Dear YZ,
I guess this is what you want:
1.
http://stackoverflow.com/questions/3418128/how-to-convert-a-factor-to-an-integer-numeric-without-a-loss-of-information
2.
http://stackoverflow.com/questions/6979625/arithmetic-operations-on-r-factors/6980780#6980780
3.
http://toddjobe.blogspot.jp/201
bigger say 10,000 rows of data,
the dissimilarity matrix will be O(n^2), and out of memory will occur.
I am wondering is there any better ways to do the mixed type cluster?
Cheng Yi
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Hi:
I am looking for clust algorithms for interval-typed data. (for example, the
session data with start time and end time).
I can't find it.
Please help to point me to any existing.
Cheng Yi
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R
Hi all,
I want to transform a dCgMatrix from package Matrix into a matrix.csr from
package SparseM, and I found out this link :
http://stat.ethz.ch/R-manual/R-devel/library/Matrix/html/SparseM-conv.html
But there's no informaion about usage/description/arguments, so how do I
use this SparseM-co
Hi all,
I have a huge sparse matrix, it's 360K*210K. Right now I have all the
nonzero elements and their indices, so I want to transform this information
into a sparse matrix so that I could pass the sparse matrix into svm
function.
I was planning to use sparse_matrix<- as.matrix.csr(v,nrow=36
Hi all,
When I called arrayIndex(20:23, dim=c(4,3,3)), it says "Error: could not
find function "arrayIndex"in R". So I called ls("package:utils") to see the
functions inside:
[1] "?"
[2] "adist"
[3] "alarm"
[4] "apropos"
[5] "aregexec"
[6] "argsAnywhere"
[7] "arrangeWindows"
[8] "a
use of the quotation marks,
so I thought the name must be just "utils".
On Tue, Apr 2, 2013 at 9:16 AM, Sarah Goslee wrote:
> Why do you think the utils package and the R.utils package are the same
> thing?
>
> Sarah
>
>
> On Tuesday, April 2, 2013, Yi Yuan wrote
list of expressions as its argument.
> This approach gives you more control over the legend and choice of
> fill colors at the expense of a couple of lines of code. To change the
> axis and legend titles, one can use the labs() function; e.g.,
>
> last_plot() + labs(x = "Visibili
Hi
I am trying to add a less than equal sign to a plot. I have previously done
this using unicode but is not working in this instance. Any suggestions
would be great
thanks
example code:
library(ggplot2)
df<-data.frame(vis=c(0,0,1,1) , count=c(10,15,20,10) , grp=c(0,1,0,1))
df$grp <-factor(df$g
or just
levels(df$y)[5:7]<-"others"
Ista Zahn wrote
> Hi Lorenzo,
>
> On Mon, Mar 25, 2013 at 6:18 PM, Lorenzo Isella
> <
> lorenzo.isella@
> > wrote:
>> Dear All,
>> Probably something very easy, but I am looking for the most efficient
>> ways
>> to achieve this.
>> Consider the following sn
or this with Pete's example
orig[,order(orig[2,])]
Pete Brecknock wrote
>
> fitz_ra wrote
>> I know this is posted a lot, I've been through about 40 messages reading
>> how to do this so let me apologize in advance because I can't get this
>> operation to work unlike the many examples shown.
does this work for you?
df1 = data.frame(x = rnorm(100))
df1$type = ifelse(df1$x <= 0 , "type1", "type2")
df1$group<-1
df2 = data.frame(x = rnorm(50,0,2))
df2$type = ifelse(df2$x <= 0 , "type1", "type2")
df2$group<-2
combined.df<-rbind(df1,df2)
boxplot(combined.df$x ~ combined.df$group *co
look at dev.new() to specify plot window size
and then ?layout to specify number and size of each plot in the window
Jiaqi.Zhang wrote
> Hi, all,
>
> I am working on the following code to learn how to plot graphs together. I
> used the par(mfrow=c(1,3)) function to try to put all three plot()
Hi
for the loop section runif needs curved brackets
Try
IAP <-NA
for (i in 1:Sample.Size){
if (DataSet$SES[i]>0) {
IAP[i] <- ifelse(runif(1)>0.75, 1, 0) # High SES, higher
chance to be in
Treatment #
}
else {
IAP[i] <- if
Hi, guys, my problem is solved.
I used file.info(list.files(getwd(),full.names=TRUE)) and found out that
the said file is listed as "kim.jpg" instead of "kim.jpeg". So
kim<-readJPEG("kim.jpg") worked. Thanks for your help and sorry for my
newbie question.
On
) the file with mode 666, but not all permission
> information is encoded in the mode.
>
> Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
> > -Original Message-
> > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Beh
Hi, r-help mailing list subscribers,
I installed jpeg package and tried to use
kim<-readJPEG("kim.jpeg") to read in a jpeg file, but R gave me an error:
Error in readJPEG("kim.jpeg") : unable to open kim.jpeg
I already put "kim.jpeg" in Rstudio's default working directory: "E:\home
work\Rstudio
I installed jpeg package and tried to use
kim<-readJPEG("kim.jpeg") to read in a jpeg file, but R gave me an error:
Error in readJPEG("kim.jpeg") : unable to open kim.jpeg
I already put "kim.jpeg" in Rstudio's default working directory: "E:\home
work\Rstudio". So I don't think it's a problem cau
perfect.
thanks for the quick reply
soon yi wrote
> Hi
>
> I have a list such as this
>
> list(c("q","w"),"r",c("r","w"),c("q","w"))
>
> How do i create a table to include the count of groups
Hi
I have a list such as this
list(c("q","w"),"r",c("r","w"),c("q","w"))
How do i create a table to include the count of groups of terms please?
ie so output is like / similar to
q","w""r" "r","w"
211
thanks for any help
--
View this message in contex
Thank you.
Rather embarrassed. Its fair to say i had rather over comlicated my attempts
to do this.
sy
soon yi wrote
> Hi
>
> I am using geom_smooth to fit linear regression lines over a scatterplot
> for two treatment groups. The default colour for the two lines are blue. I
> h
them to be black.
Adding colour="black" into the geom_smooth aesthetic does not change the
line colour to black.
thanks, sy
soon yi wrote
> Hi
>
> I am using geom_smooth to fit linear regression lines over a scatterplot
> for two treatment groups. The default colour for
Hi
I am using geom_smooth to fit linear regression lines over a scatterplot for
two treatment groups. The default colour for the two lines are blue. I have
been unable to change this with the usual options. A search online has not
suggested any solution / work around.
Is there a solution to this?
Hi
I am using ggplot to overlay two regression lines on a scatter plot each
corresponding to a treatment group.
The default plot gives a different slope for each treatment group. However,
in some cases i want the lines to be parallel -ie no significant
interaction.
My code:
ggplot(data=df,X,Y,
170 predictors - perhaps try lasso regression
--
View this message in context:
http://r.789695.n4.nabble.com/Re-update-fit-removing-insignificant-variables-tp4650379p4650394.html
Sent from the R help mailing list archive at Nabble.com.
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#Data
df<-data.frame(id=letters[1:10],var1=rnorm(10,10,5),var2=rnorm(10,5,2),var3=rnorm(10,1,1))
#Missing
df$var1[2]<-df$var2[c(2,6)]<-df$var3[c(2,5)]<-NA
na.replace<-seq(1:ncol(df))-1
df[,names(df)]<-sapply(1:dim(df)[2], function(ii)
{ifelse(is.na(df[,ii]),na.replace[ii],df[,ii])} )
David Ro
Hello
I am using sem to look at the direct effect of one variable on another but i am
uncertain if i am progressing correctly.
An example:
covar1<- matrix(c(0.4,-0.2,3,-0.2 , 0.3,-2 , 3 ,-2 , 60), nrow=3,byrow=T)
rownames(covar1)<-colnames(covar1)<-c("endo","exo","med")
path1<-matrix(c( "
Hi
I would like to learn how the R function "hclust" deals with ties. It is
written in Fortran, so I cannot access the code. Thanks!!
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I encountered this problem when I was learning nonlinear regression with R :
there is this function "plotfit" in package "nlstools",which "displays
a superimposed plot of the dependent variable versus one the
independent variables together with the fitted model.",but when I
execute the example give
Dear all,
Suppose my data frame is as follows:
id price distance
1 2 4
1 35
...
2 4 8
2 5 9
...
n 3 7
n 8 9
I would like to calculate the rank-order correlation between price and
distance for each id.
cor(price,distance,method = "spearman") calculate a correlation for
yi has chosen to send you a free movie ticket, up to $10 value.
Sit back, relax, and enjoy! In an effort to spread the word about our great
products we are allowing our members to send free movie tickets to their
selected friends at no charge to our members. This time yi chose you! To redeem
yi has chosen to send you a free movie ticket, up to $10 value.
Sit back, relax, and enjoy! In an effort to spread the word about our great
products we are allowing our members to send free movie tickets to their
selected friends at no charge to our members. This time yi chose you! To redeem
fic code that
> fixes
> the problem and gets the job done, that would be the most useful.
>
>
> Thanks very much in advance for your help!
>
> Sincerely,
> ---
> Josh Banta, Ph.D
> Center for Genomics and Systems Biology
> New York University
> 100 Washin
rise 4.2. Could somebody show
> me how to import/export SAS datasets. Thanks.
>
--
Gong-Yi Liao
Department of Statistics
University of Connecticut
215 Glenbrook Road U4120
Storrs, CT 06269-4120
860-486-9478
__
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ct.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Gong-Yi Liao
Department of Statistics
University of Connecticut
215 Glenbrook Road U4120
Storrs, CT 06269-4120
860-486-9478
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_
-1.3025-0.3499
Is MASS's mca developed with different definition to SAS's
corresp ?
Thank you for any comments!
--
Gong-Yi Liao
Department of Statistics
University of Connecticut
215 Glenbrook Road U4120
Storr
Hi,ALL
I want to use R in Perl, the Statistics::R module is great but I meet the
problem: I don`g know how to pass one array from Perl to R, can anyone show me?
Any suggestion will be appreciate~
Thank you!
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Thanks for the info!
-Original Message-
From: David Scott [mailto:d.sc...@auckland.ac.nz]
Sent: Friday, October 22, 2010 4:19 PM
To: David Reiner
Cc: Li, Jing Yi; r-help@r-project.org
Subject: Re: [R] previous business day
On 23/10/2010 4:59 a.m., David Reiner wrote:
> Look at
Great. Thanks a lot!
Please follow the attached hyperlink to an important disclosure:
http://www.credit-suisse.com/legal/marketcommentary
-Original Message-
From: David Reiner [mailto:david.rei...@xrtrading.com]
Sent: Friday, October 22, 2010 11:59 AM
To: Li, Jing Yi
Cc: r-help@r
yes. do you know the name of related functions in the timeDate package?
Thanks!
-Original Message-
From: David Reiner [mailto:david.rei...@xrtrading.com]
Sent: Friday, October 22, 2010 10:10 AM
To: Li, Jing Yi; David Winsemius
Cc: r-help@r-project.org
Subject: RE: [R] previous business
, 2010 4:34 PM
To: Li, Jing Yi
Cc: Clint Bowman; Henrique Dallazuanna; r-help@r-project.org
Subject: Re: [R] previous business day
On Oct 21, 2010, at 4:20 PM, Li, Jing Yi wrote:
> Yeah, thanks Henrique for the code. It works! But I also have the
> questions for the holidays.
>
>
: Thursday, October 21, 2010 4:16 PM
To: Henrique Dallazuanna
Cc: Li, Jing Yi; r-help@r-project.org
Subject: Re: [R] previous business day
May also wish to "or" in a check for holidays.
--
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler
How to get the previous business day in R? I saw some post about using
functions in timeSeries package before but can not find it anymore.
Thanks!
===
Please access the attached hyperlink for an important el...{{dropped
yes. c(T,F) does return
[1] TRUE FALSE
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Tuesday, October 12, 2010 10:00 AM
To: Li, Jing Yi
Cc: r-help@r-project.org
Subject: Re: [R] append rows to Sybase datatable using RJDBC
On Oct 12, 2010, at 9:51 AM
Hi,
Does anyone have experience using RJDBC library to write to Sybase
datatable? The jdbc driver I am using is jConnect 6.0. I can
successfully write into a new datatable, but have problem appending rows
to existing one. It either complains "Table *** already exists" or
simply overwrite the exist
Does anyone have experience using RJDBC library to write to Sybase
datatable? The jdbc driver I am using is jConnect 6.0. I can
successfully write into a new datatable, but have problem appending rows
to existing one. It either complains "Table *** already exists" or
simply overwrite the existing o
quot;variance of dependent variable
> based on model". Do you want its total variance, residual variance,
> ___ ?
>
> Cheers,
>
> Josh
>
> On Mon, Sep 27, 2010 at 12:58 PM, Yi Du wrote:
> > Hi folks,
> >
> > I use lm to run regression and I don&#
Hi folks,
I use lm to run regression and I don't know how to predict dependent
variable based on the model.
I used predict.lm(model, newdata=80), but it gave me warnings.
Also, how can I get the variance of dependent variable based on model.
Thanks.
[[alternative HTML version deleted]]
ing...@lancaster.ac.uk> wrote:
> On Thu, Sep 2, 2010 at 7:17 AM, Yi wrote:
> > Hi, folks,
> >
> > runif (n,min,max) is the typical code for generate R.V from uniform dist.
> >
> > But what if we need to fix the mean as 20, and we want the values to be
> > int
Hi, folks,
runif (n,min,max) is the typical code for generate R.V from uniform dist.
But what if we need to fix the mean as 20, and we want the values to be
integers only?
Thanks
[[alternative HTML version deleted]]
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soda 7 0.5987654
> 3 drink soda 6 0.5987654
> 4 fruit apple 2 0.722
> 5 fruit apple 3 0.722
> 6 fruit orange 1 0.722
>
> HTH,
> Dennis
>
> On Wed, Aug 11, 2010 at 3:40 PM, Yi wrote:
>
>> Thank you for reminding me.
&
tration= sum of square of share
For food 1, fruit, for apple ,there are two rows, value =2 and 3; for
oranget, value =1.
share_apple=(2+3)/(2+3+1)=5/6 ## It is the same for the two rows
share_organge=1/6
concentration_fruit= share_apple^2+sjare_orange^2=(5/6)^2+(1/6)^2
Hope this makes it easier to und
Hi, folks,
##
food=c('fruit','fruit','fruit','drink','drink','drink')
type=c('apple','apple','orange','water','soda','soda')
value=c(2,3,1,5,7,6)
data=data.frame(food,type,value)
share=c((2+3)/(2+3+1),5/6,1/6,5/(5+7+6),13/18,13/18)
market_con=c(rep(0.833^2+0.167^2,3),rep(0.278^2+0
mmand to generate the prediction of z
with the new data.frame but there should be a better way.
Thanks all.
Yi
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PLEASE do read t
much larger than the values from se.fit=T.
The reason why I need to know the estimations of expectation and also
variance is that Y=ln(Z) and I need to know the expectation of Z.
Thanks
Yi
[[alternative HTML version deleted]]
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R-help@r
|X*)] or say sd[log(Y|X*)].
Thanks.
On Wed, Jul 21, 2010 at 3:44 PM, Dennis Murphy wrote:
> Hi:
>
> On Wed, Jul 21, 2010 at 2:29 PM, Yi wrote:
>
>> Hi, folks,
>>
>> Here are the codes:
>>
>> ##
>> y=1:10
>> x=c(1:9,1)
>&
Sorry, for the second question. I stated in a wrong way. My aim is the mean
and sd of each new observation.
#
mean=fitted(prediction)
##
But I do not know how to get sd for each new observation.
Any tips?
Thanks
Yi
On Wed, Jul 21, 2010 at 2:29 PM, Yi wrote:
> Hi, folks,
>
e value of Residual standard error from summary(lin)?
Answer to either question will be appreciated!
Thanks
Yi
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PLEASE do read t
Hi, folks,
Suppose the data is as follows:
###
x=1:10
y=2:11
z=3:12
data1=data.frame(x,y)
data2=data.frame(x,z)
##
In real case, how to check data1$x and data2$x are the same or not? I am
using for-loop to do this.
Is there a quicker way?
Thanks!
Yi
[[alternative HTML
Hi,
I attached a picture to compare the 'mess' to what I what.
Maybe there is difference between computers?
Thanks.
On Fri, Jul 2, 2010 at 10:52 AM, David Winsemius wrote:
>
> On Jul 2, 2010, at 1:34 PM, Yi wrote:
>
> Hi, folks,
>>
>> I would like to copy t
.01 * 0.05 . 0.1 1
Residual standard error: 0.7181 on 8 degrees of freedom
Multiple R-squared: 0.3753, Adjusted R-squared: 0.2972
F-statistic: 4.807 on 1 and 8 DF, p-value: 0.0597
How can I get the exact ouput as shown in R but not as the above?
Thanks.
~ . , sum))
> first second (all)
> 1 b Brazil 2
> 2 c China15
> 3 e England13
> 4 f France 8
> 5 j Japan 5
> 6 k Korea 4
> 7 u usa 8
>
> names(ms)[3] <- 'third'
>
> This seems to
x,newdata2$x)
names(new)=c('x','y','z','v1','v2')
new
Because I do not think 'aggregate' can not set z as a list and at the same
time keep x and y for z.
Any tips? I mean my way is too 'silly'.
Thanks all in advance!
Yi
O
Hi, folks,
I am sorry that I did not state the problem correctly yesterday.
Please let me address the problem by the following codes:
first=c('u','b','e','k','j','c','u','f','c','e')
second=c('usa','Brazil','England','Korea','Japan','China','usa','France','China','England')
third=1:10
data=data.
This does not work. ><
But the expected dataframe is like this:
1 uthird 8
2 bthird 2
3 ethird 13
4 kthird 4
5 jthird 5
6 cthird 15
8 fthird 8
Thanks in advance.
Yi
[[alternative HTML version
Hi, folks,
Please first look at the codes:
plan_a=c('apple','orange','apple','apple','pear','bread')
plan_b=c('bread','bread','orange','bread','bread','yogurt')
value=1:6
data=data.frame(plan_a,plan_b,value)
library(plyr)
library(reshape)
mm=melt(data, id=c('plan_a','plan_b'))
sum_plan_a=cast(mm,
Hi, folks,
Finally Friday~~ Here comes the question:
x=c('germany','poor italy','usa','england','poor italy','japan')
y=c('Spain','germany','usa','brazil','england','chile')
s=1:6
z=3:8
test=data.frame(x,y,s,z)
#Now I only concern the countries ('germany','england','brazil'). I would
like to ke
(1e+03,
5e+3).
I would like all the data in the digit format (1000, 5000).
Does any function works for this?
Big thanks
Yi
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x3
-10-02 5 1 (# points in
this range)
0-10 7 9 6
...
I know the table function but I do not know how to deal with the range
issue.
Thanks in advance.
Yi
[[alternative HTML
ther there is a general way to figure out how R function
works and what is the underlying theory besides looking at the codes
(type var or lm at the Rprompt). Because R codes are too difficult to
understand.
Thanks
Yi
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assumption and the model used for rlm.
Thanks
Yi
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PLEASE do read the posting guide http://www.R-project.org/posting-guid
Hi, folks,
As seen in the following codes:
x1=rlnorm(10)
x2=rlnorm(10,mean=2)
y=rlnorm(10,mean=10)### Fake dataset
linmod=lm(log(y)~log(x1)+log(x2))
After the regression, I would like to know the mean of y. Since log(y) is
normal and y is lognormal, I need to know the mean and variance of log(y)
I am so frustrated about reading data from this sample csv file.
My code is :
>test=read.csv(file='test.csv',header=T)
warning message:
In read.table(file = file, header = header, sep = sep, quote = quote, :
incomplete final line found by readTableHeader on 'test.csv'
>test
[1] ÐÏ.à..
<0 ro
Hi,
I need to regress the population on time slot and also days in advance.
A sample dataset is like this. I do not know whether I can attach a file in
this mailing list or not. If you know how to do it, I will be happy to send
you my data file.
time slot days in advance US EURCHIN
Hi,
I need to regress the population on time slot and also days in advance.
A sample dataset is like this. I do not know whether I can attach a file in
this mailing list or not. If you know how to do it, I will be happy to send
you my data file.
time slot days in advance US EURCHINA
Hi, folks
linmod=y~x+z
summary(linmod)
The summary of linmod shows the standard error of the coefficients. How can
we get the sd of y and the robust standard errors in R?
Thanks!
[[alternative HTML version deleted]]
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Hi, folks,
test=matrix(rep(letters[1:3],6),nrow=6,byrow=T)
test[2,]=letters[5:7]
test[4,]=c('e','f','i')
test[1,3]='i'
colnames(test)=c('leave','arrive','line')
The code will generate a sample dataset. I have thousands rows of data.
For the same 'leave' and 'arrive', how can I get the sum of squ
i've just installed the package"xlsx",which is used for read,write,format
Excel 2007 files, as i loaded the package ,i was told to intall the package
rJava, the problem was that i didn't have a JAVA platform on my computer, so
i have to install JAVA JDK first, my problem is ,after i 've installed
J
Hi Alex,
You can try to use:
par(new=TRUE)
to draw the two graphs together. But keep in mind that the scale of x axis
of both graphs is using the same level. Otherwise, the graph would be messed
up.
Yi
On Tue, Apr 6, 2010 at 6:16 PM, Alexandre Serra Barreto wrote:
>
> Dear lis
to do
that?
Thanks,
Yi
On Mon, Mar 1, 2010 at 11:26 AM, Owe Jessen wrote:
> Did you have a look at the package arima?
>
> HTH
> Owe
>
>> Hi there,
>>
>>
>> I want to fit a ARMA model with the method of MLE. Is there any package
>> that
>>
Hi there,
I want to fit a ARMA model with the method of MLE. Is there any package that
could implement this method?
Thanks,
Yi
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I use abline(h=0.08) to draw a horizontal line and I also want to
show 0.08 in the y-axis, how can I do it?
Many thanks,
Yi
--
Yi Du
Ph. D student in Economics
University of Missouri
Department of Economics
118 Professional Building
Columbia MO 65211
1-573-239-6467
[[alternative
lattice of kernelplot, But I still don't know how to draw the four
years kernel in one graph. Also, I don't need the rug(age) in kernelplot,
how can I delete it?
Thanks.
--
Yi Du
[[alternative HTML version deleted]]
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ifferent from SAS, perhaps SAS and R use different
> breakpoints, that is, different boundaries between the histogram bars.
>
> -Don
>
> At 11:58 AM -0600 1/13/10, Yi Du wrote:
>
>> Hi,
>>
>>
>> I use a vector of data to draw the histogram, but it is different from
don't know
where I did wrong.
Thanks.
--
Yi Du
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.h
Hi,
Is that okay to let R to read data set more than 1 rows and use it to do
some kernel density estimation? Thanks.
Yi
--
Yi Du
Ph. D student in Economics
University of Missouri
Department of Economics
118 Professional Building
Columbia MO 65211
1-573-239-6467
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ls='GMM', but I can't get
the suitable results.
Many thanks.
Yi
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Hi there,
I run a loop program with R and need to save the variable in each step into
a vector. After I ran the code, R told me that Error: cannot allocate vector
of size 266.6 Mb. Is there any solution of this kind of problem? Thank you
for your attention.
Yi
--
Yi Du
[[alternative
Hi,
I try to use "randomFroest" package to run SNP data analysis. I have the
following questions.
1. Can the outcome variables in Random Forests be binary or continuous?
2. Can the covariates in Random Forests be continuous or categorical?
3. How to define which variables (both outcome and
-- Forwarded Message ---
From: "Wang Yi"
To:
Sent: Fri, 6 Feb 2009 23:30:56 +0800
Subject: Problem about Mann-Kendall trend test
Dear all R-users:
In my case the series is the annual number of dry spell with their length
exceeding a given threshold representi
in advance
Regards
--
Wang Yi
START Regional Center for Temperate East Asia(TEA),
Institute of Atmospheric Physics(IAP),
Chinese Academy of Sciences(CAS),
Qijiahuozi Huayanli 40#,
P.O.Box 9804, Beijing 100029,China
Tel:13466795920
E-mail:wan...@tea.ac.cn
is gumble but I can't find useful information in ks.test help
page. Can
anyone tell me how to perform the ks test.
Thanks a lot for your help.
--
Wang Yi
START Regional Center for Temperate East Asia(TEA),
Institute of Atmospheric Physics(IAP),
Chinese Academy of Sciences(CAS)
ncan Murdoch
>
Thanks. I've read all the manuals and my situation is more complicated
than the external ptrs and finalizers can handle. I'll probe the
R-devel list and see what I can get.
--
Yi
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onment('package:base')
unlockBinding('<-',env)
assign('<-', newAssign, envir=env)
.Internal(lockBinding(as.name('<-'), env)) #not using lockBinding
directly because it calls '<-'
It gave me this error: Error: evaluation nested too deeply
unting for some large resource. I guess this is already the most
non-intrusive way I can think of--initially I modified R's source
code, an even worse option.
>
> Patrick Burns
--
Yi
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lar type of objects, but
preserve its effect for other regular objects (in other words, if I do
x<-5 with my new <-, x will be 5 and nothing strange happens), then
what should I put in the [ ] below?
old <- `<-`
old(`<-`, function(x, value){
if (value is my t
On Thu, Jan 22, 2009 at 4:17 PM, Wacek Kusnierczyk
wrote:
> Duncan Murdoch wrote:
>> On 1/22/2009 2:41 PM, Yi Zhang wrote:
>>> Hi,
>>>
>>> I want to create an alias for the "<-" function and then later
>>> overwrite it. Any idea ho
On Thu, Jan 22, 2009 at 3:06 PM, Duncan Murdoch wrote:
>
> get("<-") will give it to you, and
>
> `<-` <- function(x, y) cat("x=", x, "y=", y, "\n")
>
> will change it -- and will probably be the last effective thing you do in
> that session, unless you're really careful:
>
>> x <- 1
>> x
> [1] 1
Hi,
I want to create an alias for the "<-" function and then later
overwrite it. Any idea how I can get the "<-" function object? I know
for other functions it's easy, something like "f <- seq" will do; how
really no clue for this one. Thanks!
__
R-help
)
> x <- 2
> g() # 1
>
> On Wed, Jan 21, 2009 at 5:45 PM, Yi Zhang wrote:
>> Hello,
>>
>> I'm writing a function like this:
>>
>> f<-function(x,y,...) {
>> ...
>> assign(x,y,envir=?)
>> }
>>
>> I need the caller (of
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