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Thanks for your help !
I got another problem with my function :
test <- function(x,bb0=-3,bb1=5,c0=2,r0=0) {
((exp(c0-r0)*(bb0+x)*(bb1-x))/((bb0+x+1)*(bb1-x-1))-1)}
With this :
curve(test(x),from=-10,to=10)
we can see that there are 2 roots : one in [3,4] and one in [5,10]
> uniroot(test,c(5, 1
Hi ,
I would like to know if a R function have the same behaviour than the matlab
solve function.
I tried something with uniroot but I have some problems:
The equation I need to solve is :
exp(c0-r0)*(bb0+x)*(bb1-x)=(bb0+x+1)(bb1-x-1)
So I tried this:
STEP 1: my function test
test <- function(x,
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