Re: [R] fields package question

Actually, let's set it grid_new.l <- list(abcissa=c(-15.0,-14.5),ordinate=y) to avoid out of bounds On Tue, Dec 25, 2018 at 4:41 PM M P wrote: > Thanks, Eric, for looking into that. > The values are below and since I subset the new abcissa is smaller range > grid_new.l <-

Re: [R] fields package question

rmatted emails are not passed > along. > > > > On Tue, Dec 25, 2018 at 4:13 AM M P wrote: > >> Hello, >> I used commands below to obtain a surface, can plot it and all looks as >> expected. >> How do I evaluate values at new point. I tried as below but

[R] fields package question

Hello, I used commands below to obtain a surface, can plot it and all looks as expected. How do I evaluate values at new point. I tried as below but that produces errors. Thanks for suggestions/help. x <- log(lambda) y <- rh z <- qext[,,2] grid.l <- list(abcissa=x,ordinate=y) xg <- make.surface.g

[R] an apply question

Hello, It should be easu but I cannot figure out how to use apply function. I am trying to replace negative values in an array with these values + 24. Would appreciate help. Thanks, Mark shours <- apply(fhours, function(x){if (x < 0) x <- x+24}) Error in match.fun(FUN) : argument "FUN" is missing,

Re: [R] subsetting time series

Thats works perfectly, thanks a lot, Mark On Thu, Dec 13, 2012 at 11:34 AM, arun wrote: > Hi, > Try this: > seq1<-seq(from=as.POSIXct("2012-05-30 > 18:30:00",tz="UTC"),to=as.POSIXct("2012-05-31 02:30:00",tz="UTC"),by="1 > hour") > seq2<-seq(from=as.POSIXct("2012-05-31 > 00:30:00",tz="UTC"),to=as

[R] subsetting time series

Hello, my series of dates look like [1] "2012-05-30 18:30:00 UTC" "2012-05-30 19:30:00 UTC" [3] "2012-05-30 20:30:00 UTC" "2012-05-30 21:30:00 UTC" [5] "2012-05-30 22:30:00 UTC" "2012-05-30 23:30:00 UTC" [7] "2012-05-31 00:30:00 UTC" "2012-05-31 01:30:00 UTC" [9] "2012-05-31 02:30:00 UTC

[R] ncdf - writing variable to a file

Hello, I have a problem writing a variable to an existing file. Below is a part of my script and how it fails. I can't find "create.var.ncdf" in help Thanks for any help. Mark nc <- open.ncdf(ncname, readunlim=FALSE, write=TRUE ) missing <- 1.e+30 xdim <- nc$dim[["west_east"]] ydim <- nc$dim[["s

[R] variable spatial correlation

Hello, I used "correlogram" from "spatial" package to determine correlation scale for my data but just looking with bare eye it seems that the correlation scale varies over the domain. Can someone suggest what would the best way to handle that problem? Thanks, Mark [[alternative HTML versi

Re: [R] 1-d function fitting

No, that's not my homework. Does that seem so easy? Mark Rolf Turner <[EMAIL PROTECTED]> wrote: On 26/10/2007, at 10:14 AM, m p wrote: > Hello, > I'd like to check if my data can be well approximated with a function > (1+x/L) exp(-x/L) > and calculate the bes

[R] 1-d function fitting

Hello, I'd like to check if my data can be well approximated with a function (1+x/L) exp(-x/L) and calculate the best value for L. Is there some package in R that would simplify that task? Thanks, Mark __ [[alternative HTML version de