Re: [R] Error massage in attaching package 'rgl'

2008-02-17 Thread stat stat
I am using 2.6.0 version in usual Windows-XP platform Duncan Murdoch <[EMAIL PROTECTED]> wrote: On 17/02/2008 8:15 AM, stat stat wrote: > Hi, > > I am getting following error message while attaching 'rgl' package : > >> library(rgl) > Error in get(Info[i,

[R] Error massage in attaching package 'rgl'

2008-02-17 Thread stat stat
Hi, I am getting following error message while attaching 'rgl' package : > library(rgl) Error in get(Info[i, 1], envir = env) : internal error in R_decompress1 Can anyone tell me what should I do here? Regards, - 5, 50, 500, 5000 - Store N number of mai

Re: [R] Error in if loop

2007-10-21 Thread stat stat
EMAIL PROTECTED]> wrote: On 21/10/2007, stat stat wrote: > I have created a if loop as follows: > > name = "e" > if (name == "v") > { >u = 0 > } > else u = 1 > > however i am getting error : Error: unexpected 'else' in "else

[R] Error in if loop

2007-10-21 Thread stat stat
I have created a if loop as follows: name = "e" if (name == "v") { u = 0 } else u = 1 however i am getting error : Error: unexpected 'else' in "else" definitely I can write in : ifelse() form, however I want to write in this way. Can anyone tell me where is my error? thanks in advance

[R] Splines

2007-10-05 Thread stat stat
I want to fit a cubic spline of x on y. where : x [1] 467 468 460 460 450 432 419 420 423 423 y [1] 1 2 3 4 5 6 7 8 9 10 using the syntax spline(y, x) I got following output : $x [1] 1.00 1.310345 1.620690 1.931034 2.241379 2.551724 2.862069 [8]

[R] Sample selection problem

2007-10-03 Thread stat stat
I want to get a sample of some arbitrary size from a population having only two values 0 and 1 with replacement, but with different probability for selection. For example 0 will be selected with probability 0.4 and 1 with 0.6. I could use sample function i.e. sample(c(0,1), 30, T) to get this, h

[R] Expressing number in percentage

2007-09-27 Thread stat stat
I am wondering if there is any procedure to write a particular value in Percentage format, still maintaining it's numeric character. for example I want to write '.33' as '33%' regards, thanks in advance - [[alternative HTML version

[R] Legend

2007-09-26 Thread stat stat
I have following syntax for putting a legend : legend("bottom", fill=c("red","blue"), legend=expression(p==0.30, p==0.50), bty="n") However what I want is that : the value "0.30" should be a value of a variable instead of a constant, so that I can put the name of this variable and in legend it