Dear all,
I can't get the labels slot in ICLUST to accept a character vector.
library(psych)
test.data <- Harman74.cor$cov
ic.out <- ICLUST(test.data,nclusters
=4,labels=letters[1:ncol(test.data)]) ## Error in !labels : invalid
argument type
ic.out <- ICLUST(test.data,nclusters =4,labels=1:ncol(tes
Any advice on which package I can use for calculating effect sizes for two
dependent samples? compute.es seems only to consider independent samples.
Thanks in advance
Steve Powell
[[alternative HTML version deleted]]
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R-help@r-project.org
Structural equation modelling combines those observed variables
> exactly to be able to take the variation on the combined latent
> variable into account. If you use those latent variables as input in a
> second analysis, you lose the information regarding the variation.
>
> Cheers
&g
SPSS.
>
> I don't understand what you mean with scores in the context of
> structural equation modelling. Lavaan is unknown to me.
>
> Cheers
> Joris
>
> On Tue, Jun 22, 2010 at 3:11 PM, Steve Powell wrote:
>> Dear expeRts,
>> sorry for such a new
or lavaan packages, to use in further analyses?
Best wishes
Steve Powell
www.promente.org | skype stevepowell99 | +387 61 215 997
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PLEASE do read the posting guide http://www.R-p
Dear expeRts
Is it not the case that very many multi-level datasets have associated
sample weights? But then I don't see a way to include them in the
analyses? Or, how can I make nlme talk to the "survey" package?
Best Wishes
Steve
__
R-help@r-project.o
For psychologists like me (possibly for others) by far the most
time-consuming detail is variable labels. I need them for just about
every analysis I do. We can use special packages like Hmisc and its
function spss.get to import the labels, but then nearly all the other
packages don't respect the l
y stuck.
If someone could put me on the right track I could be more specific with
reproducible examples etc
Best Wishes
Steve Powell
**details of Lahirie method as we used it: the schools were
put into a list in order of ascending size (student population) and this
list was divided
calculate a covariance
matrix of the questionnaire scores for use in sem. How do I apply the weights?
Thanks in advance,
Steve Powell
www.promente.org
proMENTE social research
Krančevićeva 35
71000 Sarajevo
skype stevepowell99
mob. +387 61 215 997
tel. +387 33 556 865
fax. +387 33 556 866
Thanks Prof Ripley! How obvious in retrospect!
Prof Brian Ripley wrote:
On Thu, 4 Sep 2008, Steve Powell wrote:
Dear list members,
I am trying, within a lapply command, to print the name of the objects
in list or data frame. This is so that I can use odfWeave to print out a
report with a
Dear list members,
I am trying, within a lapply command, to print the name of the objects
in list or data frame. This is so that I can use odfWeave to print out a
report with a section for each object, including the object names.
I tried e.g.
a=b=c=1:5
lis=data.frame(a,b,c)
lapply(
lis, function
)
presumably my zip and unzip are not set up correctly but I dont know how to do
that. I installed zip and unzip from info-zip.org as suggested in the help
file, and think I managed set my Windows path to include the folders where they
are installed, but still no luck. Any ideas?
thanks
Steve Powell
sion but can't seem to get
it right. Any ideas?
Thanks in advance
Steve Powell
proMENTE social research
research | evaluation | training & consulting
Kranjčevićeva 35, 71000 Sarajevo
mobile: +387 61 215 997 | office: +387 33 556 865 | fax: +387 33 556 866
skype: stevepowell99
o
label(df$a)="lab1"
label(df$b)="lab2" etc
Or
attributes(df$a)$label="lab1" etc
But I would like to do this with a loop or an apply function.
Thanks and best wishes
Steve Powell
proMENTE social research
research | evaluation | training & consulting
Kranj
Dear list members
I would like to apply a vector of labels
v=c("lab1","lab2","lab3")
to a dataframe
df=data.frame(1:3,1:3,1:3)
using some kind of loop or apply function.
Any ideas?
Thanks
Steve Powell
Checked by AVG Free Edition.
17:03
[[al
Dear Sumit
Tinn-R is a little text editor which can do all that and more:
http://www.sciviews.org/Tinn-R/
Best wishes
Steve Powell
proMENTE social research
research | evaluation | training & consulting
Kranjčevićeva 35, 71000 Sarajevo
mobile: +387 61 215 997 | office: +387 33 556 865 |
coeff)$"Pr(>|z|)" into the loop.
Very best wishes
Steve Powell
proMENTE social research
research | evaluation | training & consulting
Kranjčevićeva 35, 71000 Sarajevo
mobile: +387 61 215 997 | office: +387 33 556 865 | fax: +387 33 556 866
skype: stevepowe
Dear list members,
In sem, std.coef() will give me standardized coefficients from a sem model.
But is there a trick so that path.diagram can use these coefficients rather
than unstandardized ones?
Thanks
Steve Powell
From: John Fox
Date: Wed 28 Feb 2007 - 14:37:22 GMT
Dear Tim,
See
www.psih.org
-Original Message-
From: Frank E Harrell Jr [mailto:[EMAIL PROTECTED]
Sent: 17 September 2007 17:18
To: Steve Powell
Cc: [EMAIL PROTECTED]
Subject: Re: [R] Creating Hmisc labels inside a function
Steve Powell wrote:
>
> Thanks, Frank - it doesn't work though.
>
with
attributes, labels etc. So
assign(label(obj),"some label") #doesn't even work outside a function, at
the command prompt.
Any more ideas anyone?
Best wishes
Steve Powell
proMENTE social research
research | evaluation | training & consulting
Kranjčevićeva 35, 71000
t;)
I usually use the "assign" function to make assignments inside functions,
but assign will not work with attributes, labels etc.
Any ideas?
Thanks in advance
Steve Powell
proMENTE social research
research | evaluation | training & consulting
Kranjčevićeva 35, 71000 Sarajevo
mobil
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