Hi John,
The package lubridate is the easiest way to deal with dates.
library(lubridate)
frame$groupByWeekNumber <- wday(frame$dt) - 1 # Sun=1, Sat=7
On Mon, Jul 7, 2014 at 11:54 PM, John McKown
wrote:
> I have a column, dt, in a data.frame. It is a list of POSIXct objects.
> I could us
Hi Andrea,
A "cleaner" alternative to Jim's suggestion is something like
a.df <- as.data.frame(a)
group1 <- (a.df$col1 == 1) & apply(a.df[,c("col2","col3","col4")], 2,
function(x) any(x == 1 | is.na(x)))
group2 <- (a.df$col1 == 1) & apply(a.df[,c("col2","col3","col4")], 1,
function(x) all(x ==
Hi Martin,
See ?cor.test
example(cor.test)
Regards,
- Jon
On Mon, Feb 25, 2013 at 5:06 AM, Martin Batholdy
wrote:
> Hi,
>
> is there a predefined function that computes the p- or t-value
> based on a correlation coefficient and its sample size?
>
>
> thanks!
>
> ___
Hi Fabio,
I cannot reproduce it but this is probably some env var not set, or
some problem with the path to your R installation having whitespace in
it.
See ?.libPaths, if it is empty you might want to hard-code R_HOME somewhere.
Regards,
On Thu, Feb 14, 2013 at 10:58 PM, Fabio Veronesi wrote:
Hi Dominik,
You can try
x <- 5
plot(rnorm(50), main=bquote(.(x) * mu * g/m^3 * " substance"))
Regards,
- Jon
On Thu, Aug 16, 2012 at 3:37 PM, Dominik Refardt
wrote:
> Hello
>
> This is a problem I encountered repeatedly and I found no answer that made
> me really happy. I hope it is not too t
On Thu, Jun 28, 2012 at 8:47 PM, James Holland wrote:
> With the multiple if statements I need to check for, I though for statements
> with the if/else if conditional statement was better than nested ifelse
> functions.
for () gives you a lot of flexibility at the expense of being verbose
& slow,
Hi James,
On Thu, Jun 28, 2012 at 12:33 AM, James Holland wrote:
> I need to look through a dataset with two factor variables, and depending
> on certain criteria, create a new variable containing the data from one of
> those other variables.
>
> The problem is, R keeps making my new variable an
Hi Kat,
On Thu, Jun 28, 2012 at 8:22 AM, kat_the_great wrote:
> Dear R Users:
>
> I'm a STATA user converting to R, and I'd like to be to do the following.
> #Assign var_1 and var_2 a value
> 10->var1
> 20->var2
>
> #Now I'd like to print the values of var_1 and var_2 by looping through
> var_1 a
Hi Walt,
as.Date("01OCT1928", "%d%b%Y") works for me. See also ?strftime
Regards,
Jon
On Tue, Jun 19, 2012 at 8:00 PM, Data Analytics Corp.
wrote:
> Hi,
>
> I imported an excel table (using read.csv) of Dow Jones monthly average
> closings where the first variable is a date as a character str
Hi Lucia,
On Mon, Jun 18, 2012 at 6:11 PM, lucinka wrote:
> Hello,
>
> I got this matrix of gentic distances between my samples. it is 85x85 but
> only lower half (without diagonal) contains my distances. How can I make a
> mean and standard deviation on these distances, please ?
You can try so
Hi Al, Michael,
On Sat, Jun 16, 2012 at 11:01 AM, R. Michael Weylandt
wrote:
> On Fri, Jun 15, 2012 at 6:56 AM, Al Ehan wrote:
>> Hi,
>>
>> I would like to make a replication of 10 of a linear, first order
>> Autoregressive function, with respect to the replication of its innovation,
>> e. for e
Hi Ken, Stef,
We can make your script more elegant like below:
On Sun, Jun 17, 2012 at 12:52 AM, Ken wrote:
>
> stef salvez googlemail.com> writes:
[snip]
> #load library
> library(plyr)
>
> # utility function
> mean.var = function(df, var){ mean(df[[var]], na.rm = T)};
>
> # create example
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