Thank you!
On Jan 6, 2010 12:31am, Peter Ehlers wrote:
> x[apply(x,1,function(x)all(x>=0)),]
> -Peter Ehlers
> Simon Blomberg wrote:
> x[-which(x
> but I'm sure someone will suggest an easier way.
> Simon.
> On Wed, 2010-01-06 at 05:13 +, farida...@gmail.com wrote:
> Hello A
Hello All,
I would like to remove the entire row, if there is any negative element in
that row. What is the best way to do that?
For example,
x<-matrix(c(2,-1,-2,3,5,6,-3,7,4,2,1,0), 4, 3)
the returning matrix should look like
[,1] [,2] [,3]
[1,] 2 5 4
[2,] 3 7 0
Thank you in advance,
FM
Dear All,
I have a matrix like X and need to create a new matrix based on the vector
m which gives the number of replicates for each unique row. The resulting
matrix should look like y.
> x
x1 x2
[1,] 2 0.5
[2,] 2 0.5
[3,] 2 0.5
[4,] 6 1.0
[5,] 6 1.0
[6,] 6 1.0
[7,] 1 1.5
[8,] 1 1.5
[9,] 1 1.
Dear R experts,
I would like to substitute the values of a vector, say A, with the average
values taken over a factor
For example, lets assume
A
[1] 1 2 3 4 5 6 7 8 9 10
B
[1] 1 2 2 4 4 4 7 7 7 7
Levels: 1 2 4 7
I need to have
1.0 2.5 2.5 5.0 5.0 5.0 8.5 8.5 8.5 8.5 8.5
Thank you
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