mail
enquir...@solutionmetrics.com.au<mailto:enquir...@solutionmetrics.com.au> or
call +61 2 9233 6888
Full Schedule<http://bit.ly/13lJ4ag>
Regards,
Kris Angelovski | Chief Data Scientist | SolutionMetrics
T +61 2 9233 6888 | M +61 488 388 338
E
kris.angelov...@solutionmetrics.co
ir...@solutionmetrics.com.au<mailto:enquir...@solutionmetrics.com.au> or
call +61 2 9233 6888
Cheers
Kris Angelovski | Chief Data Scientist | SolutionMetrics
T +61 2 9233 6888 | M 0488 388 338
E
kris.angelov...@solutionmetrics.com.au<mailto:kris.angelov...@solutionmetric
Thank you all for the feedback. I was actually amazed at not only the
number but quality of responses, and they were all helpful. I have got it
working now, thanks again!
Kind regards,
Kris
2015-06-12 7:58 GMT+08:00 John Kane :
> Thanks Don,
>
> I suspected there was a Boxplot() out
installing all the packages but keep getting teh same error
message. The code runs on my supervisors R program and produces a boxplot,
but doesn't on mine and am wondering if someone could assist me.
Thanks in advance,
Kris
--
*Kris Singh*
Provisional Psychologist
MPsych (Clinical Neuropsyc
au<mailto:enquir...@solutionmetrics.com.au> or
call +61 2 9233 6888
Cheers
Kris Angelovski | Director| SolutionMetrics
T +61 2 9233 6888 | F +61 2 9233 4099
Suite 44, Level 9, 88 Pitt Street, Sydney NSW 2000
solutionmetrics.com.au<http://www.sol
ug, 2013 - Sydney (Thu)
2 Sep, 2013 - Sydney (Mon)
.
For more information, please email
enquir...@solutionmetrics.com.au<mailto:enquir...@solutionmetrics.com.au> or
call + 61 2 9233 6888
Cheers
Kris Angelovski | Director| SolutionMetrics
T +61 2 9233 6888 | F +61 2 92
hout luck
xyplot(Cond ~ as.numeric(DateTime) | Sensor, data = dat, groups = id,
layout=c(1, 2), type="l", xlab="Date", ylab="Relative Conductivity",
scales = list(x = list(julian(dat$DateTime) )))
Thanks very much for any assistance.
Kris
--
View this messa
When adding a trend line to a scatterplot (e.g. abline (90,4,col="red"), I
believe the "90" is the intercept and "4" is the slope. How do I determine
the intercept and slope for the abline command?
Kristopher R. Deininger
Management Strategy & Entrepreneurship
PhD Student 2012
Robert H. Smith
When adding a trend line to a scatterplot (e.g. abline
(90,4,col=red), I believe the 90 is the intercept and 4 is the
slope. How do I determine the intercept and slope for the abline command?
_
eet.
[[alternative
do, or is there
another command that I should be using?
Any guidance would be great.
Cheers,
Kris
Kris Jamsen
Research Fellow
Centre for Molecular, Environmental,
Genetic and Analytic (MEGA) Epidemiology
Level 1, 723 Swanston St
The University of Melbourne
Victoria,
Hi everyone,
I sent this message before I became a member of the list, so apologies
if you get it twice.
Cheers,
Kris
I'm trying to fit a generalized linear mixed effects model (logistic) in
R and am having some trouble specifying the covariance structure for the
random ef
I have data in the form of a column such as
1234.
2345.
3435.
4343.
I want to have the data in this form ..i.e to remove the "dot" at the
end of each number above.
1234
2345
3435
4343
I am trying to use split but it is not working. Any suggestions?
[[alternative HTML version deleted]]
__
I have 2 tables,T1 and T2. There are 4 columns of T1 and 2 columns of T2
T2
1. 990334. G21
2. 844047. G25
3. 281739. G37
4 280903. G002615
5 418546. G004657
The data in T1
V1V2V3 V4
1 T00015 AFP1 human G004657
2 T00035AP-2alphaA human
#x27;t a useful reply.
Any ideas?
Best wishes, Kris.
_
[[alternative HTML version deleted]]
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