Hi David,
I did something similar:
years <- scotland_weather%>%
select(starts_with("Year"))%>%
gather(year.col,year)%>%
select(-year.col)
months <- scotland_weather[seq(1, 24, 2)]%>%
gather(month,rainfall_mm)
sco
Dear Ista,
Many thanks for your reply.
Your tidyr solution didn’t work:
> dput(head(scotland_weather,6))
structure(list(Jan = c(293.8, 292.2, 275.6, 252.3, 246.2, 245
), Year.1 = c(1993L, 1928L, 2008L, 2015L, 1974L, 1975L), Feb = c
Hi,
Sorry for this direct approach but I am stuck with a stupid data that I would
like to reformat.
The datafile is location at: fileURL <-
http://www.metoffice.gov.uk/pub/data/weather/uk/climate/datasets/Rainfall/ranked/Scotland.txt
You can read the data by:
if(!file.exists("scotland_rainfal
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