${HOME}/usr/local/lib
export CAIRO_CFLAGS=-I${HOME}/usr/local/include
Regards,
José-Marcio
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
I'm not sure, but would recommend not to.
--
Marcio
www.dsr.inpe.br/~mello
On 31/01/2013 04:26, Ortiz, John wrote:
Dear list,
Can I use a character to set the name of a R package? like this (-)
for example (sdp-R)
Thanks,
John
__
R-h
ngle value is
given, it is used for both margins; if two values are given, the first
is used for x- distance, the second for y-distance."
Good luck!
Marcio
www.dsr.inpe.br/~mello
On 8/13/12 11:33 PM, Lorenzo Isella wrote:
Dear All,
Please see the short script at the en
Dear Simon,
Thanks for the quick reply.
Unfortunately I don't have access to Pinheiro and Bates. I tried googling
the pdSymm and lme but I still cannot get the syntax right.
In my model, I only have 1 random factor with repetitions (groups) (e.g. 2
records per each level)
I am pasting bellow a ver
Hi folks,
I was wondering how to run a mixed models approach to analyze a linear
regression with a user-defined covariance structure.
I have my model
y = xa +zb +e and
b ~ N (0, C*sigma_square). (and a is a fixed effects)
I would like to provide R the C (variance-covariance) matrix
I can easi
For Windows you can use winMenuAdd function. Type ?winAddMenu to see how...
Good luck,
Marcio
www.dsr.inpe.br/~mello
On 3/6/08 10:35 AM, Alberto Monteiro wrote:
er MIMI& piki PIKINHA wrote:
Hello, I´m spanish student, and I´m making the finish project of
computer science. I´m working
Hi David,
thanks a lot! Actually, I was looking for the graph since I still
have obtained the table... but It can help...
Best,
Marcio
www.dsr.inpe.br/~mello
On 2/29/12 5:34 PM, David L Carlson wrote:
Something like this?
x<- round(runif(100, 0, 40), 0)
y<- round(runif(100, 0,
Hi Ralf,
have you solved your problem?! If so, could you share? I have the same
problem...
Best,
Marcio
On 3/25/10 6:03 PM, Ralf B wrote:
Hi all,
I have simple x/y data from screen recording in a sequence:
number,x,y
1,10,30
1,20,
1,43,110
1,74,18
1,88,112
and would like
"L","R","H","D"),states=c("F","F","T","T","T"))
querygrain(setFinding(BN,nodes=scenaria.q2$nodes,states=scenaria.q2$states),nodes="S")
#answering the 3rd question:
# what is the probability of what is
,nodes=scenaria.q1$nodes,states=scenaria.q1$states),nodes="S")
#answering the 2nd question:
# what is the probability of S=T given C=F, L=F, R=T, H=T, and D=T?
scenaria.q2<-list(nodes=c("C","L","R","H","D"),states=c("F","F
lProb(cnet,node=1)[1]
#0.2
#what is the probability of b="2"?
cnNodeMarginalProb(cnet,node=2)[2]
#0.56
#what is the probability of c="1"?
cnNodeMarginalProb(cnet,node=3)[1]
#0.428
#but how can I answer questions like:
#what is the probability of a="1" given that c
orks to compute the results but I don't know how to do it with R.
Looking forward to receiving replies!
Thanks in advance,
Marcio Pupin Mello
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PLEASE do read th
Hi djmuseR,
I tried installing and running the script that you suggested.
But with every value I tried for a, b, c and d I get one of those 2 error
messages
Error in nls(y ~ a - b * exp(-c * x^d), start = list(a = 10, b = 30, c =
0.4, :
singular gradient
Error in numericDeriv(form[[3L]], name
Thanks for the answers.
Indeed, I wrote wrong in my examples the variables x and y
I meant to say
> y <- c(1,7,14,25,29,30)
> x <- c(1,2,3,4,10,20)
Thanks
--
View this message in context:
http://r.789695.n4.nabble.com/Fitting-my-data-to-a-Weibull-model-tp3780169p3781746.html
Sent from the R h
Hi guys,
I have a data-set that fits well into a Weibull model y = a-b*exp(-c*x^d).
I want to estimate the parameters of the coefficients a, b, c and d, given x
and y.
Can you guys help me?
Just as an example, I fit the data
y <- c(1,2,3,4,10,20)
and
x <- c(1,7,14,25,29,30)
According to this mod
David Firth wrote:
Dear R users:
It is planned that participants in the R User Conference, useR! 2011
(August 16-18, http://R-project.org/useR-2011) will each receive a
Better :
http://www.R-project.org/useR-2011
__
R-help@r-project.org mailin
Xin Zhang wrote:
Hi all,
I have never worked with this kind of data before, so Please help me out
with it.
I have the following data set, in a csv file, looks like the following:
Jan 27, 2010 16:01:24,000 125 - - -
Jan 27, 2010 16:06:24,000 125 - - -
Jan 27, 2010 16:11:24,000 176 - - -
Jan 2
It's there. Thank you Ben and also Kurt!
Best,
Marcio
Em 4/7/2011 10:19 AM, Marcio Pupin Mello escreveu:
Thanks Ben! I will!
Em 4/7/2011 8:32 AM, Ben Bolker escreveu:
Marcio Pupin Mello ieee.org> writes:
I've just published a new book for R beginners in Portuguese:
"C
See
http://cran.opensourceresources.org/web/packages/index.html
--
Marcio Pupin Mello
Survey Engineer
Ph.D student in Remote Sensing
National Institute for Space Research (INPE) - Brazil
Laboratory of Remote Sensing in Agriculture and Forestry (LAF)
www.dsr.inpe.br/~mello
Em 4/7/2011 10:59 AM
luck!
--
Marcio Pupin Mello
Survey Engineer
Ph.D student in Remote Sensing
National Institute for Space Research (INPE) - Brazil
Laboratory of Remote Sensing in Agriculture and Forestry (LAF)
www.dsr.inpe.br/~mello
Em 4/7/2011 7:38 AM, idham escreveu:
Hi guys,
I'm really new in R.
Tryi
Thanks Ben! I will!
Em 4/7/2011 8:32 AM, Ben Bolker escreveu:
Marcio Pupin Mello ieee.org> writes:
I've just published a new book for R beginners in Portuguese:
"Conhecendo o R: uma visão estatística" (something like "Knowing R: an
statistical approach"). I'
You can do it using factor:
s0<-factor(0:5)
s1<-sample(s0,5,re=T)
s1
[1] 0 2 2 4 0
Levels: 0 1 2 3 4 5
table(s1)
s1
0 1 2 3 4 5
2 0 2 0 1 0
Good luck!
--
Marcio Pupin Mello
Survey Engineer
Ph.D student in Remote Sensing
National Institute for Space Research (INPE) -
More informations about the book at
http://www.editoraufv.com.br/produtos/conhecendo-o-r
--
Marcio Pupin Mello
Survey Engineer
Ph.D student in Remote Sensing
National Institute for Space Research (INPE) - Brazil
Laboratory of Remote Sensing in Agriculture and Forestry (LAF)
www.dsr.inpe.br/~mello
___
them, you can
sort them by their scores and enumerate the number of couples out of order you can get.
Hope this help.
José-Marcio
--
-------
Jose Marcio MARTINS DA CRUZ http://j-chkmail.ensmp.fr
Ecole des Mines de Paris
sammyny wrote:
I did a fourier transform on a function in time domain to get the following
functions in frequency domain (in latex):
$Y_1[\omega] = \frac{1}{1-\phi_1 e^{-jw}}$
$Y_2[\omega] = \frac{1}{1-(\phi_1 + \phi_2)e^{-jw} +\phi_1\phi_2e^{-2jw}}$
How do I find the spectrum of this functio
Thanks for the hint. Helped a lot
Gabor Grothendieck wrote:
On Sat, Feb 12, 2011 at 7:48 AM, Jose-Marcio Martins da Cruz
Functions which work with ts typically assume that a full cycle is
represented by 1 unit so if a full cycle is a week then a week must be
one unit and a day must be 1
This question is surely trivial, sorry. I'm afraid I'm misunterpreting
the information I got with the documentation, and I'm a little bit
confused. I'm just an engineer with some little skills in statistics.
Well, I have a time series - 600 days long - with some weekly
periodicity inside. So
D=1 and select d using ndiffs and the KPSS test
# for stationarity.
# ... if no model can be found - return NULL
--
-------
Jose Marcio MARTINS DA CRUZ http://j-chkmail.ensmp.fr
Ecole des Mines de Paris
60, bd Saint Mi
I think ther's a bug here :
bdp wrote:
Some code I have been playing with to do this follows ...
get.best.arima<- function(x.ts, minord=c(0,0,0,0,0,0),
maxord=c(2,1,1,2,1,1))
{
# function based on 'Introductory Time Series with R'
best.aic<- 1e8 # a big number
n<- leng
Hello,
I have a matrix with the numbers 0,1 and 9
I would like to write a function that could sum each line skiping everytime
a number 9 appears
for example
[0 1 0 1 1 9 1]
the sum would be 4.
However I cannot replace 9 by 0 otherwise after the sum is done I wouldn´t
be able to distiguish which o
#Mdarts is a matrix 2343x788
#frequencia is a vector 2343x1
# 9 in Mdarts[fri,frj] stands for my missing values which i want to replace
by the value in the vector frequencia
Mdarts<-t(matrix(scan("C:/GWS/CNB/dartg.txt"),ncol=nindT,nrow=nm, byrow=T))
frequencia <- matrix(scan("C:/GWS/CNB/freq.txt
I would like to divide a vector in 9 groups in a way that each number is
present in only one group.
In a vector of 783 I would like to divide in 9 different groups of 87
Example <- matrix(c(1:783),ncol = 1)
s1 <- as.matrix(sample(Example,87, re = FALSE))
Example <- Example[-s1]
s2 <- as.matrix(sa
Hi guys, my doubt is quite simple,
I´ll try to explain:
test = matrix(0, nrow = 783, ncol = 12)
for (x in 1:9){
for (y in 1:12){
### In the original script for each y its generated a vector (87x1)
### 87 times 9(x) = 783 (equals the number of rows I want to fill in the
"test" matrix
}
}
W
I have a matrix 700x2000 which is sampled in each cycle from another matrix
788x2000 with the numbers 0,1 and 9
There is one specific collumn of this matrix, dart[,1977], that usually,
after the samplimg procedure has only 1 and 9 (because the zero frequency in
this collumn is low).
However, when
Hi Lucas,
try:
if(pvalue>0.05 & pvalue<0.1)
HTH
Marcio
Lucas Sevilla García wrote:
>
>
> Hi R community
>
> I have a little problem, and I tried to solve it by myself but I couldn't.
> I building an if loop, and I want to check a value inside an i
g it to do with the script you
> provided.
>
> On Sun, Sep 27, 2009 at 10:09 AM, Marcio Resende
> wrote:
>>
>> Hi Tobias, thanks for the help,
>> the code I am using is quite long, but basically what I tried to do was
>>
>> test <- matrix(0,6,1)
&g
Hi Tobias, thanks for the help,
the code I am using is quite long, but basically what I tried to do was
test <- matrix(0,6,1)
x <- matrix( c(50,100,200,300,900,2343) ,ncol = 1)
for (i in x){
test [i] <- (i)
}
but this code returns NA for all the elements which are not x
Tobias Verbeke-2 w
Hi Hyo,
I am kinda of new in R but I think if you use
x <- as.matrix(data2) #with the numer of collumns you wish
y <- t(x)
it should work
Hope I´ve helped
Márcio
Hyo Lee wrote:
>
> Hi guys,
> I need your help!!
>
> My goal is to make a csv file from ncdf file.
> This is the code i've used
Hi nice people,
I would like to do a for cycle but i wish it to assume only the numers 50,
100, 200, 300, 900 and 2343
I tried to do something like
x <- c(50,100,200,300,900,2343)
for (i in x){
#.
}
But it didn´t work
Could anybody help me?
Thanks in advance
Marcio
--
View this message
Hi,
I am new in R and I don´t know how to sum the product of two elements at the
time in a matrix
X=[ 1 5 9 13
2 6 10 14
3 7 11 15
4 8 12 16]
I would like to do (1*5+2*6+3*7+4*8)
I need to do it step by step because I will further put a conditional in the
formula
Sorry, I sent it quickly and forgot to thank in advance
Marcio
Marcio Resende wrote:
>
> hello guys, I need to do a BLUP in the simplest model
> y = Xm + Zg + e
> however I have missing data in the analysis which I can´t consider as
> 0(zero). So I need to generate the matrix X
hello guys, I need to do a BLUP in the simplest model
y = Xm + Zg + e
however I have missing data in the analysis which I can´t consider as
0(zero). So I need to generate the matrix X'Z, Z'X and Z'Z step by step; I
can´t use
crossprod(x) #neither
X'X <- t(x)%*%x
because I should skip the element
After I run my script I save all my output e.g.
write.table(d, file = "C:/PINEheight.txt)
write.table(v, file = "C:/PINEvolume.txt)
write.table(v, file = "C:/PINEdiameter.txt)
write.table(v, file = "C:/PINEdensity.txt)
and then I would like to run again with another tree and save again e.g
write
I am new in R and i am having trouble here. I´ve already searched in the list
but hasn´t helped
When i run this script above i get the message "Error in gen[j, i] :
incorrect number of dimensions". However gen is 1000x200 (ind x loc) and so
is g
could anybody help me
for (i in 1 : loc) { #l
Good Mourning,
I have a function to generate a matrix as I show part of it;
g[j,i]<-if (gen[j,i]==0) al1[i,1]+al1[i,1] else ...
However i would like that this function occurred with a probability P and
that another function (another formula to generate g matrix) with
probability P-1
That´s it,
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