On 04/12/2012 09:11 PM, David Winsemius wrote:
On Apr 12, 2012, at 3:49 PM, Aye wrote:
Okay, i got this far:
f <- function(x) 0.25*x^2 + 6.47*x -32.6
g <- function(x) 0.99*x^2 -6*x -195
h <- function(x) 0.77*x^2 +14*x -495
j <- function(x) 0.001*x^2 + 65*x -785
k <- function(x) 0.9*x^2 -2*x -6
On 01/27/2012 07:40 AM, uday wrote:
I have some satellite data which contains latitude and longitude information
.
> From this data I would like to calculate distance between first location
(scalar latitude and longitude) and all other (vectors latitude and
longitude)
How I should solve this pr
On Mon, 2010-06-28 at 10:48 -0400, Robert Baer wrote:
> y=rnorm(100)
> x=abs(y)
> plot(x, y, axes=FALSE)
> axis(1, pos=0)
> axis(2)
> box()
It's nice to know that R tends to make nice graphics by default. But you
can have R do not so great graphics (like Excel and other programs that
make really
On Mon, 2009-05-11 at 12:36 -0700, Anyuan Guo wrote:
> Dear all,
> I have P value of a list of markers. Now I need the chi square value
> with degrees of freedom 2.
> I noticed there are several Chisquare functions (dchisq, pchisq,
> qchisq, and rchisq), but it seems all are not for my pu
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