, 2013 at 3:50 PM, Marc Schwartz wrote:
>
> On Oct 4, 2013, at 2:35 PM, peter dalgaard wrote:
>
> >
> > On Oct 4, 2013, at 21:16 , Mary Kindall wrote:
> >
> >> Y[Y < mean(Y)] = 0 #My edit
> >> Y[Y >= mean(Y)] = 1 #My edit
> >
> > I
Sorry David,
The formula that I use here is
fmla = as.formula(Y ~ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8)
Thanks
On Sat, Oct 5, 2013 at 2:02 AM, David Winsemius wrote:
>
> On Oct 3, 2013, at 3:07 PM, Mary Kindall wrote:
>
> > In the reproducible example given below, why I am
n.trees : argument of length 0
My question is, Is binarizing the response will have so much effect that it
does not find anythin useful in the predictors?
Thanks
--
-
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
___
,-1],type="prob", aggregation=
"average"); pred
For two class case, I use to do the following but it is no longer valid for
three classes.
yhat <- pred[,2]
y = test[, -1]
plot.roc(y, yhat)
Any help will be appreciated.
Thanks
-
impossible to apply rpart on my data.
I am using the following rpart command:
varimp = rpart(fmla, dat=tmpData, method = "class")$variable.importance
Thanks
--
-
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML versi
I have a value
a=300
observation (x) = sample(1:50)
How to find a p-value from this. I need to show that "a" is different fom
mean(x).
Thanks
--
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Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
__
Hi
I have data in the following format:
itemsperson1 person2
- - --
car honda,toyotahonda
bikesuzuki suzuki
pant Lee Levis, Lee
shirt Van_housen Hollister
house rented
0:07 AM, Hadley Wickham wrote:
> On Mon, Jan 16, 2012 at 6:05 PM, Mary Kindall
> wrote:
> > Thanks for reply
> > I wanted to have legend name with spaces. Right now I am using the
> > following code but it produce two legends. I have to use Gimp to cut the
> &
;Number of inputs')
> g <- g + scale_y_continuous('Conversion time (sec.)')
>
> Felipe D. Carrillo
> Supervisory Fishery Biologist
> Department of the Interior
> US Fish & Wildlife Service
> California, USA
> http://www.fws.gov/redbluff/rbdd_jsmp.aspx
>
>
lt;- g + geom_point()
g <- g + scale_x_continuous(name='Number of inputs')
g <- g + scale_y_continuous('Conversion time (sec.)')
g
--
-
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
___
Hi
I am plotting line chart using ggplot and want to use geom_line and
geom_point simultaneously.
I get the plot but now I have two legends. None of the legend is
representing the true values. I need the legend with shape and color both.
Thanks
> con = textConnection("inputs var1var2va
/55078149a733dd1a0b42a57faf847036.png
http://had.co.nz/ggplot2/graphics/90983232ced45a93d9fbbe40afffd69a.png
Thanks
On Thu, Jan 12, 2012 at 12:13 PM, Justin Haynes wrote:
> On Thu 12 Jan 2012 09:02:27 AM PST, Mary Kindall wrote:
>
>> Hi
>> I have a data frame in the following form. There are two grou
28
2 200 0.0022677303 0.02948625
3 300 0.0061182673 0.01739936
4 400 0.0152237225 0.02569902
5 500 0.0300215262 0.03639880
6 600 0.0597610250 0.07717765
Thanks
--
-
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML versi
100 300
> 8 5 4 2 1 1 1 1 1 1
> #extract any range from sorted table
> > t[order(as.numeric(t),decreasing = TRUE)][1:3]
> x
> 5 6 4
> 8 5 4
>
> I hope this helps.
>
> Andrija
>
>
> On Sun, Jan 8, 2012 at 1:48 PM, Mary Kindall
> wrot
.
Thanks.
--
-
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org
,1:4]
> y = table2[1:100,3:6]
>
> z = cbind(x,y) //hanging the machine
>
> write.table(z,'out.txt)
>
>
>
> --
> -
> Mary Kindall
> Yorktown Heights, NY
> USA
>
>
[[alternative HTML version deleted]]
:100,5]
z = cbind(x,y) //hanging the machine
write.table(z,'out.txt)
--
-
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
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either of these:
>
> aggregate(x$case1, x$param, FUN=paste, collapse=",")
> aggregate(x$case1, x[["param"]], FUN=paste, collapse=",")
>
> )
>
> require(data.table)
>>> x <- data.table(x)
>>> x[
>>>
>> + ,
should be
param case1
1 a
2 b,c,d
3 e
4 f
Thanks
M
--
-
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
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read.table(DataFile, header=FALSE, fill_missing_entry = 'unAvailable')
Or remove the the complete row in which the missing entry appear.
thanks
--
-----
Mary Kindall
Yorktown Heights, NY
USA
--
-----
Mary Kindall
Yorktown Heights, NY
USA
[[alternative
ader=FALSE, fill_missing_entry = 'unAvailable')
1
thanks
--
-----
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
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PLEASE do re
ader=FALSE, fill_missing_entry = 'unAvailable')
thanks
--
-----
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
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PLEASE do read th
s the directory itself which I don't want to be printed.
Why it is so? Any workaround for this problem?
Thanks
--
-
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
__
R-help@r-project.org mai
File, 'wget' , quiet = TRUE) != 0)
{
file.remove(destFile)
}
}
thanks
--
-
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
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https://stat.ethz.ch/mai
; Program execution continues, whether or not the download from url was
> > successful. However, wget is, I believe, not available on Windows.
> >
> > Rgds,
> > Rainer
> >
> >
> > On Friday 16 September 2011 15:07:15 Mary Kindall wrote:
> > > I am plannin
2down[i], sep='')
destfile = paste (dest, 'inDir', files2down[i], sep='/' )
download.file(url, destfile, quiet = FALSE)
}
It works fine as long as the file is present. When the file is not present,
it exit from loop. Is there a way to continue looping if error occ
> install.packages("anRpackage", dep=TRUE)
I did not succeed into getting them install in req folder.
Any idea?
--
-----
Mary Kindall
Yorktown Heights, NY
USA
[[alternative HTML version deleted]]
__
R-help@r-project.org maili
the output files
}
newnames <- paste("file", 1:numFiles, sep="") #output variables to load
into
for ( i in 1:numFiles)
{
load(file = outfilenames[i]);
assign(newnames[i], dataFile) #assign into corresponding output variables;
}
#
Regards
-
M
On Sun,
ch a way that the data is loaded
into a variable that is same as the file name without extension.
file1 = load (file = './file1.Rdata')
file2 = load (file = './file2.Rdata')
file3 = load (file = './file3.Rdata')
file4 = load (file = './file4.Rdata')
How can I
7;,'z','z'), Target4 =
c('xx','yy','zz','tt','uu')));
L <- list(dataframe1, dataframe2, dataframe3, dataframe4)
merge.all <- function(...) merge(..., all = TRUE)
Reduce(merge.all, lapply(L, function(x) aggregate(x[2], x[1], toStr
Superb Gabor,
Though I dont know what is happening, but yes it is workin and without fail.
Thanks
-
M
On Mon, Jun 13, 2011 at 8:20 PM, Gabor Grothendieck wrote:
> On Mon, Jun 13, 2011 at 5:17 PM, Mary Kindall
> wrote:
> > Hi R users,
> > I am new to R and am trying to merge
=TRUE,
incomparables=''), by = 'Src', all=TRUE, incomparables='')
ddply(test, ~ Src , colwise(paste, .(Target1)), collapse ="," );
Thanks
On Mon, Jun 13, 2011 at 7:14 PM, Dr. D. P. Kreil (Boku) <
david.kr...@boku.ac.at> wrote:
> ?write.csv
&
x ccc
43 yy ddd
55 zz
66 tt
76 uu
82 aaa
94
10 4
11 4
Thanks
--
M
On Mon, Jun 13, 2011 at 6:35 PM, Dr. D. P. Kreil (Boku) <
david.kr...@bok
-
5 -
-zz
6 -
- tt,uu
Basically I am trying to make a consolidated table.
Help appreciated.
Thanks
M
-
Mary Kindall
Yorktown Heights
USA
[[alternative HTML version
-
5 -
-zz
6 -
- tt,uu
Basically I am trying to make a consolidated table.
Help appreciated.
Thanks
M
-
Mary Kindall
Yorktown Heights
USA
[[alternative HTML version
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