I don't know if this is the correct forum to ask the following question;
however, when I search the aroma.affymetrix discussion group, it suggested
that I should posted the question to r-help. Here it goes.
I followed the instructions on aroma.affymetrix trying to install the
packages; followi
Hi Rthoughts,
Don't be discouraged I'm learning R on/off for classes and when I was
under pressure to get work done, learning R likes pulling my hair (and
teeth) off of frustration. But, this forum is great; I got so much help
from this forum.
I use R on windows as well. After install R, i
Try:
X<- read.csv ("") or
Y<- read.delim("", sep=",", header=T)
Example, if your file is in C-directory, file name is my_file, and the file
has a header.
X<- read.csv("c:\\my_file") or
Y<- read.delim("c:\\my_file", sep=",", header=T)
My D. Coyne
-Original Message-
From: [EMAIL PROTEC
R-newbie question
I have 2 matrices
(a) P1 has only one column of 32K rows
(b) PC has 2 column {P, C} of 3200 rows
Every values in P1 matches with a value in PC[,p] (column p). I would like
to use Which to search for all value in P1 that matchex PC[,p] and get the
PC[,c]. However
Hi,
I place a t.test in a loop and would like to continue to process the loop
even when t.test encounter error. How do I do that?For example, in one
iteration, the data is completely constant and t.test gives error, the
entire program terminates. I would like to write the information out to
I would like to replace all null ("") in a column of a matrix to NA, how
would I do that without a do loop?
Thanks
--mc
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Is there a way to perform a dynamic SQL query in R, using RMySQL? Thanks
My D. Coyne
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PLEASE do read the posting
I'm running samr (Two class unpaired), but keep getting the following error:
perm= 1
Error in if (logged2) { : argument is of length zero
library (impute)
library (samr)
data = list (x=dat, y=y, geneid = matrix(twoUnpaired.data[,1],ncol=1),
genenames = matrix(twoUnpaired.data[,2], ncol=1))
Hello,
I have a data frame and would like to convert it into a matrix, how do I do
that?
Thanks
--My Coyne
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got
"Chi-squared approximation may be incorrect"
is because probably there are less than 5 observations in
the cell. Maybe will help to
try fisher.test()
Cheers
Anna
- Messaggio originale -----
Da: My Coyne <[EMAIL PROTECTED]>
A: [EMAIL PROTECTED]
Inviato: Lunedì 14
new.mat <- mat[ , colSums( mat==0 ) == 0, drop=FALSE ]
This works great. I'm learning this R slowly... It is quite powerful.
Thanks
-Original Message-
From: Charles C. Berry [mailto:[EMAIL PROTECTED]
Sent: Tuesday, January 15, 2008 3:47 PM
To: My Coyne
Cc: [EMAIL P
PM
To: My Coyne
Cc: [EMAIL PROTECTED]
Subject: Re: [R] Newbie Question -- Remove entire column in a matrix
On Tue, 15 Jan 2008, My Coyne wrote:
>
>
> I'm ordering "The R Book" and hope to learn a lot more about R. In a
> meantime, I have a matrix of digits and I w
, I think the
R-experts have more tricks to do such a 'simple' thing.
Many thanks in advance.
--My Coyne
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P
Hello,
I received the following warning when running chi-square;
n Is there a way to catch the 'error' code of 'warning' after run
chisq.test(x)?
n What does this error mean?
Thank you for your help.
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of the test.
chisq.test(x)$statistic will give you the x-squared result, if you only
want the number chisq.test(x)$statistic[[1]] can retrieve the numeric
value. So you can simply write a loop to do the test and save the
results in some matrix.
I hope it helps
Jingru Dai
My Coyne wrote
Hello,
I would like to run a series of chisq.test() and store results (x-square,
df, p-value) in a matrix for further analysis, but don't know how to do
such. Currently I run the command line for each set of data at a time and
it is time consuming.
Thank you for your help.
--My
Hello,
Newbie question and hope you can help .
I have two vector V1 and V2, where length(V2) = length of (V1) * 2;
length(V1) ~ 16,000.
For each member in V1, I need to compare 2 element of V2 for equality
i.e.
for (I in 1:length (V1)) {
if ( v2[i] == v1[i] & v2[i+1]==v1[i] ){
Hi All,
I'm new with R; this is a basic question. I was given a matrix I of (nrow,
ncol), I would like to create another matrix A with some data in the matrix
I, say [1,4] (row 1, column 4) to [271,19000] (row 271, column 19000). How
do I do this? Please help. Thank you very much.
--mc
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