Yes, I just wanted to decrease the STARTING point size!
Sorry for not being able to formulate
Thank you very much, Rui and Avi!
That's all for now. I need to comprehend information.
Medic
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№1 Medic:
The code works as I want, but the points (circles) on the plot are too
big. How to decrease them? Where to insert (for instance) size = 0.8
for points (circles) on plot?
p1 <- p + geom_point(aes(size = Stage), alpha = 1/3) + xlab ("X") +
ylab("Y") + geom_smooth()
The code works as I want, but the points (circles) on the plot are too
big. How to decrease them? Where to insert (for instance) size = 0.8
for points (circles) on plot?
p1 <- p + geom_point(aes(size = Stage), alpha = 1/3) + xlab ("X") +
ylab("Y") + geom_smooth()
Stage is factor, x and y - continuo
The code works as I want, but the points are too big. How to decrease
them? (Where to insert: size = 0.8?)
p1 <- p + geom_point(aes(size = Stage), alpha = 1/3) + xlab ("X") +
ylab("Y") + geom_smooth()
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Many Thanks!!!
> cpolw...@chemo.org.uk:
> Your X axis is plotting mydata not date?
> Use aes(x=date
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I took a SAMPLE CODE (for Connected scatterplot) from the R gallery
and applied to MY DATA, but got:
"Don't know how to automatically pick scale for object ..."
P.S. 1) R ver. 4.0 (Yes, Jeff); 2) Attached: mydata_dput (1 КБ)
SAMPLE CODE
library(ggplot2)
library(dplyr)
library(hrbrthemes)
data <-
I took a SAMPLE CODE (for Connected scatterplot) from the R gallery
and applied to MY DATA, but got:
"Error in as.Date.numeric(mydata$date) : 'origin' must be supplied".
P.S. I can not understand ?as.Date()
SAMPLE CODE
library(ggplot2)
library(dplyr)
library(hrbrthemes)
data <-
read.table("https:
cpolwart wrote:
> the event can only happen once
>
1. Yes, I'm not interested in repeat events.
2. I just had an interest in learning the code for survival analysis
in case there are: event, left censored (not left truncating) and
right censored, nothing more! But I no longer want to burden anyone
Very grateful for the all comments!
My data contains:
• left censored
• right censored
• events
(interval censored does not contain!)
(P.S. I understood, that the code with "type = 'left'" is not
suitable, because is ONLY for left-censored.)
I wanted to get the appropriate code for my so mix dat
On 2020-04-17 20:06, Medic wrote:
> I can't understand how to do a survival analysis (?Surv ()) when some
> event occurred before the start of observation (left censored). If I
> understand correctly, there are two methods. I chose a method with: 1)
> time from the start of treat
I can't understand how to do a survival analysis (?Surv ()) when some
event occurred before the start of observation (left censored). If I
understand correctly, there are two methods. I chose a method with: 1)
time from the start of treatment to the event and 2) the indicator of
the event. I did (i
Dear Burt, you gave a very elegant solution. Many thanks!
Jeff, I understand your solution, thank you very much for your time!
Colleague Milos, patronage is exactly what I need. I hope for your
further guidance! (Rcmdr is not enough for some purposes.)
Dear Ivan, I used your solution! It's the most
I have
mydata$var
#this is ONE group of patients
And I would like to get
median and ICR of mydata$var.
How can I get this?
With summary (mydata$var)!
Ok!
And now I would like to get THE SAME, but for TWO group: male and
female (which are contained in the group mydata$var)
How can I get this?
F
I have
mydata$var
and I have
mydata$group #two group
I would like to split
mydata$var
by
mydata$group #to get var1 and var2
And then get
summary (var1, var2) #this is my finite aim
How to encode it all?
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rt
Thank you, Jim, you always come to the rescue!
Jim Lemon
mydata$Temperature[sample(1:N,N)
should do the trick. You will just get a pseudo-randomly shuffled set
of the same values.
Jim
Medic wrote:
> > Variable temperature:
> > mydata$temperature
> > has N value
Variable temperature:
mydata$temperature
has N values.
With what code to сhoice (without return) n values from them RANDOMLY?
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Thank you very much!
> From: Michael Hannon
> ... following might be useful in this case:
> https://stat.ethz.ch/mailman/listinfo/r-sig-geo
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Creating map in R. I have all the files (with different extensions)
for the country I need. The problem is that I don’t know how to use
them in R. I began according to information on the Internet, and
immediately ran into difficulties (see below):
`library("tmaptools")
geo <- read_shape("Rom.shp",
Help me. pls, to read .shp file.
`library("tmaptools")
geo <- read_shape("Rom.shp", as.sf = TRUE)
This function is deprecated and has been migrated to
github.com/mtennekes/oldtmaptools`
I have to turn to another function, but I get an unclear message
`library(raster)
geo <- shapefile ("Rus.shp")
Hi, Sarah,
Thank you not just for the answer, but for the teaching (!) answer!
Yes, cex.labels is what I need!
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Point me, please, the parameter for changing the font size for the
variable name in pairs.panels ()
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For David Winsemius.
As always, You help out! Immensely grateful!
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The Y scale is divided (by default) as:
0.0 ... 0.2 ... 0.4 ... 0.6 ... 0.8 ...1.0
But I would like so:
0 ... 20 ... 40 ... 60 ... 80... 100
(with rotating axis labels)
When I use par function (marked as comment here) it turns out
correctly for ONLY ONE picture?! Help me, please. (This is the code
in your plot() statement (see ?par for
> > > details), and then use axis() to make anything you'd like (see ?axis
> > > for details).
> > --
> > >> Medic wrote:
> > >> In this code:
> > >> plot (cox, col
Thanks, but too hard for me
Sarah Goslee :
> You can presumably use xaxt="n" in your plot() statement (see ?par for
> details), and then use axis() to make anything you'd like (see ?axis
> for details).
------
>> Medic wrote:
>>
In this code:
plot (cox, col=1:2, xscale=1, xlab="OS", ylab="Probability")
the X scale is divided (by default) as:
0 ... 50 ... 100 ... 150 ... 200
And I would like so:
0 ... 12 ... 24 ... 36 ... 48.
I looked ?plot(cox), but did not understand what argument is
responsible for this.
Pls, he
Bert Gunter:
"Have you consulted ?plot.survfit ? "
Marc Schwartz
"The 'mark.time' argument for plot.survfit() is FALSE by default."
Great thanks, Bert, for explanation in which documentation to view information!
Thank you very much, Marc!
Yes, specification required:
plot (km, mark.time=TRUE)
for
According to the guidelines (if I'm not mistaken), the code below is
sufficient (without any specification) to give Kaplan-Meier curves with
censored data markings on Kaplan-Meier curves. But in my case censored data
don't appears on the curves?!
library(survival)
mydata<-read.csv (file="C:/mydata
Dear David,
you are (as always) come to the rescue!
With your wonderful pedagogical talent of explanation!
Many thanks for the support!
My warmest and sincere wishes for the new year!
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h
How to note (in code) a few (!) adjusting covariates for cox
regression. I had an example for one covariate, and tried (according
to my own understanding) two variantes of code (pls, see below), and
got ... a different p-value. What is the right code? Many thanks!!!
(1)
survdiff (Surv(survt,statu
1. Dear John, thank you for the important point!
2. Dear Duncan, thank you for the clear clarification!
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automatically)
2) installing all packages only in RStudio (R will take them automatically)
3) installing all packages in R and in RStudio (i.e. in each of them)
Thanks, Medic
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> install.packages("survival")
package ‘survival’ successfully unpacked and MD5 sums checked
> library(survival)
Error: package or namespace load failed for ‘survival’ in get(Info[i,
1], envir = env):
lazy-load database 'C:/Program
Files/R/R-3.5.1/library/lattice/R/lattice.rdb' is corrupt
In addit
Rui Barradas,
thank you for your prompt response, your code will be useful to me in
the future!
Rick Bilonick ("your data appear to be categorical"),
thank you very much for your comment (I would have to more correctly
express my task).
JIM Lemon,
THANKS!!! THIS IS EXACTLY what I needed!
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What would be the correct code (simplest version) (without gplot())
for histogram (with 7 bars), which would include 7 names of bars under
the X-axis. The data are:
name number
ds6277
lk 24375
ax46049
dd70656
az216544
df 220620
gh641827
(I'm attaching mydata.r, making
I need a R-code for a situation that is well described in the sas help. I
would be very grateful for the help!
"Time-dependent variables can be used to model the effects of subjects
transferring from one treatment group to another. One example of the need
for such strategies is the Stanford heart t
When I run the code from the book Kleinbaum "Survival analysis" (7. Running an
extended cox model. Page 646) I got an ERROR. What do you think is the reason?
I attach a file with few lines of dataset "addicts-dput.r".
> library(cmprsk)
> addicts = read.csv ("addicts.csv")
id clinic status su
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