Maybe Friedman test
On Mon, Sep 6, 2010 at 4:47 PM, David Winsemius wrote:
> The usual least-squares methods are fairly robust to departures from
> normality. Furthermore, it is the residuals that are assumed to be normally
> distributed (not the marginal distributions that you are probably looki
Try this:
fill=c("gray"(0.1),"gray"(0.5),"gray"(1))
On Wed, Sep 1, 2010 at 4:59 PM, Jens Oldeland wrote:
> No...but it works!
>
> I do not know why I did not find it...
> Many thanks!
>
>
> Hi David, thanks to you as well.
>
>
> Greg Snow schrieb:
> > Did you try gray.colors(3)?
> >
>
>
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