riate model and then
using Anova() from the car package.
-Paul
On Tue, Mar 3, 2009 at 5:37 PM, Paul Gribble wrote:
> Have a look at
>>
>> http://cran.r-project.org/doc/Rnews/Rnews_2007-2.pdf
>>
>
> Wow. I think my students would keel over.
>
>
> Anova() from
>
> Have a look at
>
> http://cran.r-project.org/doc/Rnews/Rnews_2007-2.pdf
>
Wow. I think my students would keel over.
Anova() from the car package looks promising - I will check it out. Thanks
On Tue, Mar 3, 2009 at 4:00 PM, Peter Dalgaard wrote:
> Paul Gribble wr
I have 3 questions (below).
Background: I am teaching an introductory statistics course in which we are
covering (among other things) repeated measures anova. This time around
teaching it, we are using R for all of our computations. We are starting by
covering the univariate approach to repeated m
esting test.
>
> --
> Gregory (Greg) L. Snow Ph.D.
> Statistical Data Center
> Intermountain Healthcare
> greg.s...@imail.org
> 801.408.8111
>
>
> > -Original Message-
> > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> > pro
I wonder if someone could explain the behavior of the anova() and lm()
functions in the following situation:
I have a standard 3x2 factorial design, factorA has 3 levels, factorB has 2
levels, they are fully crossed. I have a dependent variable DV.
Of course I can do the following to get the usua
5 matches
Mail list logo