thanks Rainer,
it worked!
> From: rainer.schuerm...@gmx.net
> To: r-help@r-project.org; fin_e...@hotmail.com
> Subject: Re: [R] for/if loop in R
> Date: Fri, 22 Jul 2011 03:23:19 +0200
>
> For me, this works:
>
> > Now, I want to add a 4th column, trend
> priceda
For me, this works:
> Now, I want to add a 4th column, trend
pricedata$trend <- 0
> which can have 2 values 0 or 1. if return>1%, trend=1 else trend=0.
pricedata$trend <- ifelse( pricedata$return > .01, 1, 0 )
Rgds,
Rainer
On Thursday 21 July 2011 19:39:15 financial engineer wrote:
>
> hi,
>
hi,
Can someone please help me figure out where I am making a mistake in my for/if
loop:
I have a data frame (112 rows) called pricedata with 3 columns: date, prices,
return.
Now, I want to add a 4th column, trend, which can have 2 values 0 or 1. if
return>1%, trend=1 else trend=0.
so, this
Hi ya, I've revised the code (and finally know what I m doing.. :-D)
The good news is.. I dont get any error message, but the bad news is the
following optim generate no results. I still think there is something to do
with my loop... can anyone advice? Thanks again!!!
pp=1
rr=1
for (ii in 1:n
Within the loops you are changing the loop variables (pp & rr). Why
are you doing this? THis might be causing your problem of what sounds
like an infinite loop. You probably want to rethink what you are
trying to do in the loop.
On Wed, Jan 28, 2009 at 3:21 AM, SnowManPaddington wrote:
>
> Hi,
What are you trying to do with
> for (pp in 1:pp+1){
?
Also, note that 1:rr+1 and 1:(rr+1) mean different things.
Zhou
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Hi, it's my first time to write a loop with R for my homework. This loop is
part of the function. I wanna assign values for hll according to panel
[ii,1]=pp. I didn't get any error message in this part. but then when I
further calculate another stuff with hll, the function can't return. I think
it
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