Hi
Is there a way to remove blank characters from the end of strings in a
vector? Something like the =TRIM functions of the OpenOffice
spreadsheet. E.g.,
a <- c("hola", "Yes ", "hello ")# I'd like to get:
c("hola", "Yes", "hello")
Thanks
Juli
--
http://www.ceam.es/pausas
Hi
I'd like to write.table a dataframe, but with an specific order of
columns. Is there a direct way to do it? or I have to generate a new
dataframe as follows:
t <- data.frame(c=1:10, b=11:20, a=letters[1:10])
t2 <- data.frame(a=t$a, b=t$b, c=t$c)
write.table(t2, row.names=F)
Thanks for any com
Hi,
Is there a way in R to plot an envelope line from a cloud of points
(x, y data) ? That is, a smooth line that include all points, where
the points do not follow a strait linear pattern. Could somebody
redirect me to some package or function for this? Thanks in advance.
Juli
--
http://www.cea
drop1(glm(sf ~ tr, family="binomial", subset=(tr %in% c("1", "3"))),
test="Chisq") # significant, as expected
Is this the correct approach?
Many thanks
Juli
On Wed, Feb 27, 2008 at 12:13 PM, Prof Brian Ripley
<[EMAIL PROTECTED]> wrote:
> On Wed, 27 Feb
Dear all,
I have a question on glm, family binomial. I do not see significant
differences between the levels of a factor (treatment) if all data for
a level is 0; and replacing a 0 for a 1 (in fact reducing the
difference), then I detect the significant difference that I expected.
Is there a way to
the tr
variable in different columns (as a timevar) with their value (val).
sp code tr.A tr.B tr.C
aa1 31NANA
aa2 NA32NA
aa2 NA33NA**
aa3 NANA34
ba3 3536NA
ba4 NANA37
ca4 38 NA NA
d
Dear all,
I'm not very sure on the use of repeated measures in R, so some advice
would be very appreciate.
Here is a simple example similar to my real problem (R 2.6.0 for
windows): Lets supose I have annual tree production measured in 9
trees during 3 years; the 9 trees are located in 3 different
Hi,
I'm trying to use reshape but I cannot quite understand how it works.
Could somebody help me on this? Example, my data is something like:
mydat <- data.frame(tree= 1:10, serra=rep(1:2, c(5,5)), bt01= 101:110,
bt02= 201:210, bt03= 301:310, mm01= 9101:9110, mm02= 9201:9210, mm03=
9301:9310)
>
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