ter
Cc: 'Marcio Resende'; r-help@r-project.org
Subject: Re: [R] Sampling procedure
If parsimony is needed, then define a 9-row matrix and send a
randomized indexed version of Example to it:
s<-matrix(NA, nrow=9, ncol=length(Example)/9)
s[,] <- Example[sample(Example, length(Example) )]
net]
Sent: Thursday, October 15, 2009 8:48 AM
To: Bert Gunter
Cc: 'Marcio Resende'; r-help@r-project.org
Subject: Re: [R] Sampling procedure
If parsimony is needed, then define a 9-row matrix and send a
randomized indexed version of Example to it:
s<-matrix(NA, nrow=9, nc
nal Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org
] On
Behalf Of David Winsemius
Sent: Thursday, October 15, 2009 7:55 AM
To: Marcio Resende
Cc: r-help@r-project.org
Subject: Re: [R] Sampling procedure
On Oct 15, 2009, at 10:19 AM, Marcio Resende wrote:
I
, 2009 7:55 AM
To: Marcio Resende
Cc: r-help@r-project.org
Subject: Re: [R] Sampling procedure
On Oct 15, 2009, at 10:19 AM, Marcio Resende wrote:
>
> I would like to divide a vector in 9 groups in a way that each
> number is
> present in only one group.
> In a vector of 783 I would li
On Oct 15, 2009, at 10:19 AM, Marcio Resende wrote:
I would like to divide a vector in 9 groups in a way that each
number is
present in only one group.
In a vector of 783 I would like to divide in 9 different groups of 87
Example <- matrix(c(1:783),ncol = 1)
> Example <- matrix(c(1:783)
I would like to divide a vector in 9 groups in a way that each number is
present in only one group.
In a vector of 783 I would like to divide in 9 different groups of 87
Example <- matrix(c(1:783),ncol = 1)
s1 <- as.matrix(sample(Example,87, re = FALSE))
Example <- Example[-s1]
s2 <- as.matrix(sa
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