I have a version that uses bigmemory on my blog, but looks at distance on
a sphere for a 36k * 36K matrix
not hundreds of Gb so I dont know if the approach will work for you
http://stevemosher.wordpress.com/2012/04/12/nick-stokes-distance-code-now-with-big-memory/
Steve
However, I never
see the function level() in raster. also levelplot in rastervis package.
you basically create a raster attribute table coerce the raster to factor
class and plot. check geo sig i have posted the same question there
On Oct 29, 2012 2:15 AM, "Jonsson" wrote:
> This code will read binary file and di
i believe ff has a dataframe class. as for your object data im less clear.
how big is it
On Oct 18, 2012 12:45 PM, "Alexander Shenkin" wrote:
> Hi Folks,
>
> I've been bumping my head against the 4GB limit for 32-bit R. I can't
> go to 64-bit R due to package compatibility issues (ROBDC - possib
thanks Dr. R. this will come in handy in the future as I have a knack for
hanging R.
On Oct 2, 2012 12:01 PM, "Prof Brian Ripley" wrote:
> On 02/10/2012 18:29, Bert Gunter wrote:
>
>> ?history
>>
>> in a fresh R session, to see what might be possible. I'll bet the
>> answer is, "No, you're screwe
1. get programming grapgical user interfaces in R. lawrence and verzani.
2. if you used gwidgets on gtk i could tell you exactly what to do.
3. with the toolkit youve selected i think tlpack controls the way children
are placed in a container. default is top to bottom
On Aug 24, 2012 11:27 PM, "p
I believe chambers book has an example using S4 classes. which isnt much
help for a beginner.
you can do it the old school way. build it by hand with one vector of
pointers and another data structure of leaf nodes. there is nothing magical
about a tree. you can build one in basic or fortran. painf
use a list. or create new class which is a list
On Jun 16, 2012 8:52 AM, "Onur Uncu" wrote:
> Hello R Community,
>
> I have the following design question. I have a data set that looks
> like this (shortened for the sake of example).
>
> Gender Age
> M 70
> F 65
> M
is there a statement of work for the summer of code work.
On May 29, 2012 12:19 PM, "Joshua Ulrich" wrote:
> On Tue, May 29, 2012 at 2:11 PM, Noah Silverman
> wrote:
> > Hello,
> >
> > I noticed something odd when working with data frames and xts objects.
> >
> > If I read in a CSV file, R creat
Did you edit the description file and the namespace file and the Rd files?
Although my tutorial is for windows if you follow steps 8 thru 10 on mac it
should work
http://stevemosher.wordpress.com/step-8-the-sample-package/
On Thu, May 17, 2012 at 7:44 PM, Noah Silverman wrote:
> Hello,
>
> I
read your file with readLines(). copy the first few lines for me to read
here
test <- readLines(yur filename)
test[1:5]
post the result. we can figure it out from there
On Apr 13, 2012 11:46 AM, "AMFTom" wrote:
> Dear Thierry,
>
> Thanks for your help. Now though, I try to import data from a tx
one way to solve your problem is to fetch the directory using rcurl. then
mapply using the dirlist as a parameter passed to download file
On Apr 13, 2012 9:24 AM, "MacQueen, Don" wrote:
> If you take a thorough look at the help page for download.file, and follow
> its advice, you may find a solut
Welcome to R and the list.
Others may suggest books ( Nutshell was my first ) but first there are
some things that will help you
both in programming and getting help on the list.
You should post executable code in your question. So, build a toy example
of the data.frame you have
and show what
esponse reading failed
>
> Does not seem to work... Thoughts?
>
> --j
>
> On Mon, Apr 9, 2012 at 1:32 PM, steven mosher
> wrote:
> > A couple of ways.
> >
> > using Rcurl you can use the curlOption of dirlistonly.
> >
> > otherwise you can read
cr.usgs.gov/MOTA/MCD15A3.005/",verbose=TRUE,ftp.use.epsv=TRUE,
> dirlistonly = TRUE)
> Error in function (type, msg, asError = TRUE) :
> FTP response reading failed
>
> Does not seem to work... Thoughts?
>
> --j
>
> On Mon, Apr 9, 2012 at 1:32 PM, steven mosher
&g
A couple of ways.
using Rcurl you can use the curlOption of dirlistonly.
otherwise you can read the page and parse. I've got some code around here
to do that.
Steve
On Mon, Apr 9, 2012 at 11:27 AM, Jonathan Greenberg wrote:
> R-helpers:
>
> I'd like to be able to store all the file informa
As the other poster noted, you can just skip lines.
Big matrix should work just fine, except I am not sure how the dates will
be handled
Here is some sample code from my stuff
txtName is the file name of the file you are reading
Directory is the path where you want to write the file.backed ma
see the package animate
On Mar 24, 2012 7:37 AM, "Sarah Goslee" wrote:
> The easiest approach is to save your plot as a bitmap every x-th
> iteration, and then use other tools to animate them. I use ImageMagick for
> this, but I'm sure there are other options.
>
> Sarah
>
> On Mar 23, 2012, at 11
1. How much RAM do you have (looks like 2GB ) . If you have more than 2GB
then you can allocate
more memory with memory.size()
2. If you have 2GB or less then you have a couple options
a) make sure your session is clean of unnecessary objects.
b) Dont read in all the data if you dont
I have a large file backed big. matrix, with millions of rows and 20
columns.
The columns contain data that I simply need to tabulate. There are a few
dozen unique
values. and I just want a frequency count
Test code with a small "big" matrix.
library(bigmemory)
library(bigtabulate)
test <- bi
u set 'delete' to be the 'finalizer' of the
> object; in this way you avoid ff to save it in some tmp dir and occupy disk
> space forever. Then, you can access your object in the next R session:
>
> > ffload("mydir/myfile")# also without extension
>
Did you have to use a particular filename? or extension.
I created a similar file but then could not read it back in
Steve
On Mon, Feb 13, 2012 at 6:45 AM, Djordje Bajic wrote:
> I've been investigating and I partially respond myself. I tried the
> packages 'bigmemory' and 'ff' and for me the
Here ben
I have a tutorial on how to do it
http://stevemosher.wordpress.com/step-8-the-sample-package/
On Sun, Dec 18, 2011 at 11:49 PM, Petr PIKAL wrote:
> Hi
>
> If I remember correctly I do
>
> start clear R -vanilla session
> copy my functions to it.
> run package.skeleton("some.name")
check the help archives.
hclust with method=ward might be what you are looking for
On Wed, Oct 19, 2011 at 2:43 PM, Jörg Reuter wrote:
> I am very new to R, so sorry that I ask stupid things.
> I want compare a Matrix row by row and at the end I want to a Matrix with
> the Levenshtein-Dista
check the version of libcurl you have installed. If you have an older
version some of the
options may not be present.
On Sun, Oct 9, 2011 at 10:39 AM, Steven Oliver wrote:
> Hey Guys,
>
> I just started fooling around with the twitteR package in order to get a
> record of all tweets from a s
You can probably use the package jpg , It will be a pain. You will
have to read it in as a jpg
then isolate the numbers ( by row and column ) then figure out some
way ( probably not that hard)
to identify the numbers
from the bit pattern. I tried something similar with the png
package. it wa
worked beautifully.
Thanks.
On Mon, Sep 12, 2011 at 9:45 AM, Gabor Grothendieck
wrote:
> On Mon, Sep 12, 2011 at 11:57 AM, steven mosher
> wrote:
>> Gabor.. thanks.
>>
>> zr <- zooreg(rnorm(24), as.chron("2011-01-01"), frequency = 24)
>>
>> a c
,200
The end goal is to create a data structure for around 200 series aligned by time
On Mon, Sep 12, 2011 at 3:48 AM, Gabor Grothendieck
wrote:
> On Mon, Sep 12, 2011 at 1:58 AM, steven mosher wrote:
>> I have date data as a numeric and hourly data in 0 to 2300 hours in a
>>
I have date data as a numeric and hourly data in 0 to 2300 hours in a dataframe.
d <- rep(20110101,24)
h <- seq(from = 0, to = 2300, by = 100)
df <- data.frame(LST_DATE = d, LST_TIME = h, data = rnorm(24, 0, 1))
S <- chron(dates. = as.character(df$LST_DATE), times. =
paste(as
Thanks Gabor!
On Wed, Jul 27, 2011 at 3:08 AM, Gabor Grothendieck wrote:
> On Wed, Jul 27, 2011 at 4:06 AM, steven mosher
> wrote:
> > there are really two related problems here
> >
> > I have a 2D matrix
> >
> >
> > A <- matrix(1:100,nrow=20,ncol
ad one guy using the package who has hit the memory limits.. I have
one more thing to try
Thanks!
Steve
On Wed, Jul 27, 2011 at 1:42 AM, Gavin Simpson wrote:
> On Wed, 2011-07-27 at 01:06 -0700, steven mosher wrote:
> > there are really two related problems here
> >
> > I
there are really two related problems here
I have a 2D matrix
A <- matrix(1:100,nrow=20,ncol =5)
S <- matrix(1:10,nrow=2,ncol =5)
#I want to subtract S from A. so that S would be subtracted from the
first 2 rows of
#A, then the next two rows and so on.
#I have a the same problem with a 3D
Thanks, I just upgraded to 1.7.1
Also thanks for adding the t() function.
On Mon, Jul 18, 2011 at 12:38 PM, Gabor Grothendieck <
ggrothendi...@gmail.com> wrote:
> On Mon, Jul 18, 2011 at 2:57 PM, peter dalgaard wrote:
> >
> > On Jul 18, 2011, at 20:19 , Gabor Grothendieck wrote:
> >
> >> On
Same here.
Just made my first package and regret not having learned how to do it from
the very beginning.
Steve
On Sun, Jul 10, 2011 at 3:27 AM, Michael Dewey wrote:
> At 12:30 09/07/2011, Simon Chamaillé-Jammes wrote:
>
>> Dear all,
>>
>> sorry if this is a bit on the sidetrack for R-help.
>>
code/documentation mismatches ... WARNING
Data sets with usage in documentation object 'FILE.PARAMETERS' but not in
code:"
changing \usage cleared the warning
\usage{FILE.PARAMETERS}
clears check! crantastic, no warnings, no errors!
On Wed, Jun 22, 2011 at 8:29 AM, steven mos
Thanks Duncan, I'll join Dev and ask the questions over there.
Steve
On Wed, Jun 22, 2011 at 7:19 AM, Duncan Murdoch wrote:
> On 11-06-21 11:58 PM, steven mosher wrote:
>
>> Thanks to all your help I've just finished my first package and I have a
>> couple of quest
Thanks to all your help I've just finished my first package and I have a
couple of questions
I want to submit to CRAN but I have 1 warning
" checking for code/documentation mismatches ... WARNING
Data sets with usage in documentation object 'FILE.PARAMETERS' but not in
code:
FILE.PARAMETE
at contained
all the source
Files and that all the files in that directory ending in .R would be used.
Thanks
On Wed, Jun 8, 2011 at 11:44 PM, Prof Brian Ripley wrote:
> On Wed, 8 Jun 2011, steven mosher wrote:
>
> I'm using package.skeleton() windows 7, 64 bit.
>>
here i wrote a step by step tutorial.
http://stevemosher.wordpress.com/2011/06/09/making-simple-packages-in-r-on-windows/
On Wed, Jun 8, 2011 at 1:17 PM, Xia.Li wrote:
> Hello R users,
>
> I have difficulties when trying to make R packages. I tried to read many
> tutorials but still could not
I'm using package.skeleton() windows 7, 64 bit.
When I try to specify the code_files
package_skeleton(code_files = " some directory")
I get a warning that that the connection cannot be opened and
I get a Permissions denied error.
I'm running R as admin and I've given everybody full permis
I hope you're successful because I'm having issues as well building a simple
package on
windows. maybe when you're finished you can share back a step by step
guide.
On Thu, Jun 2, 2011 at 12:21 PM, Nipesh Bajaj wrote:
> I have run R CMD check trial1 and saw an error. This says that:
>
> * chec
Thanks Thomas.
On Sat, May 28, 2011 at 11:29 AM, Thomas Levine wrote:
> You can do pretty well without ggplot actually.
>
> boxplot(Time~paste(Incidents,Months),data=DF,border=c('grey20','red'))
>
> On Sat, May 28, 2011 at 2:55 AM, steven mosher
> wrote
= Time, fill = Months)) +
> geom_ribbon(aes(ymax = ..density.., ymin = -..density..),
>alpha = .2, stat = "density") +
> facet_grid( ~ Incidents) +
> coord_flip()
>
> ## Option C altered
> ggplot(DF, aes(x = Time, fill = Months)) +
> geom_ribbon(aes(ymax = ..density.., y
Hi,
I'm really struggling with barplot
I have a data.frame with 3 columns. The first column represents an
"incident" type
The second column represents a "month"
The third column represents a "time"
Code for a sample data.frame
incidents <- rep(c('a','b','d','e'), each =25)
months<- rep(c(1
2011 at 12:17 PM, Henrique Dallazuanna wrote:
> Try this:
>
> tryCatch(log(rnorm(10)), warning = function(m)deparse(m$call[[2]]))
>
> Where log(rnorm(10)) is your expr to evaluate.
>
> On Fri, Mar 18, 2011 at 4:04 PM, steven mosher
> wrote:
> > I've read t
I've read the help and the archives on tryCatch but I'm still stuggling
trying to understand how it
works exactly and how I can use it to get the result I need.
I have a data.frame of urls which point to 11 .zip files. Basically I use
RCurl to get the list of
files from a ftp and then reduce that
eric("as.data.frame")) {
setGeneric("as.data.frame", function(dirlist )
standardGeneric("as.data.frame"))
}
setMethod("as.data.frame",
signature(dirlist = "ftpdir" ),
function (dirlist )
{
return( dirlist@dirframe)
}
)
On Thu, J
On Thu, Jan 13, 2011 at 6:46 AM, Martin Morgan wrote:
> On 01/12/2011 10:54 PM, steven mosher wrote:
> > I have J Chambers wonderful text ( Software for data Analysis) and I've
> been
> > trying
> > my hand at some very routine S4 OOP development.
> >
> >
I have J Chambers wonderful text ( Software for data Analysis) and I've been
trying
my hand at some very routine S4 OOP development.
One of the things I was trying to do was to create some very basic S4
classes. The first
was simply a class that had a data.frame as part of its representation.
set
Here John,
from the manual
URLs
A note on file:// URLs. The most general form (from RFC1738) is
file://host/path/to/file, but R only accepts the form with an empty host
field referring to the local machine. This is then file:///path/to/file,
where path/to/file is relative to /. So although the
https
your second link is an https
that's not supported as I recall.
?url
On Thu, Jan 6, 2011 at 11:53 AM, John Kane wrote:
> # Can anyone suggest why this works
>
> datafilename <- "
> http://personality-project.org/r/datasets/maps.mixx.epi.bfi.data";
> person.data <- read.table(datafilen
Hmm,
Rcurl may be able to help you. Not sure I have not played with the "query"
abilities.
On Tue, Jan 4, 2011 at 10:54 AM, Erik Gregory wrote:
> R-Help,
>
> I'm trying to obtain some data from a webpage which masks the URL from the
> user,
> so an explicit URL will not work. For example, when
Thanks,
I was trying apply(TestZoo,2,lm,TestZoo~time(TestZoo))
which was throwing a formula error.
On Tue, Dec 21, 2010 at 12:21 PM, Gabor Grothendieck <
ggrothendi...@gmail.com> wrote:
> On Tue, Dec 21, 2010 at 3:02 PM, steven mosher
> wrote:
> > I have a matrix of zoo s
I have a matrix of zoo series. each series is in a column.
x <- as.yearmon(2000 + seq(0, 23)/12)
# 24 months of data, lets make 20 sets of random data
testData <- matrix(rnorm(480),ncol=20)
# make a zoo object and columns will hold the 20 series
TestZoo <- zoo(testData,order.by=x)
# now run lm f
Hi,
Next time give folks code to produce a toy sample of your problem
DF <-data.frame(ID=rep(1:5,each=3),Data=rnorm(15),Stuff=seq(1:15))
DF
ID Data Stuff
1 1 2.0628225 1
2 1 0.6599165 2
3 1 0.5672595 3
4 2 -0.5308823 4
5 2 -0.5358471 5
6 2 -0.1414992
org Ruß:
> v = download.file(url,destf,method="wget")
> if(v!=0) {
> #download.file failed
> }
> #no error message though
>
> 2)
>
> Henrique Dallazuanna and Steven Mosher both suggested using RCurl,
> here is an example code from Henrique for checking if a file exists o
Month=dir[ ,1],Time=dir[ ,2],stringsAsFactors=FALSE)
closeAllConnections()
return(out)
}
On Tue, Nov 30, 2010 at 9:56 AM, Baoqiang Cao wrote:
> Thanks Steven!
> It is excellent code indeed!
>
> On Tue, Nov 30, 2010 at 11:26 AM, steven mosher
> wrote:
> > I w
length(contents)]
On Tue, Nov 30, 2010 at 9:56 AM, Baoqiang Cao wrote:
> Thanks Steven!
> It is excellent code indeed!
>
> On Tue, Nov 30, 2010 at 11:26 AM, steven mosher
> wrote:
> > I would use RCurl.
> >
> > if you have, for example, the url of an ftp s
using RCurl
getFtpList <- function(ftp){
# the structure returned is dependent on the ftp site as there are
# various formats for directory listings dependent upon the server
# and the OS. you will need to play with this.
# have a look at the ftp with your browser first and adjus
I would use RCurl.
if you have, for example, the url of an ftp site you can merely do a
getURL() and the contents will be returned. That call will return data that
can be coerced into a data.frame that will look like a directory structure
listing the file names.
If you need code just ask, but t
R 2.12 is not functioning for me On the MAC what the most painless way of
reverting
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://ww
just merge the data.frames back together.
use merge or cbind()
cbind will be easier
DF1 <- data.frame(x,y,z)
DF2 <-data.frame(DF1$x) # copy a column
then you added columns to DF2
just put them back together
DF3 <-cbind(DF2,DF1$y,DF$z)
if you spend more time with R you will be able to do thing
Line should be:
first=second=third=fourth=fifth=sixth=seventh=eighth=ninth=tenth<-vector(length=nrow(
sent))
sorry cut and past error
On Tue, Nov 2, 2010 at 3:32 PM, steven mosher wrote:
> That's easy you are confusing the dummy code I sent.
>
> Do this:
>
> lit<
gt; <-data.frame(Sentence=sent,first,second,third,fourth,fifth,sixth,seventh,eighth,ninth,tenth,stringsAsFactors=FALSE)
>
>
>
> »Error in data.frame(Sentence = sent, first, second, third, fourth, fifth,
> :
>
> arguments imply differing number of rows: 22928, 10«
>
>
Thanks david.
Matevz, maybe I can help explain by doing a very simple and brute force
approach
as opposed to the way david did it. But you should learn his methods.
I will just do a subset of your problem and if you understand how it works
then you should
be able to get something done and the
I'm doing some test processing of a cvs file that appears to use a different
locale
from my machine.
I get the following warning:
input string 1 is invalid in this locale
My locale is US. Is this simply a matter of changing my locale to 'all;
locales?
I don't know what locale the string is in,
Ok I downloaded it and showed you how to get your data out. How to read it
into a raster brick,
how to plot the data, how to get the mean rainfall of every day.lots more
you can do.
there is a bad bit of data in the last time step.
check my blog.
In the future what you should do is write code t
Thanks for the pointer,
After looking at the many folders of R code I have I decided it was time to
start working in an IDE and also getting my stuff under version control (
for my own sanity)
I'll have a look at Geany.. for version control.. not so sure.
On Wed, Oct 27, 2010 at 12:14 PM, Liviu
if your data for the rest of the file looks like this then read.fwf will
work.
depending which vars you want to pull)
widths= c(18,32,41)
E-CBIL-28-raw-cel-1435145228.cel1
would pull 3 vars, E-CBIL-28-raw-cel-; 1435145228.cel;1
widths <-c(32,41)
E-CBIL-28-raw-cel-1435145228.cel;1
you
I've read a number of examples on doing a multiple bar plot, but cant seem
to grasp
how they work or how to get my data into the proper form.
I have two variable holding the same factor
The variables were created using a cut command, The following simulates that
A <- 1:100
B <- 1:100
A[30:60]
I have a program that creates a Png file using Rgooglemap with an extent
(lonmin,lonmax,latmin,latmax)
I also have a contour plot of the same location, same extent, same sized
(height/width) png file.
I'm looking for a way to make the contour semi transparent and overlay it on
the google map ( hyb
Hmm,
RCurl might have something on this.
otherwise pull you can figure out their scheme and just construct the url
from scratch.
when you finish filling in the form, look at the url they construct. do it a
few times
and you can just emulate that. I've done that in the past without problems.
depe
tual storage.
>
> Cheers,
>
> Josh
>
> On Sat, Oct 9, 2010 at 1:33 PM, steven mosher
> wrote:
> > Given a csv file from this location
> >
> > Airports<-"http://www.ourairports.com/data/airports.csv";
> >
> > download.file(Airports,base
Given a csv file from this location
Airports<-"http://www.ourairports.com/data/airports.csv";
download.file(Airports,basename(Airports))
airports <-read.csv("airports.csv",encoding="UTF-8")
> airports[1,]
id ident type name latitude_deg longitude_deg
elevation_ft continen
Thanks,
haven't used valgrind in years, this should be fun.
Steve
On Wed, Oct 6, 2010 at 1:55 PM, Ben Bolker wrote:
> steven mosher gmail.com> writes:
>
> >
> > I know its no consolation, but I have a similar issue with R on a MAC,
> also
> > ploting
>
I know its no consolation, but I have a similar issue with R on a MAC, also
ploting
out large numbers of raster layers. sometimes the problem lingers even
after I clear the workspace, do gc() etc. Almost as if R wont ask for
processor resources.
weird.
On Wed, Oct 6, 2010 at 12:06 PM, Bastien F
in the package R.utils
getAbsolutePath()
or you can do a file.list(.. full.names=TRUE,
recursive=TRUE,pattern="(.R)")
the rest will require grep and pulling the file name and directory path
apart
If its not evident just ask and I'll write something for you.
basically you want a call t
The package R.utils has a function to get absolutepath
On Sun, Sep 26, 2010 at 1:00 AM, Sebastian Gibb wrote:
> Hello,
>
> I get a value which stores a relative file name. (I get it from another
> function, which I don't want to change.)
> e.g.
> > fileName <- "../data/2010-08.csv";
>
> Is it pos
had taken crazy pills.
i did note, however, some odd behavior with tryCatch, where statements
after the "finally={} were executed. Not sure if that deserves a bug report.
On Tue, Sep 21, 2010 at 2:33 AM, Barry Rowlingson <
b.rowling...@lancaster.ac.uk> wrote:
> On Tue, Sep 21, 2
I'm accessing around 95 tar files on an FTP server ranging in size between
10 and 40MB a piece.
while certainly can click on them and download them outside of R, I'd like
to have my script do it.
Retrieving the ftp directory with RCurl works fine (about 90% of the time)
but downloading the files
> v<-c(1,2,3,4,5,6,7,8,97,6,5,4,NA,NA)
> b<-zoo(v)
> b
1 2 3 4 5 6 7 8 9 10 11 12 13 14
1 2 3 4 5 6 7 8 97 6 5 4 NA NA
> b[is.na(b)]<-0
> b
1 2 3 4 5 6 7 8 9 10 11 12 13 14
1 2 3 4 5 6 7 8 97 6 5 4 0 0
> is.zoo(b)
[1] TRUE
On Mon, Sep 20, 2010 at 2:37 AM
you are welcome. Henrik's package is an great piece of work. It is worth
the time to read through the whole thing and see how you can improve your
programs by using other features as well.
On Thu, Sep 16, 2010 at 2:16 AM, Wonsang You wrote:
> Dear Henrik and Steven,
>
> Thank you for your kind
pany Limited
> Tel: +662-305-9179
> Email: supha...@phatrasecurities.com
>
> *From:* steven mosher [mailto:mosherste...@gmail.com]
> *Sent:* Thursday, September 16, 2010 2:29 AM
> *To:* Suphajak Ngamlak
> *Subject:* Re: [R] Get File Names in Folder, Read Files, Update, and Write
>
Wongsang,
Just to be clear R.utils is different than "utils"
As Henrik notes gunzip has been in R.utils ( see http://cran.r-project.org/)
for some time. It works
like a champ. R.utils is a great package.
On Wed, Sep 15, 2010 at 9:30 AM, Wonsang You wrote:
> Dear Henrik,
>
> Thank you so mu
not sure how you wanted sampling of x
R<-142
color<-rep(0,142)
for(i in 1:R){
y<-sample(x,142,replace=FALSE)
onebit<- as.numeric(3471 %in% y)
twobit<-as.numeric(6720 %in% y)*2
fourbit<-as.numeric(6263 %in% y)*4
colorbit<-onebit+twobit+fourbit+1
color[i]<-colorbit
}
On Tue, Sep 14, 2010
A NA NA NA NANA
> 8 49 14 19 24 29 34 39 4449
> 9NA NA NA NA NA NA NA NA NANA
> 105 10 15 20 25 30 35 40 4550
> >
>
>
>
> -----Original Message-
> From: r-help-boun...@r-project.o
34 39 4449
> 9NA NA NA NA NA NA NA NA NANA
> 105 10 15 20 25 30 35 40 4550
> >
>
>
>
> -----Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of steven mo
j<-matrix(nrow=10,ncol=10)
k<-matrix(seq(1:50), ncol=10)
row.names(k) <- seq(2,10,by=2)
j
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] NA NA NA NA NA NA NA NA NANA
[2,] NA NA NA NA NA NA NA NA NANA
[3,] NA NA NA NA NA
A quick question
x <- as.yearmon(2000 + seq(0, 23)/12)
x
[1] "Jan 2000" "Feb 2000" "Mar 2000" "Apr 2000" "May 2000" "Jun 2000" "Jul
2000" "Aug 2000" "Sep 2000" "Oct 2000" "Nov 2000" "Dec 2000" "Jan 2001"
[14] "Feb 2001" "Mar 2001" "Apr 2001" "May 2001" "Jun 2001" "Jul 2001" "Aug
2001" "Sep 2001
()
>>>>
>>> R version 2.11.1 (2010-05-31)
>>> x86_64-pc-mingw32
>>>
>>> locale:
>>> [1] LC_COLLATE=English_United States.1252
>>> [2] LC_CTYPE=English_United States.1252
>>> [3] LC_MONETARY=English_United States.1252
&g
;
> Josh
>
> On Sun, Aug 15, 2010 at 12:06 AM, steven mosher
> wrote:
> > Did you exit R and then return?
> > fname<-"test.Rdata"
> > full<-file.path("Example",fname,fsep=.Platform$file.sep)
> > full
> > [1] "Example/t
; [5] LC_TIME=English_United States.1252
>
> If correcting the quoting does not help you, perhaps you can report
> the results of sessionInfo()
>
> Cheers,
>
> Josh
>
> On Sat, Aug 14, 2010 at 5:14 PM, steven mosher
> wrote:
> > In the particular application I ha
rt
> the results of sessionInfo()
>
> Cheers,
>
> Josh
>
> On Sat, Aug 14, 2010 at 5:14 PM, steven mosher
> wrote:
> > In the particular application I have I save "test.Rdata" to a sub
> directory
> > dir<-"Example"
> > dir.creat
In the particular application I have I save "test.Rdata" to a sub directory
dir<-"Example"
dir.create(dir)
test<-data.frame(a=c(1,2,3),b=c(3,4,5)
full<-file.path(dir,"test.Rdata,fsep=.Platform$file.sep)
save(test,file=full)
load(full)
returns NULL
it works fine when the object is saved to the wor
Thx, I see my problem. more sleep required
On Sat, Aug 14, 2010 at 9:25 AM, Romain Francois wrote:
>
> Le 14/08/10 18:22, steven mosher a écrit :
>
>
>> Stupid question, but its been a long night.
>>
>> If I have a long vector how can I turn it into a list of th
Stupid question, but its been a long night.
If I have a long vector how can I turn it into a list of the same length
x<-rep(seq(1,100,by=1),each=10)
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch
, 2010 at 11:21 AM, Gabor Grothendieck <
ggrothendi...@gmail.com> wrote:
> On Wed, Aug 11, 2010 at 12:22 PM, steven mosher
> wrote:
> > Given a long zoo matrix, the goal is to "sweep" out a statistic from the
> > entire length of the
> > sequences.
> >
Given a long zoo matrix, the goal is to "sweep" out a statistic from the
entire length of the
sequences.
longzoomatrix<-zoo(matrix(rnorm(720),ncol=6),as.yearmon(outer(1900,seq(0,length=120)/12,"+")))
cnames<-c(12345,23456,34567,45678,56789,67890)
colnames(longzoomatrix)<-cnames
longzoomatrix[
rc<-list(c(
123,321,234,543,654,768,986,987,246,284),c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"))
# the matrix has rownames that are used as identifiers and columns
# of time. 1 years worth of data. Thats the native format
test<-matrix(seq(1,120, by=1), nrow=10,dim
That works.
Thanks
On Mon, Aug 9, 2010 at 7:55 AM, Henrique Dallazuanna wrote:
> Try this:
>
> aggregate(example[c('x', 'y')], example[c('id', 'Year')], 'mean')
>
>
> On Mon, Aug 9, 2010 at 11:46 AM, steven mosher wrote
Assuming a data frame or matrix with two columns representing variable that
you want to aggregate over.
you want to calculate column means, by year, for each Id
example<-data.frame(id=c(rep(12345,5),rep(54321,6),rep(45678,7)),Year=rep(seq(1900,1902,by=1),6),
x=seq(1,18,by=1),y=seq(18,1,by=-1))
1 - 100 of 157 matches
Mail list logo
