In addition to what the others have told you, it looks like you might
be confusing
matrices with data.frames. Please see
?data.frame
I think what you are looking for is
> b <- c('a','b','c')
> c <- c("ee","tt","rr")
> k <- cbind(a,b,c)
> K <- data.frame(a, b, c)
> K
a b c
1 1 a ee
2 2 b tt
3
Hard to say, not sure what you want to do. But the columns are not denoted by
[a], [b] or [c]. You should learn to use the str function to understand what
various expressions really are, and return to the "Introduction to R" document
that comes with the software. There is a distinct difference b
Hi,
Try:
k[,"a"]
#[1] "1" "2" "3"
k[,"b"]
#[1] "a" "b" "c"
k[,"c"]
#[1] "ee" "tt" "rr"
A.K.
On Tuesday, October 22, 2013 11:37 PM, Vivek Singh
wrote:
Hi All,
I have create a matrix using cbind() function as follows:
> a=c(1,2,3)
> b=c('a','b','c')
> c=c("ee","tt","rr")
> k=cbi
Hi All,
I have create a matrix using cbind() function as follows:
> a=c(1,2,3)
> b=c('a','b','c')
> c=c("ee","tt","rr")
> k=cbind(a,b,c)
Problem: when we print the matrix k,
> k
a b c
[1,] "1" "a" "ee"
[2,] "2" "b" "tt"
[3,] "3" "c" "rr"
we can see that rows are represented
And here is a second solution, that differs in what happens if the variables
have differing lengths:
> var1 <- 1:4
> var2 <- 1:3
> sapply(ls(patt="^var[0-9]"), get)
$var1
[1] 1 2 3 4
$var2
[1] 1 2 3
> do.call("cbind", lapply(ls(patt="^var[0-9]"), get))
[,1] [,2]
[1,]11
[2,]2
Try this:
sapply(ls(patt="^var[0-9]"), get)
On 13/11/2007, livia <[EMAIL PROTECTED]> wrote:
>
> Hello everyone,
>
> I would like to use the "cbind" function to construct a dataset, combining
> some variable I defined before.
> The codes are something like
>
> var1 <- ...
> var2 <- ...
> var2 <- .
Hello everyone,
I would like to use the "cbind" function to construct a dataset, combining
some variable I defined before.
The codes are something like
var1 <- ...
var2 <- ...
var2 <- ...
...
data <- cbind(var1,var2,var3...)
The problem is I would like some flexibity in the data, i.e. the numbe
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