, to create a line chart, with the years (Y10_11, etc.) in
the X-axis and the Categorie in the Y-axis. The lines should be created with
the numbers for each categorie. So in each plot there should be 6 lines in
dependence of the value for each year.
Thank you.
Best regards.
Mat
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3 4700
4 3500
5 3800
Thanks.
Best regards. Mat
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hello togehter,
i have a little problem, i have frames like this two:
Cat Hours
A101 15
B103 10
Cat Hours
A103 16
B106 11
I need to convert this 2 data.frames into the following equal structure:
Cat Hours
A101
B
works perfect, thank you :-)
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w can
i do this?
The solution look like this one:
1
A Marius Muller -
B Rockwood
C Microlog Services
D Firefox Services
Thank you.
Best regards. Mat.
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df2$ID"?
My solution should like this one, that i can convert into a data.frame
ID 1 2 3 4 5
110 10 20 30 40 50
211 0 0 60 70 0
312 0 0 0 80 0
Thank you
Mat
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Hello togehter,
i have a litte problem. I have an output data.frame which look like this
one:
ID
1 10
2 11
3 12
Now I have another data.frame with more than one line for each ID:
IDGroupValue
1 10110
2 10220
3 103
Thanks for the help.
problem is solved. :-)
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ne:
IDONE TWO THREEMAX
1 2 57 7
2 6 NA NA 6
3 5 7NA 7
4 1 NA NA 1
how can i do this?
thank you. Mat
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thanks for the help up to here.
A little problem remains.
I have different "ABNR", if i try it with another ABNR, the Column extend
for each ABNR, it should start with "FIRST" again.
dat1 <- read.table(text="FS_ID ABNR
932733688812
11391 33688812
11392 33688812
11388 33688812
11390 3368
e
row. The earlier date value should stand under "FIRST", the newer date under
"SECOND".
Maybe anyone can help me, how i can do this.
Best regards. Mat
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Sen
thanks a lot, works perfectly
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Hello together,
i have a little problem, to create a new column, in a data.frame.
I know i can calculate one column with as a example 2 like this:
ORDER$WEIGHT <- ORDER$VALUE * 2
But how can i create the ORDER$WEIGHT with different numbers, like this one.
I have a data.frame like this one:
ORDE
thanks together,
out1 <- out[(out$No %in% no.ind),]
works perfectly :-)
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ee
i tried it like this one:
out1<-out[(out$No==no.ind),]
in no.ind i have the 2 numbers: c("2","3")
but this doesn't work.
Maybe anyone can help me.
Thank you.
Mat
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-10-0415
32013-10-0110
the result should be this one:
IDName First SecondThird
1 Andy10 15
2 John 7 10 15
3 Amy 10
maybe you can help me, to do this?
Thank you.
Mat
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80.58285
5 2013-02 1013.72028
6 2013-03 939.63030
7 2013-04 977.17073
8 2013-050.0
9 2013-060.0
10 2013-07 1047.56938
11 2013-08 225.44031
12 2013-09 667.91489
13 2013-100.0
i converted this data.frame with plotbase<-t(plotbas
thanks. Works perfectly
you made my day :-)
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Thanks first.
that doesn't look bad. But if have a equal ID in dat2, the days are no
longer correct.
the correct data.frame has to look like this one:
ID Name Management Training
1 1 Jack 13
2 2 John 10
3 3 Jill 04
not this one:
ID Name
regards. Mat
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if i can sort my list as follows, i can create the bar chart.
But how can i sort my list from:
[,1] [,2] [,3]
[,4]
abnr2 11425 11425 11555 11888
TIME 21 1
. So the value of one column
has to have a own color in dependence of the "Cat".
Perhabs anyone have an idea?
Thanks.
Mat
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49396 1140
B49396 15013
perhabs anyone can help me.
Thank you
Mat
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thank you, this code works:
library(plyr)
join(dat1,dat2,by=c("cu.nr.","name"),type="right")
but my dat2 frame has a lot of columns, which i don't want to match.
How can i say, that only the column "value" should be match to dat1 ?
Thank you.
Mat
Value
A 33 Evo
B 1 Mer 80
C 1 Pold
thanks.
Mat
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t very productive
Thanks.
Mat
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i found a way :-)
data<-merge(data,project,by.x="PJ_ID",by.y="PROJ_ID",all.x=TRUE)
perhaps this can help someone
Mat
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;,sep=""),
"Orders",sep="/"),"txt",sep=".")
write.xls( Orders,pfad,colNames = TRUE,sheet = 1,from = 1,rowNames = FALSE )
if(dim(CO.PHB)[1]>0){
write.table( CO.PHB,pfad,row.names=FALSE,sep=" | ")
}}
how should my code look like, if i want onl
can i do this.
Thanks.
Mat
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111 final2013-01-12
is there any way to filter my data.frame to the latest data, perhabs "max"?
Thanks.
Mat
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s one.
I have: Mercedes_02352
Audi_03555
and now i want to filter this data.frame to
235
355
can you help me?
Thanks.
Mat
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.
1 2 3
1st round 1:22:30:0
2nd round 2:2 1:01:1
can you help me?
Thanks.
Mat
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thx, that worked perfekt, but is there any way to convert my Number 1 row
# 123
up as column description?
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thx, works perfectly :-)
Mat
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e:
1 2
A Albert1800
B Jack2000
C Mike 2200
How can i eliminate this double entries?
Thanks.
Mat?
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want a new data.frame, who show me only the newest entries according
to the No.
The solution look like this one:
No. Datelast change
1 1 2012-11-05 final
2 2 2013-01-17 final
can anyone help me?
thanks.
Mat
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thx, works perfektly :-)
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Hello together,
i want to round some numbers in my data.frame.
How can i round a number to values like 0.5; 1.0; 1.5; 2.0; etc.
It should look like this one
before
2.2 ; 2.3; 2.26; 1.11
after
2.0; 2.5; 2.5; 1.0
thanks.
Mat
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works perfectly. Thank you :-)
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Hallo together,
i have a data.frame like this one.
A
13
2-2
31
and now i want to convert the negative number to 0.
A
13
20
31
How can i do this?
Thanks.
Mat
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Thank you all, a few ideas worked perfectly for me.
I take "with(dat1,aggregate(B,by=list(A=A),length))" for my task.
Have a nice day.
Mat
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1
How can i do this?
Thank you.
Mat
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i tried it this way. With this Code the Row "Difference" gets complete green.
But i want the color change to red according to a different value.
highlight_other<-out.ex1[(out.ex1$AUFTR_NAME=="Difference"),]$LFD2
zellen_other<-paste(paste("A",highlight_other,sep=""),paste("S",highlight_other,sep=""
generated from the data above and is ok.
The Excel sheet was generated every day. And the numbers can change from day
to day.
I know how to color the whole row, but i don't know how to color the number
"Difference --> 1,15" according to her value, like: if>1,2 <- RED, if <
i tried it this way, but this won't help.
O3R <- sh$PT_IST(zellen_other)
O3RF <- O3R$Font()
O3RF[["Bold"]] <- TRUE
O3RF[["Size"]] <- "10"
O3RF[["Color"]] <-"5287936"
perhabs you can help me, how i can differenz between the val
quot; ?
I know how to colour a complete row, like this task:
U3R <- sh$Range(zellen_blue)
U3RF <- U3R$Font()
U3RF[["Bold"]] <- TRUE
U3RF[["Size"]] <- "10"
U3RF[["Color"]] <-"-10526881"
but how can i color numbers accordung to her v
gsub() works perfectly, thank you very much.
Mat
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Numbers in my vector.
this one doens't work:
data_export_final<-data_export[(data_export$KD_NR==Top10),]
Thank you.
Mat
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our help.
Mat
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] 130
But how can i get this result under my column for the Excel Export?
Now my Excel Export looks like this one.
PT_PROG
23
100
7
and now i want under this digets the sum of this column (130)?
Thanks for your help.
Mat
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Ok, I can replicate your problem, with following code:
dat <- 1:10
barplot(dat, beside=TRUE,ylim=c(0,100));
par()$usr;
par(new=T);
plot(dat, ylim=c(0,100), type="l");
par()$usr;
So it looks like even if you specify yourself ylim, the resulting
effective ylim (usr[3:4] ) will be d
Barry, thanks a lot for checking for this!! Find below answers.
Le 13. 04. 11 18:26, Barry Rowlingson a écrit :
2011/4/13 Matthieu Stigler:
Jim
Thanks for your feedback! The problem is that the people "those responsible
for layout" are us... We are doing the book in Latex, and till now did not
Le 24. 01. 11 20:43, Duncan Murdoch a écrit :
On 11-01-24 12:07 PM, Matthieu Stigler wrote:
hi
I am seeing a strange behavior I can't understand... doing:
> source("/tmp/RFile.r",echo=TRUE)
Error in rep.int(c(prompt.echo, continue.echo), c(leading,
length(dep) - :
invalid 'times' value
indeed this makes the trick! quite strange... is this a known bug/issue?
thanks!
Matthieu
Le 24. 01. 11 19:48, William Dunlap a écrit :
Put a space after the # in the line
#line 516
to avoid the problem. A similar problem also
appears in parse().
> parse(text="#line 102\nlog(pi)\n")
E
Hi
Well this is the output of str(dep) on a small example:
str(dep)
chr [1:8] "###" ...
Browse[1]> dep
[1] "###"
[2] "### chunk number 1:"
[3] "###"
[4]
Ajay
Please avoid cross-posting on two lists. Continue this thread only on
thes-ig-debian list.
You can't update packages from within R? Did you try to start R with
sudo permissions?:
sudo R
Hope this helps
Mat
Le 22. 01. 11 07:50, Ajay Ohri a écrit :
Dear List
I use synapt
écrit :
Hi Mat,
You might be able to use the matrix method to get what you want.
head.matrix(EuStockMarkets)
-Ista
On Sat, Sep 4, 2010 at 1:15 PM, mat wrote:
Hi
I have a few problems with tail/head when applied to multiple time series.
I'm not sure as whether I did not understan
Hi
I have a few problems with tail/head when applied to multiple time
series. I'm not sure as whether I did not understand the function or
whether it correspond to an unexpected behavior.
When head(a,n) is applied on data.frame or matrix, it returns a
data-frame or matrix with first n obs of
array or vector by himself, then the r tools use
the array or vector to calculate? I am very looking forward to your reply
thanks very much
sincerely
mat chueng
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https
Raghu
Those packages are still not on CRAN. You can download the current
version from R-forge:
*|install.packages("blotter", repos="http://R-Forge.R-project.org";)
Mat
|*
Le 10. 07. 10 12:00, r-help-requ...@r-project.org a écrit :
> Message: 137
> Date: Sat, 10 Jul
your case) which looked quite well.
At least this seemed to work out all right on my Windows XP PC.
Hope this helps,
-Mat
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Mike Prager
Sent: Thursday, June 05, 2008 9:38 AM
To: [EMAIL PROTECTED]
Subject: Re: [
he computers.
2) USC and OK St. and GA: Both have lower Cavg scores, but high human
polls (Harris and USA Today) which tend to coincide w/ the preseason
ranking.
3) As for bias, #2 seems to show some bias in the human polls, though I
would not say the computer ranking is not w/o flaw.
Basical
formal job announcement is available at www.usajobs.gov - enter
FDA-09-07-109 in the search box. This announcement contains details
about the position, qualifications, and information about applying. If
you have any other questions, I would be happy to assist in anyway.
Thanks,
-Mat
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