y=1-x
Regards,
Sergiy
On Mon, 19 May 2025, 16:44 Rui Barradas, wrote:
> Hello,
>
> And a test for equality of all solutions so far.
>
>
> do.call(
>identical,
>list(
> 1L - x,
> +!x,
> as.integer(!x),
> as.integer(xor(x, 1L))
>)
> )
> #> [1] TRUE
>
>
> Hope this h
>From a practitioner perspective. Parametric methods have more power. If
assumptions are here - use formulas. On the other hand my usual
recommendation to colleagues: "If you don't know what to do - use
bootstrap."
Regards,
Sergiy
On Mon, 5 May 2025, 17:06 Gregg Powell via R-help,
wrote:
> Hi K
I suspect it might be relevant for RStudio, but definitely not for pure R.
On top of that you can just copy R to a flash drive or any accessible
folder. It will work.
Regards,
Sergiy
On Fri, 13 Dec 2024, 15:56 Bert Gunter, wrote:
> Thanks, Ivan. Exactly my reaction.
>
> And as a Turing complete
Hi All,
Just noticed that R returns results for non-existent name if you have
another variable with the same beginning when you subset with $.
See the code below:
name_0 <- "ID"
name_1 <- "name"
name_2 <- "name1"
v0 <- 1:200
v1 <- c(rep(0,100), rep(1,100))
v2 <- c(rep(0,50), rep(1,150))
df <- as
mstring1 <- c("123456789012345678901234567890123456789012345678901234567890
123456789012345678901234567890123456789012345678901234567890")
mstring2 <- c("123456789012345678901234567890123456789012345678901234567890
1234567890123456789012345678901234567890123456789012345678901234567890")
vec.in <
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