Hello R users I'm posting here my recent implementation of Top Trading Cycles
Algorithm in R. For more details, look for Shapley and Scarf "On Cores and
Indivisibility" Journal of Mathematical Economics, 1, 23-37.
ttc.many <- function(m, n, preference.row, preference.col,expand)
{
# m = row numbe
Hello R Developers, I have made a new code for this algorithm in R. In the
end I present an very small example with system.time computing.
Gale-Shapley Many-to-One (Note that many are always in Rows):
#
#
gsa
David Winsemius wrote
> On Nov 2, 2012, at 11:20 AM, VictorDelgado wrote:
>
>> Hello dear R-helpers,
>>
>> I'm working with R-2.15.2 on Windows 7 OS. I'm stucked with a merge of
>> two
>> data frames by characters.
>> In each data frame I
Hello dear R-helpers,
I'm working with R-2.15.2 on Windows 7 OS. I'm stucked with a merge of two
data frames by characters.
In each data frame I got two different list of names, that is my main-key to
be merged.
To figure out what I'm saying, I build up a modified "?merge" example, with
errors b
Vinicius,
Vinicius Magalhães wrote
>
>
> + n <- length(*x.ts*)
> + for (p in 0:maxord[1]) for (d in 0:maxord[2]) for (q in 0:maxord[3])
> + for (P in 0:maxord[4]) for (D in 0:maxord[5]) for (Q in 0:maxord[6])
> + {
> + fit <- arima(*x.ts*, order=c(p,d,q),
> + seas = list(order=c(P,D,Q),
>
VictorDelgado wrote
>
> gsa <- function(m, n, preference.row, preference.col, first)
> {
> # m: number of rows (men)
> # n: number of columns (women)
> # first 1 for row (men); and 2 for column (women)
> #
> # Two Auxiliary functions:
> # 1:
> min.n <- fun
VictorDelgado wrote
>
>
> quantile(x)
>
>
Correcting to
quantile(q)
-
Victor Delgado
cedeplar.ufmg.br P.H.D. student
www.fjp.mg.gov.br reseacher
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Gerhard wrote
>
>
> Suppose I create a custom function, consisting of two beta-distributions:
>
> myfunction <- function(x) {
> dbeta(x,2,6) + dbeta(x,6,2)
> }
>
> How can I calculate the quantiles of myfunction?
>
> Thank you in advance,
>
> Gerhard
>
>
Gehard, if do you want to know
VictorDelgado wrote
>
> Dear R-helpers,
>
> I'm not a speciallist in writing complex functions, and the function still
> very rusty (any kind of suggestions are very welcome). I want to implement
> Gale-Shapley algorithm for R Language. It is based on
> http://ww
sambooth21 wrote
>
>
> And I just don't know where to start, if anyone could help this would be
> greatly appreciated
>
>
look for ?anova
-
Victor Delgado
cedeplar.ufmg.br P.H.D. student
www.fjp.mg.gov.br reseacher
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sambooth21 wrote
>
> I am having a few problems importing the data i'm running this code and
> the table sets up fine but all of the data values say NA:
>
> housdat<- c(21, 21, 28, 14, 19, 37, 34, 22, 36, 17, 23, 401, 10, 11, 36,
> 3, 5, 23, 61, 23, 17, 78, 46, 43, 43, 35, 40, 48, 45, 86, 26, 18
Dear R-helpers,
I'm not a speciallist in writing complex functions, and the function still
very rusty (any kind of suggestions are very welcome). I want to implement
Gale-Shapley algorithm for R Language. It is based on
http://www.jstor.org/stable/10.2307/2312726 Gale and Shapley (1962) , and it
Hi Amy Wesolowski,
I don't have a straightfoward answer to you question. I have been working
with reldist too, and the 'rpy' and 'rpluy' functions described by "Applying
Relative Distribution Methods in R" are also not working here in my 2.9.1
R-version. I think its because they are reldist intern
rstudent,
one solution could be given by spliting your graph in two parts:
part_1 <- # take the desired four points subset #
part_2 <- # all rest points not to label
You will also need one vector with your names. I supose:
list <- c("B13", "G13", "K14", "N14")
So
plot(part_1$x, part_1$y)
text
Another possibility without using subset():
plot(Well[][Plate==101]~Raw[][Plate==101])
This also works to '>=' '<=' and other conditions.
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Sent from the R help mailing list archive at
ty S. Goslee,
It's helpfull to test the condition:
> all.equal(s[4],0.15)
[1] TRUE
instead the previous "FALSE" answer obtained with
>s[4]==0.15
[1] FALSE
but I still need get it to vector r:
Victor Delgado wrote:
>
>
>> for (w in 1:length(s)){
>> r[w] <- dados[,3][dados[,2]==s[w]][1]
>> }
Hi There,
I'm facing one problem to construct a vector using the "for" command:
I have one matrix named 'dados' (same as /data/ from portuguese), for
example:
> dados[140:150,]
[,1] [,2] [,3]
[1,] 212.7298 0.14 0.11
[2,] 213.3778 0.14 0.11
[3,] 214.0257 0.15 0.11
[4,] 214.6737 0.1
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