Hello,
Given a list with all elements having identical layout, e.g.:
l = NULL
l[[1]] = list(4, "hello")
l[[2]] = list(7, "world")
l[[3]] = list(9, " ")
is there an easy way to collapse this list into a data.frame with each
row being the elements of the list ?
I.e. in this case I want to
Hello,
I am an advanced user of R. Recently I found out that apparently I do
not fully understand vectors and lists fully
Take this code snippet:
T = c("02.03.2008 12:23", "03.03.2008 05:54")
Times = strptime(T, "%d.%m.%Y %H:%M")
Times # OK
class(Times) # OK
is.list(Tim
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