Duncan,
Alas, I had left out the --pdf flag when I tried the solution.
I am glad I have an answer now, and a better understanding of the problem.
Troy
On Wed, Jan 30, 2013 at 9:50 AM, Duncan Murdoch wrote:
> On 13-01-30 11:00 AM, Troy S wrote:
>
>> Michael,
>>
>> I a
.sty files somewhere to help the situation.
Thanks guys. I appreciate the help!
Troy
On Wed, Jan 30, 2013 at 5:52 AM, Michael Friendly wrote:
> On 1/29/2013 6:04 PM, Troy S wrote:
>
>> Ok, yes I realize it. So let me try to fix it:
>> I removed the sty files, and set TEXIN
rdoch wrote:
> On 13-01-29 4:55 PM, Troy S wrote:
>
>> Duncan,
>> Copying all 3 sty files to my working directory solved the problem. I'm
>> still curious why this was necessary in my new install. Duncan, many
>> thanks!
>>
>
> You do realize that yo
Duncan,
Copying all 3 sty files to my working directory solved the problem. I'm
still curious why this was necessary in my new install. Duncan, many
thanks!
Troy
On Tue, Jan 29, 2013 at 10:58 AM, Duncan Murdoch
wrote:
> On 29/01/2013 1:37 PM, Troy S wrote:
>
>> Dear useRs--
Dear useRs--
I have been using Sweave with miktex for years, but on a new install on
Windows XP, miktex seems to be hung up on single quotes. See example below.
Digging through stackexchange, I found using \usepackage[noae]{Sweave} in
the tex file solved the problem. My questions are:
--Why wo
Dear UseRs,
I'm running a chi-squared test where the expected matrix is the same as the
observed, after rounding. R reports a X-squared of zero with a p value of
one. I can justify this because any other result will deviate at least as
much from the expected because what we observe is the expect
Dear R List,
I am trying to use mixed models to analyze an intervention and want to make
sure I am doing it correctly. The intervention is for lowing cholesterol
and there are two groups: one with an intervention and one without. The
subjects were evaluated a differing amount of time, so there w
Dear R fans,
I am trying to do step-wise linear regression using the F-test to decide
which variables to admit. Ewout Steyerberg suggests using the F-test for
this purpose.
I first build a model using no variables using lm(y ~ 1) and then using one
variable that is a strong predictor using lm(y
> Stefano
>
> -Messaggio originale-
> Da: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org]per conto di Troy S
> Inviato: Friday, August 06, 2010 6:31 PM
> A: Michael Bedward
> Cc: r-help@r-project.org
> Oggetto: Re: [R] Confidence Intervals for
exp(sum.coef[,1]+1.96*sum.coef[,2])
> > lower.ci<-exp(sum.coef[,1]-1.96*sum.coef[,2])
> >
> > cbind(est,upper.ci,lower.ci)
> >
> > regards.
> >
> > 2010/8/6 Troy S
> >
> >> Dear UseRs,
> >>
> >> I have fitted a logistic regress
Dear UseRs,
I have fitted a logistic regression using glm and want a 95% confidence
interval on a response probability. Can I use
predict(model, newdata, se.fit=T)
Will fit +/- 1.96se give me a 95% of the logit? And then
exp(fit +/- 1.96se) / (exp(fit +/- 1.96se) +1) to get the probabilities?
R Gurus--
I am trying to adopt this code. I do not care about colors, but would like
the data in the upper plots jittered. Here is what I have. So far, the
lower squares are blank.
Troy
print(splom(foo,
upper.panel = function(x, y, ...) {panel.splom(jitter(x), jitter(y),
...)},
l
r-friends--
I am trying to make a lattice plot with a single label at 0.05. A reference
line at y=0.05 as well... This is what I have so far. The label reads 0.0 and
there is a grid instead of a single reference line. Can someone help please?
Troy
x<-18:35
(pv<-1/(x-17))
xydf<-data.frame(x,
R Fans--
I am having problems with the following code. It worked under R 2.6.0 but not
in 2.7.0.
> library(Epi)
> df <- read.table( "c:/Documents and Settings/Troy S/My
> Documents/debug_chisq_080613b.txt")
> summary(df)
cvd agecat
Min. :0.0
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