Thank Petr for your help. It do what I wanted also.
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Hi,
Thank Michael, I resolved my problem with your help. the projections of the
layers were the same.
Ok for reading the posting guide and . R sig geo list.
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Hi
I want to overlay my raster and its boundary which is a shapefile.
When I used thise code separately, all is ok:
# Open raster
>Image<-read.table("C:\\Users\\Documents\\Nouveau\\Frequence.txt",sep="",dec=",",header=TRUE)
>
>testo<-rasterFromXYZ(Image)
>plot(testo)
>testo2 <- aggregate
Hi
Thank you Bert and Thomas for your help, I did what I wanted with this code.
>test<-c(4,8,9,6,7)
>barplot(test,density =20,angle=45)
But I want to cross the lines in each bar.
Please, how to do it?
Thank you in advance.
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Hi,
Instead to put colour in my histogram,
I want to put symbols like lines, dots etc.
Do you know the function that does it?
Thank you in advance
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inverse(Barerror$Mois),Barerror$Mois[1]),y=c(Barerror$MoyArea+Barerror$SdArea,inverse(Barerror$MoyArea-Barerror$SdArea),Barerror$MoyArea[1]+Barerror$SdArea[1]),col="gray",border=NA)
lines(Barerror$MoyArea~Barerror$Mois,lwd=2)Â
Â
Thanks
Komine
Â
De : J
Hi,
Thank you David, I resolved the problem with ?text.
Komine
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Dear,
Thank bbolker for your answer, but with las I do not see oblique orientation
for labels. There are horizontal, vertical but not oblique orientation.
Thank for others answers.
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Hi,
I drew a barplot with this code:
> BarSize<-barplot(Size$SumArea,names.arg=Size$Class)
However the name of each bar is long. Thus, some names do not appear. I want
to write labels with Oblique orientation.
Can you help me to do that?
Thank you in advance.
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(small) reproducible example
of your data.
The statement "...output does not seem good." Â is not very useful.
Please explain what you would like the polygon area to look like, and
why you don't like the way it came out. Â Links to posted images of the
chart would help too.
Hi everybody,
I have a matrix with 3 columns (Date, MeanArea and SdArea). I want to draw a
figure showing the variable MeanArea in terms of the Date. But instead to
use the variable SdArea as bar error, I want to use “polygon error”. I use
this code but the output does not seem good.
Polyhttp://r.
Hi,
Thank Michael for your help.
Komine
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https
Hi,
I try to build a loop difficultly.
I have in a folder called Matrices several files (.csv) called Mat2002273,
Mat2002274 to Mat2002361.
I want to calculate for each file the mean of the column called Pixelvalues.
I try this code but as result, I have this message: Mat2002273 not found
>
Thank you Sarah and Petit bleu for your help.
I solved my problem with the code of Sarah.
Komine
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HI,
This code is part of a code I used to do a linear regression:
>points(var1~var2,data=Regress,pch=21,bg="grey")
>reg11<-lm(var1~var2,data=Regress)
>abline(lm(var1~var2,data=Regress),lty=2,lwd=2,col="grey")
>legend("topleft",legend=
>c("NDII from composite",
>"y= 0.0007x - 0.1156",expression(p
Thank you for your answers. The problem persists always (without ".pdf" or
using "print" or "plot"). The code runs, but the probem is to save the
figure with pdf format in order to load it directly in word.
Howerver, I will read the link indicated.
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Hi,
I created a figure with R and I want to save it in .pdf. I used this code:
> pdf("res.pca.pdf",width=10,height=8)
> library(FactoMineR)
> res.pca<-PCA(acp)
> res.pca
> dev.off()
When I go in my folder, I find an empty file ( 0 Ko).
Do you know where is the problem.
Thank you in advance
Thanks, I see the problem. R did the opposite of Excel. I invert the
position of variables in my code and the result is now correct.
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Hi,
I used simple linear regression with the R software and EXCEL on the same
data. Although , I find the same R2=0.84, I find different estimated values
(intercept and slope). For the R software (slope =0.0009, Intercept =
-0.1478), for EXCEL (slope =927.7, Intercept = 154,41).
When I use the e
Thank you bbolker for your help and advice about guide.
Komine
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What I can do to obtain R^2?
- The way to verify Homoscedasticity and normality is the same for linear
model?
Thank you in advance
KOMINE
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Sent fr
where is the problem?
- What I can do to obtain R^2?
- Is the method to verify homoscedasticity and normality is the same for
linear model?
Thank you in advance
KOMINE
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Se
Hi,
After performing a multiple linear regression,
I am looking for an R package that can calculate the fraction [a] a
partitioning of variation. This fraction measures the proportion of variance
of y explained by the explanatory variable x1 (for example) when other
variables (x2, x3 ...) are hel
fraction of each variable must be equal to 1.
Thanks for your help.
Komine
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to invert the color to obtain red
color corresponding with the big values.
Thanks for your help.
Komine
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1218/nomogram_2.jpeg
Please can I do to have linear predictor between 0 to 1.
Thanks very much for your Help
Komine
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nomogram.
Thanks again
Komine
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https://stat.ethz.c
er to understand.
http://r.789695.n4.nabble.com/file/n3503828/nogramme.bmp
Nb: I Apologize for my bad english
Thanks for your help
Komine
PhD student
Dakar _Sénégal
West Africa
Komine wrote:
>
> Hi all R users
> I did a logistic regression with my binary variable Y (0/1) and 2
>
)
plot(Predict(f,L=200:800,P=3))
Unfortunately, I have error after the 2nd code:
Erreur dans datadist(f, data = donnee) : program logic error
Please could you provide me a document more simple which is more
understandable for new R user.
Thanks for your help.
Komine
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Thanks Frank
I will try rms package and give after the result.
Komine
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ld you help me on the code to draw nomogram.
Nb: my English is low, I apologize.
Thank for your help
Komine
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