Sorry... I missed that the mailing list had been removed from this email.
Tina... always keep the mailing list included when you ask questions.
On Thu, 13 Jun 2019, Jeff Newmiller wrote:
I am sorry I did not read more closely earlier... I agree with Bert... you do
need to spend some time learn
Jeff:
Your solution is not quite what she asked for (she wanted a data frame, not
a list).
Moreover, most of the time it is done automatically as the first step of a
tapply() /filter() type operation or is inherent in modeling and
trellis-type plots. I *still* suspect it is unnecessary, but of cou
I do it regularly.
Base R:
result <- split( DF[ , 4, drop=FALSE ], DF[ , -4 ] )
Tidyverse:
library(tidyr)
result <- nest( DF, time )
filter( result, "a2"==a & "b1"==b & "c1"==c )[[ "data" ]]
On Thu, 13 Jun 2019, Bert Gunter wrote:
Why? I suspect that there is no reason that you need to do t
Why? I suspect that there is no reason that you need to do this.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Thu, Jun 13, 2019 at 1:22 PM Tina
How about just
df$time[match(paste(df$a, df$b, df$c), c(
"co mb o1",
..
"co mb oN"))]
On Fri, 14 Jun 2019 at 08:22, Tina Chatterjee
wrote:
> Hello everyone!
> I have the following dataframe(df).
>
> a<-c("a1","a2","a2","a1","a1","a1")
> b<-c("b1","b1","b1","b1","b1","b2")
> c<-c(
Hello everyone!
I have the following dataframe(df).
a<-c("a1","a2","a2","a1","a1","a1")
b<-c("b1","b1","b1","b1","b1","b2")
c<-c("c1","c1","c1","c1","c1","c2")
time <- c(runif(6,0,1))
df<-data.frame(a,b,c,time)
df
a b c time
1 a1 b1 c1 0.28781082
2 a2 b1 c1 0.02102591
3 a2 b1 c1 0.724
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