On 10/02/2011 11:02 AM, Hosack, Michael wrote:
R experts,
I need to sample two rows without replacement from the following data frame
such that
neither row contains the same 'DOW'. For example, I cannot select both a Monday
morning
and a Monday afternoon. I am using STRATA_NUM as an index to r
R experts,
I need to sample two rows without replacement from the following data frame
such that
neither row contains the same 'DOW'. For example, I cannot select both a Monday
morning
and a Monday afternoon. I am using STRATA_NUM as an index to randomly select
rows from,
since this variable
Hello all,
Here is my solution, in case someone else needs it.
I have a dataframe consisting of two columns.
col1<-factor(c("a","a","b","b","c","c"))
col2<-factor(c("a","b","c","d","e","f"))
somedf<-data.frame(col1,col2)
somedf
col1 col2
1 a d
2 a e
3 b f
Thanks Thierry!
On 04.02.2010, at 13:22, ONKELINX, Thierry wrote:
selection <- subset(somedf, col1 != "a")
sample(selection$col2, 2, replace = TRUE)
I simplified it, but in fact it is not only 'a' to be eliminated, but
thousands of rows.
Can I use:
col1sample<-sample(col1,2,replace=T)
of
data.
~ John Tukey
-Oorspronkelijk bericht-
Van: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
Namens Olga Lyashevska
Verzonden: donderdag 4 februari 2010 14:05
Aan: r-help@r-project.org
Onderwerp: [R] Conditional sampling?
Hello,
I have a dataframe consisting of
Hello,
I have a dataframe consisting of two columns.
> col1<-factor(c("a","a","b","b","c","c"))
> col2<-factor(c("a","b","c","d","e","f"))
> somedf<-data.frame(col1,col2)
> somedf
col1 col2
1 a d
2 a e
3 b f
4 b g
5 c h
6 c i
> s
[mailto:r-help-boun...@r-
> project.org] On Behalf Of Ted Harding
> Sent: Tuesday, January 12, 2010 7:34 AM
> To: r-help@r-project.org
> Cc: ehcpieterse
> Subject: Re: [R] Conditional Sampling
>
> On 12-Jan-10 14:00:24, ehcpieterse wrote:
> > Thanks Ted, your solution
Thanks Ted, it's exactly what I'm after. Thanks for the help.
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On 12-Jan-10 14:00:24, ehcpieterse wrote:
> Thanks Ted, your solution does make perfect sense.
>
> The only question I still have is that I would like to sample
> the remaining 5 observations after I have randomly selected the
> first 10. Given the initial 10, I would like to sample the
> followin
Would the following work, or is there a reason why it would not?
risk.set <- 1:100
first.10 <- sample(risk.set, 10)
remainder <- setdiff(risk.set, first.10)
for ( i in 1:1000 )
{
next.5 <- sample(remainder, 5)
do.something.with(next.5)
}
Best,
Magnus
On 1/12/2010 9:00 AM, ehcpiet
Thanks Ted, your solution does make perfect sense.
The only question I still have is that I would like to sample the remaining
5 observations after I have randomly selected the first 10. Given the
initial 10, I would like to sample the following 5 say 1,000 times to get a
simulated conditional sa
On 12-Jan-10 12:58:13, ehcpieterse wrote:
> Hi,
>
> I am hoping someone can help me with a sampling question.
>
> I am using the following function to sample 10 unique observations:
> x <- sample(1:100, 10, replace=F)
> Given the first 10 observations, I need to sample another 5 unique
> observat
Hi,
I am hoping someone can help me with a sampling question.
I am using the following function to sample 10 unique observations: x <-
sample(1:100, 10, replace=F)
Given the first 10 observations, I need to sample another 5 unique
observations from the remainder. I essentially want to do a Monte
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