That did it!
Thanks so much as always.
I emailed the question to you because I think you are an R expert based
on all the suggestions, feedback and codes I have received from you in
the past.
Yes, I do look for answers in the open
forum but when it comes to a question for which the ans
x27;.
In the end return 'r1', not cbind.
Hope this helps,
Rui Barradas
Em 04-10-2012 23:38, genome1976 escreveu:
> Hi Rui,
>
> A while ago you helped me with calculaing all possible ratios from a dataset.
>
> This is the code I am using as suggested
ot;, "P1:P6",
"P2:P1", "P2:P3", "P2:P4", "P2:P5", "P2:P6", "P3:P1", "P3:P2",
"P3:P4", "P3:P5", "P3:P6", "P4:P1", "P4:P2", "P4:P3", "P4:P5",
&
6",
"P2:P1", "P2:P3", "P2:P4", "P2:P5", "P2:P6", "P3:P1", "P3:P2",
"P3:P4", "P3:P5", "P3:P6", "P4:P1", "P4:P2", "P4:P3", "P4:P5",
&qu
1", "P2:P3", "P2:P4", "P2:P5", "P2:P6", "P3:P1", "P3:P2",
"P3:P4", "P3:P5", "P3:P6", "P4:P1", "P4:P2", "P4:P3", "P4:P5",
"P4:P6", "P5:P1", &quo
ction(j) x[, j[2]]/x[, j[1]])
colnames(r1) <- apply(cmb, 2, function(j) paste(cn[j], collapse=char))
colnames(r2) <- apply(cmb, 2, function(j) paste(cn[rev(j)],
collapse=char))
cbind(r1, r2)[, order(c(colnames(r1), colnames(r2)))]
}
m1 <- matrix(1:24, ncol=6)
pairw
veu:
> Date: Fri, 11 May 2012 12:39:23 -0700 (PDT)
> From: genome1976<[hidden email]>
> To:[hidden email]
> Subject: [R] Calculating all possible ratios
> Message-ID:<[hidden email]>
> Content-Type: text/plain
>
> I have a data matrix with genes as colu
I have a data matrix with genes as columns and samples as rows. I want to
create all possible gene ratios.Is there an elegant and fast way to do it in
R and write it to a dataframe?
Thanks for any help.
Som.
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