Re: [R] Subset and 0 replace?

2015-05-21 Thread Vin Cheng
sult but in a more useful format (e.g., numbers > instead of character strings for sum). > > > desiredResult > [,1] [,2] [,3] [,4] [,5] > [1,] "V5" "V8" "V10" "V44" "V2" > [2,] "0.0087

Re: [R] Subset and 0 replace?

2015-05-21 Thread Vin Cheng
values>16) and use subscripting on both the left and rightside of the assignment operator to put the results in the right place. E.g.,x <- c(-1, 1, 2)ok <- x>0 x[ok] <- log(x[ok])(b) make your function handle any case so you don't have to do anysubsetting on either

[R] Subset and 0 replace?

2015-05-20 Thread Vin Cheng
Hi, I'm trying to group rows in a dataframe with SPCLORatingValue factor >16 and summing the Wgt's that correspond to this condition. There are 100 dataframes in a list. Some of the dataframes won't have any rows that have this condition SPCLORatingValue>16 and therefore no corresponding

Re: [R] binding two lists of lists of dataframes together

2015-05-14 Thread Vin Cheng
Thanks David! Have a good one! > Subject: Re: [R] binding two lists of lists of dataframes together > From: dwinsem...@comcast.net > Date: Thu, 14 May 2015 07:58:43 -0700 > CC: r-help@r-project.org > To: newrnew...@hotmail.com > > > On May 14, 2015, at 7:15 AM, Vi

Re: [R] binding two lists of lists of dataframes together

2015-05-14 Thread Vin Cheng
m: dwinsem...@comcast.net > Date: Wed, 13 May 2015 15:51:47 -0700 > CC: r-help@r-project.org > To: newrnew...@hotmail.com > > > On May 13, 2015, at 2:01 PM, Vin Cheng wrote: > > > Hi David, > > > > I tried both solutions you provided(lapply(dlist, function(x) rbind

Re: [R] binding two lists of lists of dataframes together

2015-05-13 Thread Vin Cheng
ot;ID27", "ID28", "ID29", "ID3", "ID4", "ID5", "ID6", "ID7", "ID8", "ID9"), class = "factor"), structure(c(7L, 11L, 21L, 29L, 9L, 23L, 3L, 14L, 27L, 28L, 3L, 5L,7L, 28L, 12L, 14L, 28L, 12L

Re: [R] binding two lists of lists of dataframes together

2015-05-12 Thread Vin Cheng
> Date: Tue, 12 May 2015 14:23:54 -0700 > CC: r-help@r-project.org > To: newrnew...@hotmail.com > > > On May 12, 2015, at 12:56 PM, Vin Cheng wrote: > > > Hi, > > > > Thanks David! Your solution 3 worked well with the sample data, but when I > > run

Re: [R] binding two lists of lists of dataframes together

2015-05-12 Thread Vin Cheng
19025, 0.01755, 0.02279875, 0.00744525, 0.02255, 0.01792375, 0.0164255, 0.00978, 0.01792375, 0.0020025)), V3 = list(c(47L, 95L, 26L, 64L, 16L, 55L, 61L, 39L, 23L, 66L), c(1, 1, 2, 3, 4, 5, 6, 7, 8, 9), c(NaN, NaN, NA, NA, NA, NA, NA, NA, NA, NA), c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0),

Re: [R] binding two lists of lists of dataframes together

2015-05-12 Thread Vin Cheng
Hi, Apologies for the newbie error. Thanks John, Jim, Jeff! Please find the dput output below. I'm trying to take list1 and list 2 and bind them together at an individual list level by column - all the structures and col names will be the same, but the number of rows could be different

Re: [R] binding two lists of lists of dataframes together

2015-05-12 Thread Vin Cheng
Hi, Apologies for the newbie error. Thanks John, Jim, Jeff! Please find the dput output below. I'm trying to take list1 and list 2 and bind them together at an individual list level by column - all the structures and col names will be the same, but the number of rows could be different for

Re: [R] binding two lists of lists of dataframes together

2015-05-11 Thread Vin Cheng
> From: newrnew...@hotmail.com > To: r-help@r-project.org > Date: Mon, 11 May 2015 20:16:40 + > Subject: [R] binding two lists of lists of dataframes together > > Hi, > I'm new to R and am stumped. I'm trying to bind List 1 to List 2 and have > the corresponding Output. > > I've fou

[R] binding two lists of lists of dataframes together

2015-05-11 Thread Vin Cheng
Hi, I'm new to R and am stumped. I'm trying to bind List 1 to List 2 and have the corresponding Output. I've found the following code - I can't say I understand rbindlist(lapply(list12, "[", i, TRUE)). Either way - it doesn't give exactly what's needed. library(data.table) list12 <- li