Re: [R] Is this foreach behaviour correct?

ers to dates. That's true with the function in the base package, but the zoo package also has an as.Date() function, which defaults the origin to "1970-01-01". If James is using zoo his code would be okay. If he's not, he would have got an error, so I think he must have been. Du

Re: [R] Is this foreach behaviour correct?

o I think he must have been. > > Duncan Murdoch > >> >> Jim >> >> On Sun, Nov 6, 2016 at 12:10 PM, James Hirschorn >> wrote: >>> This seemed odd so I wanted to check: >>> >>> > x <- foreach(i=1:10100, .combine

[R] Reduce does not work with data.table?

Reduce is failing when applied to a list of elements of class data.table. Perhaps this is a bug? Example: library(data.table) dt1 <- data.table(x = 1:3, y = 4:6) dt2 <- data.table(x = 4:6, y = 1:3) dt3 <- data.table(x = 0:-2, y = 0:-2) # This works fine dt1 + dt2 + dt2 #x y # 1: 5 5 # 2:

[R] Is this a bug in quantmod::OpCl?

OpCl works on xts objects but not on quantmod.OHLC objects. Is this a bug? Example error: x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 9, 14) - 1 set.seed(1) x <- zoo(matrix(runif(20, 0, 1), nrow=5, ncol=4), x.Date) q <- as.quantmod.OHLC(x,c("Open","High","Low","Close")) # error OpCl(q) #> Erro

[R] Extracting from data.frame

Can someone please explain the following behavior? df1 and df2 are data.frames. Suppose I want a subset of the rows (observations) using extraction, say just the first row. What I want to know is why if df1 has just one column then df1[1,] returns a vector, whereas if df2 has 2 or more columns

Re: [R] extracting named vector from dataframe

tions such as sort(). -Original Message- From: David Winsemius [mailto:dwinsem...@comcast.net] Sent: Sunday, October 31, 2010 12:24 PM To: James Hirschorn Cc: R-help@r-project.org Subject: Re: [R] extracting named vector from dataframe On Oct 31, 2010, at 11:54 AM, James Hirschorn

[R] extracting named vector from dataframe

Suppose df is a dataframe with one named row of numeric observations. I want to coerce df into a named vector. as.vector does not work as I expected: as.vector(df) returns the original dataframe, while as.vector(df,mode="numeric") returns an unnamed vector of NAs. This works: > v <- as

Re: [R] Long model formulae

> > Here is a dodge I often use. This is a mock-up example. Very instructive (and helpful) ... > > ___ > > bar <- data.frame(matrix(rnorm(1001), nrow = 1)) > names(bar)[1] <- "y" ## say > head(bar[,1:5]) > > nbar <- names(bar) > form <- as.formula(paste(nbar[1], "~", paste(nbar[-1],

[R] Long model formulae

What is a good way to enter a very long model formula. For example: y ~ Input.2 + Input.3 + ... + Input.1000 (assuming the corresponding dataframe has many other columns). Is there a way to convert a character string to a formula? Are there command line expansions in R besides the simple '.'?

Re: [R] read columns of quoted numbers as factors

d columns differently, analogously to write.table. However, there does not even seem to be an option to make read.table behave analogously. - Original Message ---- From: peter dalgaard To: james hirschorn Cc: r-help@r-project.org Sent: Tue, October 5, 2010 7:25:52 AM Subject: Re: [R

[R] read columns of quoted numbers as factors

Suppose I have a data file (possibly with a huge number of columns), where the columns with factors are coded as "1", "2", "3", etc ... The default behavior of read.table is to convert these columns to integer vectors. Is there a way to get read.table to recognize that columns of quoted number