Re: [R] How to index the occasions in a vector repeatedly under condition 1? if not, it will give a new index.

Hi Peter, Thank you so much. Kind regards, Lijun -Original Message- From: peter dalgaard Sent: Friday, 21 February 2020 8:16 PM To: Lijun Zhao Cc: William Dunlap ; r-help@r-project.org Subject: Re: [R] How to index the occasions in a vector repeatedly under condition 1? if not, it

Re: [R] How to index the occasions in a vector repeatedly under condition 1? if not, it will give a new index.

lap Sent: Thursday, 20 February 2020 1:53 AM To: Lijun Zhao Cc: r-help@r-project.org Subject: Re: [R] How to index the occasions in a vector repeatedly under condition 1? if not, it will give a new index. Use cumsum(logicalVector) to increment a counter at the TRUE positions in logicalVector. . E

[R] How to index the occasions in a vector repeatedly under condition 1? if not, it will give a new index.

=15, it will give a new index. I want the output be like y. y<-c(1,1,1,1,1,1,2,3,3) Thank you so much, Lijun Zhao (PhD Candidate) Nutrition and Metabolism Level 7 SAHMRI North Terrace Adelaide 5005 Ph: +61 8 8128 4898 e-mail: lijun.z...@adelaide.edu.au<mailto:lijun.z...@adelaide.e

[R] How to index the occasions in a vector repeatedly under condition 1? if not, it will give a new index.

Dear All, could you please help me how to get the output from the following example? x<-c(543, 543, 543, 543, 551 , 551 ,1128 ,1197, 1197) diff<-x-lag(x) diff [1] NA 0 0 0 8 0 577 69 0 how to index the occassions in x repeatedly if the diff>15? if not, it will give a new in