Thanks! That worked
From: William Dunlap mailto:wdun...@tibco.com>>
Date: Tuesday, November 25, 2014 12:53 PM
To: Rolf Turner mailto:r.tur...@auckland.ac.nz>>
Cc: Michael Mason
mailto:mma...@benaroyaresearch.org>>, R help
mailto:R-help@r-project.org>>
Subject: Re: [R] pl
Hello fellow R users,
I have recently updated to R 3.1.2. When trying to plot an hclust object to
generate the dendrogram I get the following error:
Error in .Internal(dend.window(n, merge, height2, hang, labels, ...)) :
there is no .Internal function 'dend.window'
I am indeed using R3.1.2 b
http://r-help.markmail.org/ has a nice interface for searching the
archives, too.
On Wed, Mar 27, 2013 at 12:18 PM, Marc Schwartz wrote:
>
> On Mar 27, 2013, at 1:58 PM, Katherine Gobin
> wrote:
>
> > Dear R helpers,
> >
> > Everyday I do receive many many mails from R forum and after some perio
It sounds like, although your "noon" and "midnight" data are separate rows,
they are not fully independent. If I understand correctly, the operation
you want to perform would be simple if you had (at least temporarily) a
single row with columns ddawn.midnight, ddusk.midnight, ddawn.noon,
ddusk.noon
RY XDRY XDRY XDRY XDRY XDRY XDRY
[12] XDRY XDRY XDRY XDRY XDRY XDRY XDRY XDRY
Levels: XDRY
> mcp(xy,id,percent=95)
Error in apply(xy, 2, mean) : dim(X) must have a positive length
> xy1<-xy[1:19,]
> id1<-id[1:19]
> mcp(xy1,id1,percent=95)
Error in apply(xy, 2, mean) : dim(X) must
Hello Moshe,
Moshe Olshansky <[EMAIL PROTECTED]> writes:
> Try
> x <- as.integer(Membersind06$actual06)
> and then
> x/10
I think I tried that without success (but I tried so many things, that
one may have escaped me). In the meantime I changed the database
relation to a numeric type [numeric(
Hello,
I am trying to do arithmetic on numbers extracted from a PostgreSQL
database, wherein the numbers are stored as type "money". The
transcript below illustrates the problem.
> Membersind06 <- sqlQuery(channel,"select * from income where rowname like
> '%Membersind%'")
> names(Memb
". This works on individual entries, e.g. substr(files[[1]],3,4)
returns "00".
I wish to apply substr() to all the entries in files. All my efforts
fail. Could some kind soul explain how to do what I want?
Thanks,
Roger Mason
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