somewhere and you can help :)
Best Livia
Fra: Livia Maria Vestergaard
Sendt: 19. maj 2015 10:16
Til: r-help@r-project.org
Emne: [R] Output interpretation: standard error of lm dummy variable
Hi guys
I have a statistical question to an analyse I ran in
:)
Best Livia __
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Hi Duncan
Thank you so much - it worked :)
Best
Livia
Fra: Duncan Mackay [dulca...@bigpond.com]
Sendt: 6. maj 2015 14:26
Til: R; Livia Maria Vestergaard
Emne: RE: [R] lm model exported from R to excel
Hi Livia
There are several html packages that
Hi all
I all. I am wondering whether anybody know how to export an output of an lm
model from R to excel in order to have excel recognize the table that comes and
divide the numbers in the table into columns and rows?
I really hope it is possible? :)
Best Livia
on the
price. I know how to tell R about the date by as.Date() , but not with the
time, how can I do that?
Or do you guys maybe a third idea about what should make a regression about to
improve the model?
Cheers
Livia :)
Fra: Boris Steipe [boris.s
time but how ?
Hope that you can help me :)
Livia
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Hello,
I am working on the model of seemingly unrelated regression. I came across
with the error message:
Log determinant of residual covariance: NA
Warning messages:
NAs generated in: log(x)
I have three linear models which contain 21 explanatory variables and there
are about 300 data point
Hello,
I am working with S-plus TimeSeries Object. I wonder how can I change the
column names of the variable instead of using the one default?
i.e to change "DEV.MSCI" to other name
PositionsDEV.MSCI
04/30/1980 00:00:00.000 -0.0150328542
05/31/1980 00:00:00.000 0.0
Hello,
I would like to optimize the function "fqp" as following:
a= c(0.2,0.3,0.4)
vcov=matrix(c(1,2,3,4,5,6,7,8,9),3,3)
fqp <- function(b) {t(b)%*%a-0.5*((t(b)%*%vcov)%*%b)}
I want the linear constraint to be something like abs(b1)+ abs(b2)+abs(b3)
= 1.5.
I found it diffcult to use "constr
Hello everyone,
I would like to optimize the function "fqp" as following:
a=c(0.2,0.3,0.4)
vcov=matrix(c(1,2,3,3,2,2,2,3,1),3,3)
c=2
fqp <- function(b) {t(b)%*%a-0.5*c*((t(b)%*%vcov)%*%b)}
with constraints like ((t(b)%*%vcov)%*%b) <= 0.5
Is there a function of doing it? Many thanks.
--
View t
Hello everyone,
I would like to maximize the following function fqp with linear constraits
and the codes are as following:
a= c(0.2,0.3,0.4)
vcov=matrix(c(1,2,3,4,5,6,7,8,9),3,3)
fqp <- function(b) {t(b)%*%a-0.5*((t(b)%*%vcov)%*%b)}
constrOptim(c(b1,b2,b3), fqp,NULL,ui=?, ci=?, control=list(fnsc
Hello everyone,
I have got a question about a simple calculation. If I would like to
calculate 50/12 and return the result as 4 and the remainer 2. Is there a
function of doing this?
Many thanks.
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Hello everyone, I would like to construct a datafram with the following
command.
eval(parse(text=paste("df=data.frame(", cmd, ")", sep="")))
But it comes out " Error in parse(file, n, text, prompt, srcfile, encoding)
:
syntax error, unexpected $undefined, expecting ',' in
"df=data.fram
Hello everyone,
I get some data in the following format and I would like to combine them to
form a dataframe.
The data is like:
cbcname1 = 0.1,
cbcname2= 0.2,
cbcname3=0.3,...
name1, name2, name2 are just some random names. I would like to achieve sth
like:
(cbcname1=0.1, cbcname2=0.2, cbcnam
Hi, I guess it is because I spread the command in different rows. Thank you
very much for your help.
Petr Pikal wrote:
>
> Hi
>
> [EMAIL PROTECTED] napsal dne 11.12.2007 13:06:14:
>
>>
>> Hello everyone,
>>
>> I would like to use the "if" statements and I was thinking sth like
>>
>> If ()
Hello everyone,
I would like to use the "if" statements and I was thinking sth like
If () {} else{ if() {} else{} }
Is this a possible solution and is there any syntax error?
Could anyone give me some advice? Many thanks.
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Hello,
I would like to perform a linear regression and the data is a list.e.g
lm(list$abc~., data=list) or lm(abc~., data=list), which would give the same
result.
The problem is I would like to call the response variable in a more general
form. What I try to achieve is sth like lm(list$(paste("a
Hello,
I have got a vector, for example seq(1:10), and I have an array "name"
defined before which contain the vector name I would like to use. So
name[1]= "price". I would like to name the vector in the following codes:
paste("myname", name[1]) <- seq(1:10)
But it does not work. Could anyone g
Hello,
I define a dataframe named "Price" first and there are other dataframes as
well. Then I built an array named "code" containing all the dataframe name.
So If I call code[1], it is "Price".
Basicly, I would like to call the datafram with reference to the
array"code".e,g, If I want to call
Hello everyone,
I would like to use the "cbind" function to construct a dataset, combining
some variable I defined before.
The codes are something like
var1 <- ...
var2 <- ...
var2 <- ...
...
data <- cbind(var1,var2,var3...)
The problem is I would like some flexibity in the data, i.e. the numbe
Hi everyone, I would like to write VBA macros for accessing R and it is my
first attempt. I really could use some help here.
I am trying to use the following code to read data from Access. The R code
between "" is correct as I successfully run it from R, but when I call it
using VBA, it comes out
Hello everyone,
I would like to a linear regression with the following code.
lm(a[,"fquamsci"]~., data=a)
a is a list with class "mts" "ts" , and "fquamsci" is the name of the
response variable in a. I would like to do a linear regression of "fquamsci"
to the rest of the variables. But it tur
Hello,
I would like to use the cbind() function to construct a matrix used in the
middle of a function as following
for (i in 1:1000) {
b[i] <- function(cbind(a[[1]][[i]],
a[[2]][[i]],a[[3]][[i]],...a[[67]][[i]]))
}
Is there an easy way of achieving this rather than "cbind" every column?
--
Hello, I would like to build a list through the following codes."know1" &
"know2" are some list obtained before. "know1" has the length of 50 (as for
i), "know2" has the lengh of 50 (as for i), know1[[i]] has the length of
1000, know2[[i]] has the length of 1132. I would like to get the list
"fina
Thank you very much for your reply and I did not make myself clear.
My model is like lm(y ~ x1+x2+x3,data), I would like to see E(y) and the
standard error.
Ben Bolker wrote:
>
>
>
> livia wrote:
>>
>> Hello,
>>
>> I am performing a multiple linear r
Hello,
I am performing a multiple linear regression, is there a way of get the mean
and standard error of the response variable?
Could anyone give me some advice? Many thanks.
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Sent from the R help
Hello,
I would like to fit a linear regression and when I use summary(), I got the
following result:
Call:
lm(formula = weight ~ group - 1)
Residuals:
Min 1Q Median 3Q Max
-1.0710 -0.4938 0.0685 0.2462 1.3690
Coefficients:
Estimate Std. Error t value Pr(>|t|)
Hello,
I am very interested in Portfolio Optimization functions in this package.
For the "cmlPortfolio", I thought it would be a set of the portfolio along
the "Capital Market Line", but it turns out that there is only one
portfolio. I was wondering which portfolio should this be?
Besides, is th
Hello,
I would like to do a portfolio optimization in R and I tried to use the
function in "fPortfolio", but it appears there does not exist such function.
Could anyone give me some advice?
Many thanks
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Hello,
I would like to solve a portfolio optimization problem in R. As far as I
searched, I found the example of "solve.QP" &"portfolio.optim". In my
understanding, both of them are based on given expected return, finding the
minimum variance. Is there a way of doing this in an opposite way?i.e
m
I have got a list named "filtered", I would like to construct alist named
"fdata" as following:
fdata <- cbind(matrix(unlist(filtered),ncol=28), myregime)
If I try names(filtered), it gives all the correct name for each vector, but
if I try names(fdata), it appears "filtered[[1]]"
Hi, I would like to plot a histogram with the following codes, and I would
like to make the tick intervals smaller. I tried to add "lab=c(1,1,12)", but
nothing changes.
par(mfrow=c(1,1),font=1, cex=0.8)
hist (data1, seq(-0.01,0.3,0.01),freq = FALSE,
main="Figure1.",xlab="return",lab=c(1,1,12))
l
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