv that contains the following data:
s1 14 4 1
s2 23 4 2
s3 30 7 2
s4 50
Hi,
I do not use R lenguage for programming, hence Im trying to understand how
are specified the models below. I been reading some webpages with
information about the notation in the "lm" function, but havent understand
exactly what does the ":" do. Can some one give me an explenation of the
mode
Cleber Nogueira Borges wrote:
my linear model is y=c+a*x1+b*x2 i tried to found a, c, b by the
use of:
mymodel<-lm(y~1+x1+x2) where y, x1, x2 are 3 vectors with the same
length
the result is a=NA.so i want to know where is the problem.
It's the sum of x1 and x2 equal to one?
run the command:
my linear model is y=c+a*x1+b*x2 i tried to found a, c, b by the use
of:
mymodel<-lm(y~1+x1+x2) where y, x1, x2 are 3 vectors with the same
length
the result is a=NA.so i want to know where is the problem.
It's the sum of x1 and x2 equal to one?
run the command: round( sum( c(x1,x2) ),12)==1
Hi,
Cleber Nogueira Borges wrote:
hanen wrote:
hi,
my linear model is y=c+a*x1+b*x2 i tried to found a, c, b by the use of:
mymodel<-lm(y~1+x1+x2) where y, x1, x2 are 3 vectors with the same length
the result is a=NA.so i want to know where is the problem.
It's the sum of x1 and x2 equal t
On 30/05/2008, at 9:57 AM, Jorge Ivan Velez wrote:
Dear Hanen,
You don't need "1" in your R code. Try this:
# Model
mymodel<-lm(y~x1+x2)
# Coefficients
summary(mymodel)
See also ?lm.
That's not the problem. The ``1'' is redundant but does no harm.
There is presumably something ``wrong''
hanen wrote:
hi,
my linear model is y=c+a*x1+b*x2 i tried to found a, c, b by the use of:
mymodel<-lm(y~1+x1+x2) where y, x1, x2 are 3 vectors with the same length
the result is a=NA.so i want to know where is the problem.
It's the sum of x1 and x2 equal to one?
run the command: round( sum(
Dear Hanen,
You don't need "1" in your R code. Try this:
# Model
mymodel<-lm(y~x1+x2)
# Coefficients
summary(mymodel)
See also ?lm.
Thanks,
Jorge
On Thu, May 29, 2008 at 5:15 PM, hanen <[EMAIL PROTECTED]> wrote:
>
> hi,
>
>
> my linear model is y=c+a*x1+b*x2 i tried to found a, c, b by t
hi,
my linear model is y=c+a*x1+b*x2 i tried to found a, c, b by the use of:
mymodel<-lm(y~1+x1+x2) where y, x1, x2 are 3 vectors with the same length
the result is a=NA.so i want to know where is the problem.
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