[R] Change the limits of a plot "a posteriori"

Hi all How can I change the limits (xlim or ylim) in a plot that has been already created? For example, consider this naive example curve(dbeta(x,2,4)) curve(dbeta(x,8,13),add=T,col=2) When adding the second curve, it goes off the original limits computed by R for the first graph, which are rou

[R] All possible paths between two nodes in a flowgraph using igraphs?

wo or more. Thanks in advance jcano http://n4.nabble.com/file/n2125347/flowgraph_subsume.jpg -- View this message in context: http://r.789695.n4.nabble.com/All-possible-paths-between-two-nodes-in-a-flowgraph-using-igraphs-tp2125347p2125347.html Sent from the R help mailing list archive at Nabbl

[R] All possible paths between two nodes in a flowgraph using igraphs?

45631, 45634; and no loops of order two or more. Thanks in advance jcano -- View this message in context: http://r.789695.n4.nabble.com/All-possible-paths-between-two-nodes-in-a-flowgraph-using-igraphs-tp2125321p2125321.html Sent from the R help mailing list archive at Nabbl

Re: [R] How to create a legend that automatically reads the values from two vectors?

Hi JIm Not exactly what I want, as I can't draw the lines corresponding to the different curves in the plot as I can do in legend, but may be still of help. Thkx, Javier Jim Lemon-2 wrote: > > On 10/21/2009 01:30 AM, jcano wrote: >> betav<-c(0.78,0.94,0.88,0.41,0

[R] How to create a legend that automatically reads the values from two vectors?

Hi all!!! How can I create a legend to my plot that automatically reads the values from two vectors? betav<-c(0.78,0.94,0.88,0.41,0.59,4.68) etav<-c(235.6,59.5,31.2,8.7,3.2,1174) I want my legend to show 6 lines beta(in greeks)=0.78,eta(in greeks)=235.6 beta(in greeks)=0.94,eta(in greeks)=6.59 .

Re: [R] How to pass a character argument which contains expressions to arg.names in barplot?

Dear Uwe Sorry for not included the data, but even as that, it worked! Thank you very much for your unvaluable time and effort Cheers Javier Cano -- View this message in context: http://www.nabble.com/How-to-pass-a-character-argument-which-contains-expressions-to-names.arg-in-barplot--t

[R] How to pass a character argument which contains expressions to arg.names in barplot?

Hi all Can anybody help me with this? I am trying to include in an automatic way the argument in arg.names in a barplot. I generate the labels I want to appear below the bars with a for loop, and they contain subscripts, so I need to use expression anch<-0.05 esp<-4 for (i in 1:dim(Ntot)[1