I mean I want to convert them to whatever is the standard R DateTime class.
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I have searched and tried to read before posting but can find nothing to
accomplish change Excel dates in double format to R
Can someone please help
I have a vector of double like this from Excel.
39965.0004549653
and I want to put them in R such that I can display them in any Date and
Time fo
Hi,
Does anyone know how to halt Rcmdr?
If I make an error and execution is taking a very long time. Is there a way
to halt it WITHOUT killing Rcmdr or Rconsole?
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Thanks Philippe,
I will look at sciviews - I have never used it before.
I use Rcmdr, and I find I am often selecting and running the same lines of
code. I just thought if we could name them then easily "call" that region it
would be useful.
Cheers
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Does anyone know of a gui for R that has "regions" i.e areas of code in a
script that can be named and hopefully run as a section?
@region Init
library(whatever)
myprint<-function(...){print(...)}
@endregion
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Is there a 64 bit R - and where can I get hold of it for Windows please?
Your sizes function is useful thanks - but is there some R parameter to
allow maximum usage of memory?
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Hi,
I keep getting this error in console. but I have 30G of RAM:
Error: cannot allocate vector of size 154.3 Mb
Is there some way to tell it I have more memory available?
I am on Windows XP 64 bit
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Fayssal,
This zip file appears to be corrupted - do you have another version?
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You are right David - I found the as.Date by myself eventually(must be
getting better at this!)
But unclass is new to me - thanks very much
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Sorry David,
Here's cut down version of my function - real version does some fancy plot
formatting.
I have found a way round my problem because cbind will bind vectors and
matrices into a single matrix, which I can work with. It is not the answer I
was looking for - but it does the job.
Many th
How do I get a number representing a date from a POSIXct i.e. removing the
time elements?
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IIs there an equivalent of cumsum for a matrix? i.e cumsum is applied to each
column ?
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I am trying to un-c...
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I have a function that take a variable number of arguments, each of which
must be a vector.
Is there a way to "unbind" a matrix that would pass the columns as vectors?
Myfunc<-function(...) {
[My code]
}
Myfunc(z[,1],z[,2]) works
but Myfunc(z[,1:2]) is passing a submatrix
Is there somethin
Thanks - that works
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Sorry
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PLEASE
I am parsing dates as follows:
> z[1:10,1:3]
V1 V2 V3
10 03/02/09 22:20:51.274
2 100 03/02/09 22:28:18.801
3 200 03/02/09 22:33:33.762
4 300 03/02/09 22:40:21.826
5 400 03/02/09 22:41:38.361
6 500 03/02/09 22:42:50.882
7 600 03/02/09 22:45:19.885
8 700 03/02/09 22:4
Brian,
You say "See cbind etc". How would I do that?
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Hi,
A number of people have suggested "I read the manuals"...
Could someone help me by telling me where the primary start point is please?
For example, I am interested in writing functions with variable number of
arguments - where should I start to look?
"An introduction to R" only show a brie
But it doesn't say much - is there comprehensive documentation anywhere else?
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Thanks for all the replies guys - I think I get it now!
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z<-read.table("C:/yourfile.txt",header=TRUE,as.is=TRUE);
zdates<-as.POSIXct(strptime(paste(z[,2],z[,3]), "%m/%d/%Y
%H:%M:%S"),origin="1970-01-01" );
I would then convert z from a dataframe to a numeric matrix, and put zdates
in there as numeric too.
zm<-cbind(z[,1],as.numeric(zdates),z[,4])
I a
Thanks Duncan - that works perfectly.
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My point is this:
if we do
temp<-tDates
aggregate(DF[,c('V2', 'V3')],
list(format(temp, "%H:%M:00")),
FUN = sum)
Does agrregate still know it's refering to DF$V1 - and if so- how?
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This does what I was hoping it would:
aggregate(tm[,-1],by=list(tm[,10]),FUN="mean")
but I don't know what "tm[,-1]" means (well - the -1 bit anyway.
Does it somehow means the whole matrix?
Please don't tell me to check the manual - I tried and failed dismally...
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Thank you
In the "aggregate" how does it know which column to group?
I know you give it tDates as the second argument, but it doesn't know that
is from DF - we could have put anything there I think...
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Duncan,
Thanks you - your deparse(substitute(...)) work - fantastic.
But, when I pass in multiple arguments: f(z[,1],z[,2])
I only show first argument, rest shows up as NULL
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I have a matrix with a POSIXct as a numeric in the first column.
I would like to create a new matrix that is "grouped by" my chosed time
bars.
i.e. So I would like to group by hour or day or 5 days, and have all my
columns be summed or averaged or counted..
mydata:
V1,V2,V3
10:03:13,3.4,1002
1
enEyes=c(1,2,3,4)
> niceplot(GreenEyes)
"GreenEyes"
>
I will use the vector for plotting too, but I need it's name to produce a
legend automatically
On 10 March 2010 23:32, David Scott-6 [via R] <
ml-node+1588213-620034400-180...@n4.nabble.com
> wrote:
> ManInMoon wro
) {
> cat(x)
> }
> }
> > e="e"
>
> > niceplot(e)
> e
>
> On Mar 10, 2010, at 5:21 PM, ManInMoon wrote:
>
> >
> > I have writtn a function where I pass a variable number of arguments.
> >
> > I They are vectors and I can m
numToPOSIXct <- function(v) {
now <- Sys.time()
Epoch <- now - as.numeric(now)
Epoch + v
}
Try this - where v is your numeric version of date
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I have writtn a function where I pass a variable number of arguments.
I They are vectors and I can manipulate them, but I need to get hold of the
name for a legend.
niceplot<-function(...) {
parms=list(...)
for (x in parms) {
DoSomethingWith(x)
}
}
BUT how how can I get something l
Thank you!
On 10 March 2010 21:21, David Winsemius [via R] <
ml-node+1588077-2145101402-180...@n4.nabble.com
> wrote:
>
> On Mar 10, 2010, at 2:50 PM, ManInMoon wrote:
>
> >
> > It does help much.
> >
> > Just one line about x[-1]
> >
> >
Because I am asking for help...
On 10 March 2010 20:19, Kevin E. Thorpe [via R] <
ml-node+1587986-1699461774-180...@n4.nabble.com
> wrote:
> ManInMoon wrote:
> > Hi, I am new to R.
> >
> > What does a negative amount in an index do?
> >
> > i.e. x[-lenght
It does help much.
Just one line about x[-1]
Is there more comprehensive help anywhere?
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I understand you can pass a variable number of arguments to a function that
is written to accept "..."
I have searched for any documentation on how to write such a function -
could someone tell me where to look please
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Hi, I am new to R.
What does a negative amount in an index do?
i.e. x[-lenght[x]]
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How can I generate a vector of differences between each elemtn of an vector?
i.e. a[i]=x[i]/x[i-1]
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What is "R News 4/1"?
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I am generating a column of dates using POSIXct, but when I try to assign it
to an existing dataframe - it gets "stored" as numbers instead of as
POSIXct.
Is there a way to force a column to be a specific type (POSIXct)?
Thanks,
Moon
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It appears that I am creating a matrix where als columns are of type number,
so my Date column has been converted to a number.
Is there a way to show or display this number column as a Date again?
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Thanks Gabor - sprintf did the trick
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I have text date colum with dates such at 290210 which I can parse with
%d%m%y but I also have date without leading zeo i.e. 10210 (Ist Feb 2010)
which cause any NA.
How can I parse the second one?
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I have a big data frame and I have extracted a bit by doing:
> y<-d[1:10,6]
> y
[1] Headings 0-49 -98 -49 -41 -120 -155
-204 -169
92329 Levels: -0 -1 -10 -100 -1000 -1 -10001 -10002 -10003 -10004 -10005
-10006 -10007 -10008 -10009 -1001 -10010 -100
I have created a large dataframe (d) by getting data from file using
read.table
I now have 79 columns and 3 million rows. How can I plot the 6th column? I
tried plot(d[,6]) but it doesn't look right. When I try to do just d[,6] the
console gets some odd "levels" message I don't understand
Moon
-
Is there an easy way to do two things:
I have a dataframe with headers and 18 columns
I want to plot all the columns on same y axis plot(df) does this.
BUT
1. There is no legend, the legend function seems pedantic - surely there
must be an easy way to just pick up my headers?
2. How do I vary
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