3 1 8 222
49 1 9 2 3
55 1 10 226
61 1 11 318
67 1 12 319
73 1 13 328
79 1 14 310
--truncated
Regards,
Laz
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Hi R users,
I need to write a function that considers the row and column
autoregressive residual correlation structures. Usually
R=sigma^2_e*Identity matrix of order n, where n is the number of
observations and sigma^2_e is the usual residual error. I have to
consider an AR1 * AR1 where * stan
model that has both fixed and
several random effects. Which R packages or functions will help me to
accomplish this?
Thanks.
Laz
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PLEASE do read the posting guide http
get 12 changes which means that
function only dropped the traces when trace_j > trace_i but did not drop
the design !!
How do I fix this ?
Kind regards,
lazarus
On 10/19/2013 5:03 PM, Rui Barradas wrote:
> Hello,
>
> Seems simple.
>
>
> fun <- function(n = 10){
>
seq_len(n)){
# now swap the pairs of treatments from the original design, n times
matdf<-swapsimple(matdf,ped="F")
if(mainF(criteria="A") < start0){
start0<- mainF(criteria="A")
res$mat <- rbind(res$mat, c(trace = start0
Thank you so very much!
It works like a charm !!!
Regards,
Laz
On 10/19/2013 5:03 PM, Rui Barradas wrote:
fun <- function(n = 10){
matd <- matrix(sample(1:30,30, replace=FALSE), ncol=5, nrow=6)
res <- list(mat = NULL, Design_best = matd, Original_design = matd)
trace &l
29
[4,] 30 20 177 23
[5,] 18 27 211 10
[6,] 25 1648 26
$ Original_design
[,1] [,2] [,3] [,4] [,5]
[1,] 12 27 29 16 19
[2,] 25 107 22 13
[3,] 14 233 11 21
[4,] 28 652 18
[5,] 24 201 17 26
[6,]
Thanks. Sweave/Latex is done the job for me !
Regards,
Laz
On 9/22/2013 8:26 PM, jim holtman wrote:
CHeck out the 'tables' package if you want to create pretty outputs of
your tables. Exactly where do you plan to use them? You can also use
Sweave/Latex to create such tables.
J
Hi,
fortune("Yoda") returns a quote of fortunes.
My problem was to draw horizontal and vertical lines to separate the
blocks in my design. Each block has 4 elements. The first and second
rows and columns are in block 1, 3rd and 4th rows and 1st and 2nd
columns are in 3 etc
[,1] [,2] [,
Is "Yoda" an R package? I tried:
install.packages("Yoda")
Warning in install.packages :
package 'Yoda' is not available (for R version 3.0.1)
Warning in install.packages :
package 'Yoda' is not available (for R version 3.0.1)
How do I proceed from h
Thanks Jim,
What you have done is very good.
I was wondering if we could draw some horizontal and vertical lines to
separate the blocks. Is it possible using R?
Regards,
Laz
On 9/22/2013 11:10 AM, jim holtman wrote:
Is this what you were after:
## A function to generate a RCB design
rcbd
ction?
2 4 2 3
1 3 4 1
3 2 2 3
1 4 4 1
Regards,
Laz
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ction?
2 4 2 3
1 3 4 1
3 2 2 3
1 4 4 1
Regards,
Laz
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P
to delete
delete <- which.max(high) + 1L
mat <- mat[-delete,, drop=FALSE]
}
The error I get is
" Error in r[i1] - r[-length(r):-(length(r) - lag + 1L)] : non-numeric
argument to binary operator"
How do I fix it?
Laz
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now how to make it faster.
I used system.time()
Regards,
Laz
On 8/19/2013 10:13 AM, Bert Gunter wrote:
... and read the "R Language Definition" manual. I noticed unnecessary
constructs
(e.g., z <- f(something); return(z)) that suggest you have more basics
to learn to write efficient,
Dear R users,
I have written a couple of R functions, some are through the help of the
R group members. However, running them takes days instead of minutes or
a few hours. I am wondering whether there is a quick way of doing that.
Here are all my R functions. The last one calls almost all of
.8890167
0.884659 0.0004215379 0.000410769 0.2342 0.676307
0.8885839 0.0001215379 0.0002112 0.82752992 0.8836337
Thanks fpr you help.
On 6/7/2013 5:24 AM, Berend Hasselman wrote:
> On 07-06-2013, at 10:59, Laz wrote:
>
>> Dear R users,
>>
>> I am stuck
Hasselman wrote:
On 07-06-2013, at 10:59, Laz wrote:
Dear R users,
I am stuck here: My first function returns a vector of 5 values.
In my second function, I want to repeat this, a number of times, say 10
so that I have 10 rows and five columns but I keep on getting errors.
See the code and results
5
> [6,]46
> [7,] 117
> [8,]28
> [9,]69
> [10,]5 10
> [11,]6 11
> [12,] 18 12
> [13,]9 13
> [14,] 16 14
> [15,] 18 15
> [16,]9 16
> [17,]2 17
> [18,]7 18
> [19,] 15 19
Dear R Users,
I created a function which returns a value every time it's run (A
simplified toy example is attached on this mail).
For example spat(a,b,c,d) # run the first time and it gives you ans1=
10, perm=1 ;
run the second time and gives you ans2= 7, perm=2 etc
I store both the result
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