Hi:
Apologies for asking the following question. As this may sound very basic and
stupid for this forum , I honestly do not know how to solve it and I do not
have a teacher who can help me understand.
I have list of genes (200) that are involved in a particular process and I call
this as a Pr
Hi:
sorry for asking simple question (not simple for me though).
I have a data frame something like this:
ExpName Identifier value
MM1-x1 GSK 0.02
MM1-x1 GSK2 0.001
MM1-x1 GSK3 0.04
MM1-x1 GSK4 0.1
MM1-X2 GSK 0.4
MM1-X2 GSK2 0.1
MM1-X2 GSK4 0.002
MMX-X3 GSK 0.4
MMX-X3 GSK2 0.23
I am
Thank you. that was very easy.
-srini
--- On Thu, 8/11/11, R. Michael Weylandt wrote:
From: R. Michael Weylandt
Subject: Re: [R] help with loops
To: "Srinivas Iyyer"
Cc: r-help@r-project.org
Date: Thursday, August 11, 2011, 12:49 PM
unlist()
Michael Weylandt
On Thu, Aug 11, 201
hi I need help with list object.
I have a list object
> a <- c('apple','orange','grape')
> b <- c('car','truck','jeep')
> c <- list(a,b)
> names(c) <- c('fruit','vehicle')
> c
$fruit
[1] "apple" "orange" "grape"
$vehicle
[1] "car" "truck" "jeep"
I want to write all the elements of this l
October 23, 2008, 8:41 PM
> ?aggregate
>
> x1 x2
> 1 a 4
> 2 b 3
> 3 c 2
> 4 a 1
> 5 c 2
> 6 f 3
> 7 g 4
> 8 f 5
> > aggregate(x$x2, list(x$x1), max)
> Group.1 x
> 1 a 4
> 2 b 3
> 3 c 2
> 4 f 5
Hi group,
How can I identify an element with max value among duplicated elements all in a
data frame
Example:
> x1
x1 x2
1 a 4
2 b 3
3 c 2
4 a 1
5 c 2
6 f 3
7 g 4
8 f 5
I want to be able to get a data frame with all unique(x1) with max value
x1 x2
1 a 4
2 b 3
3 c 2
dear group,
i have a data matrix with some replicate items with different values. I want to
extract the row with max value.
for example:
> x
fruit weight
1 apple1.3
2 apple1.5
3 apple1.6
4 orange1.4
5 orange1.6
x is a data frame.
I want to extract unique items from
Dear group,
I have 3 different data frames. I want to merge all 3
data frames for which there is intersection.
Say DF 1 and DF2 has 100 common elements in Column 1.
DF3 does not have many intersection either with DF1 or
with DF2.
For names in column 1 not present in DF3 I want to
introduce NA
Dear group,
I have a dataframe (x). (4 rows, 3 columns for
example)
I want to create a master list (my_list) from data
frame.
I want each row of x to be a list.
I tried 3 different ways: writing a loop, using apply,
and going through each row.
Going through each row works for me. since I hav
Hi I have the smililar question.
I have a list:
my_list <- list(name="Fred", wife="Mary",
no.children=3, child.ages=c(4,7,9))
> my_list
$name
[1] "Fred"
$wife
[1] "Mary"
$no.children
[1] 3
$child.ages
[1] 4 7 9
Now I want to search "Fred" and get attribute of that
value which is 'name'.
NAs.
Thanks
Srini
--- Henrique Dallazuanna <[EMAIL PROTECTED]> wrote:
> Perhaps in this case:
>
> noquote(with(xx, tapply(NES, list(Class, Name),
> paste)))
>
>
> On 12/03/2008, Srinivas Iyyer
> <[EMAIL PROTECTED]> wrote:
> > Dear Group,
> > I
Dear Group,
I have a data frame like the following:
x <- c("Mike","A",0.01)
x1 <- c("Carl","A",0.2)
x2 <- c("Gene","C",0.3)
x3 <- c("James","A",-0.3)
x4 <- c("Dough","B",0)
xx <- rbind(x,x1,x2,x3,x4)
colnames(xx)<-c("Name","Class","NES")
xx <-as.data.frame(xx)
> xx
Name Class NES
x Mike
srini
--- Henrique Dallazuanna <[EMAIL PROTECTED]> wrote:
> Try this:
>
> d1 <- data.frame(d1)
> d1$V3 <- as.numeric(as.character(d1$V3))
> xtabs(V3 ~ r1+c1, data=d1)
>
> You can substitute 0 with NA:
>
> d1.tb <- xtabs(V3 ~ r1+c1, data=d1)
> d1.tb[d1.tb==0] &l
Dear group,
I have a data.frame (d1) with various elements and a
matrix (m1) created with NA (or 1s). I want to read
each row,column in d1 and fill its numeric value in
m1.
Could some one help me because I have 130K rows and
500 column data.frame object and I was told that a for
loop will take a
hello:
I am very confused when it comes to list operations in
R.
I seek help in the following problem.
I have two different vectors
myIDs - a character vector with no names to their
elements
x2 - another character vector derived from unlisting a
list where an element has both a name and value
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