f.jamitzky wrote:
>
> For fixed numbers of columns you can use
>
> data.frame(matrix(data, nrow, ncol))
>
> in order to parse the XML data.
>
> htmlTreeParse should be rather quick, but in case it is too slow you could
> use curl for downloading
> the data and xmlstarlet for transformation
f.jamitzky wrote:
>
> You can use htmlTreeParse and xpathApply from the XML library.
> something like:
>
> xpathApply( htmlTreeParse("http://blabla";, useInt=T), "//td", function(x)
> xmlValue(x))
>
> should do it.
>
Thank you, any further ideas how to transform the result into a matrix,
som
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