Hi List,
I have start and end times of events
structure(list(start = c("15:00", "15:00", "15:00", "11:00",
"14:00", "14:00", "15:00", "12:00", "12:00", "12:00", "12:00",
"12:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00",
"12:00", "12:00"), end = c("16:00", "16:00", "16:00", "12:00",
Hi muting,
# your data
muting <- data.frame(col1 = c(1,1,2,1,2,1), col2=c(NA,1,2,1,2,NA))
# 1. finding rows with NA
is.na(muting)
# 2. counting the NAs per column
colSums(is.na(muting))
# 3. keeping only the ones without NAs
muting[,colSums(is.na(muting)) == 0]
Regards,
Stefan
schrieb muting, A
Hi List,
I can not get my head around the following problem. I want to fit a
quadratic function to some data and stumbled across poly(). What exactly
does it, i.e. why are there different results for fit1 and fit2?
x = seq(-10, 10)
y = x^2
fit1 = lm(y ~ x + I(x^2))
fit2 = lm(y ~ poly(x, 2))
t;] <- NA
Xavier
- Mail Original -
De: "Stefan Uhmann"
À: r-help@r-project.org
Envoyé: Mardi 29 Septembre 2009 13h15:10 GMT +01:00 Amsterdam / Berlin / Berne
/ Rome / Stockholm / Vienne
Objet: Re: [R] sort dates within a factor
Hi Xavier,
thank you for your suggestion, it'
nd(test, index = c(2,1,NA,3,NA,1,1,2,1))
# tapply does not treat NAs as intended
unlist(tapply(test$date, test$nr, function(x){order(x, decreasing = T)}))
Kind Regards,
Stefan
xavier.char...@free.fr schrieb, Am 29.09.2009 12:12:
Is this what you want?
test[order(test$nr, -as.integer(test$date)),
Dear List,
I have the following data:
>>
test <- data.frame(date =
as.Date(c('2007-01-01','2008-03-24','2003-03-02','2008-05-03','2002-05-23','2001-06-30','2005-12-04')),
nr = c(2000,2000,2000,2001,2002,2003,2003))
test
date nr
1 2007-01-01 2000
2 2008-03-24 2000
3 2003-03-02
il Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Tue, 15 Sep 2009, Stefan Uhmann wrote:
Dear List,
I have a problem wit
Dear List,
I have a problem with RODBC on a Paradox-DB, sqlQuery, and special
characters in table names. Unfortunately, some of the latter include the
underscore <_>. And I am not able to change them.
That's not a problem, when I quote the table name:
> sqlQuery(channel2, 'SELECT * FROM "anme
Just in case sb. has the same problem, using sqlQuery instead of
sqlFetch solved the problem for me with RODBC 1.3-0. Seems as the
implementation of sqlFetch does something bad to long table names - just
a guess.
Stefan
Stefan Uhmann schrieb, Am 14.08.2009 14:12:
Hi List,
I used to access
Hi List,
I used to access a Paradox database using RODBC, but since last week I
am not able anymore to fetch any table which has a name longer than 11
or 12 characters.
Here is the the pattern of my code, nothing spectacular:
library(RODBC)
channel2<-odbcDriverConnect('DSN=xxx')
#table names
Dear List,
why does this not work?
df <- data.frame(var1 = c(3,2,1), var2 = c(6,5,4), var3 = c(9,8,7),
fac = c('A', 'A', 'B'))
tapply(cbind(df$var1, df$var2, df$var3), df$fac, mean)
Thank you,
Stefan
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R-help@r-project.org mailing list
https
Dear list,
I want to move some files that should keep their time stamps, which is
not the case if I use file.copy in combination with file.remove.
file.move would be nice, is there a package providing such a function?
Regards,
Stefan
__
R-help@r-pr
Dear List,
I have this column/vector:
vec <- c("function", "missing", "string")
and want to compute a second column/vector:
- value if the pattern "unc" is found: 1
- value if the pattern "iss" is found: 2
- value if none of the patterns is found: 0
This should be the result:
> vec2
[1] 1 2 0
Dear List, Dear Jim,
is it possible to draw multiple polygons with different line types?
lty=c or line.lty=c do not work with radial.plot (in the matrix case) as
well as add=TRUE.
Stefan
Jim Lemon schrieb, Am 14.11.2008 10:38:
Jeremy Claisse wrote:
Is it possible to plot multiple polygons
Dear List,
I have two dataframes with overlapping colnames and want to merge them.
Actually, what I want is more similar to rbind, but the dataframes
differ in their columns. Here are the examples:
df1 <- data.frame(A = c(1,2), B = c("m","f"), C = c("at home", "away"))
df2 <- data.frame(A =
n the future.
Great, thank you again!
Stefan
Jim Lemon schrieb, Am 05.11.2008 11:53:
Stefan Uhmann wrote:
Dear list,
I have a multi(3)dimensional table, which is printed as two tables:
table.a
, , = female
not at all a little medium heavy
no 53 27 8 6
yes
Dear list,
I have a multi(3)dimensional table, which is printed as two tables:
> table.a
, , = female
not at all a little medium heavy
no 53 27 8 6
yes 30 67 6166
, , = male
not at all a little medium heavy
no 31
Dear list,
are there any (late) sugestions on this issue? I'm trying to produce a
bad example for my students and I am not able to produce it using R!
Would not have been a problem with SPSS. Mighty R ..
Regards,
Stefan
Arthur Roberts schrieb, Am 29.07.2008 06:23:
Hi, all,
I need to show o
Dear list,
slightly OT: can you recommend me any sources where I can find more
about this Type I - II - III anova problem? It seems as my statistics
courses did not cover this issue, so I feel rather naive and have this
sort of feeling that some of my analyses might be complete nonsense.
Reg
hadley wickham schrieb:
Hi Stefan,
Could you be a bit more explicit? Do you have an example dataset that
you are trying to visualise?
Right, thanks for pointing out the obvious.
So here's my code:
>>
library(gplots)
quarter <- as.factor(sample(c("Q1", "Q2", "Q3", "Q4"),
100, repla
Hi,
anybody any hints how to get a barplot with both juxtaposed and stacked
bars?
/Stefan
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
an
Jim Lemon schrieb:
On Wed, 2008-08-20 at 13:36 +0200, Stefan Uhmann wrote:
Dear R-Helpers,
I need the centroid of circular data and (because the function used does
not provide the centroid coordinates, or did I miss sth.?) tried it via
the indirect way and just computed the cartesian
Dear R-Helpers,
I need the centroid of circular data and (because the function used does
not provide the centroid coordinates, or did I miss sth.?) tried it via
the indirect way and just computed the cartesian coordinates:
>>>
library(plotrix)
library(maps)
#generate data
data1<-matrix(c(1.8
Dear HelpeRs,
i have a data.frame df as follows:
>
df <- data.frame(id=rep(1:3,rep(10,3)),
emoqu=as.factor(rep(c(0,0,1,1,2,2,3,3,4,4),3)),
x=rnorm(30), y=runif(30))
Now, I would like to rearrange the data and it works - regarding the
variables/columns I would l
iostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
- Original Message ----- From: "Stefan Uhmann"
<[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, May 15, 2008 10:07 AM
Subject: [R] Function for subset of cases/lines
Hi,
I have a vector:
q1<-c(4660,562
Hi,
I have a vector:
q1<-c(4660,5621,5629,8030,8080,8180,8501,8190,8370,8200)
The following command gives me the mean of its elements:
mean(q1)
[1] 7346.1
What can I do to do the same for the variable 'height', but only for the
cases/rows which have one of the elements of q1 as 'number':
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