iginal Message-
Date: Mon, 04 Mar 2013 10:48:39 -0500
From: Duncan Murdoch
Cc: "r-help@r-project.org"
Subject: Re: [R] Mysterious issues with reading text files from R in
ArcGIS and Excel
Message-ID: <5134c257.6020...@gmail.com>
Content-Type: text/plain; charset=ISO-8859-1; fo
I appreciate the help and suggestions. I was afraid that this question would
be considered "off topic", but thought I would give it a try to see if anyone
else gets these results from R output files. As I do not know what a hex
editor or hexbin are I guess I will not be able to continue this d
that were generated from using the write.table or
write.csv.
Any thoughts at to explain why I get 2 new columns of data in either the CSV
format or the TXT format?
~K
On 04/03/2013 10:52 AM, Kerry wrote:
> Here's the first 5 lines of my dataset:
>
"id", "x", "y",
"date", "R1dmed", "R1dmean", "R1error", "R2error"), row.names = c(NA,
5L), class = "data.frame")
and here's the code I wrote for this file:
write.table(test, "D:/MooseEncounters
It seems within the last ~3 months Ive been having issues with writing text or
csv files from a R data frame. The problem is multifold and it is hard to
filter out what is going on and where the problem is. So, Im hoping someone
else has come across this and may provide insight.
My curre
Basic question:
Is it correct to assume that when using cutree to set the # clusters
(say k=4), cutree determines the clusters by the largest distances
among all potential clusters?
I've read the R help for cutree and am using it to define the number
of groups to obtain Dunn Index scores (using c
Beautiful! It works perfectly, thanks!
kb
On Oct 21, 7:42 am, Jim Lemon wrote:
> On 10/21/2011 06:25 AM, Kerry wrote:
>
> > Can someone please help me out with this? The ggplot2 suggestion works
> > great but I've spent a few days trying to figure out how to plot 2
> &
values = mycols)
>
> You can always use the labels = argument of scale_colour_manual() to
> assign more evocative legend values, or equivalently, you can assign
> the labels in the cut() function within d3 and d4 to those you want in
> the legend and leave the plot code as is.
&g
If it would help get any assistance with my issue, here's another
method I'm trying (using R sample data):
ggplot(mtcars, aes(disp)) +
geom_point(aes(y = mpg, colour = qsec))+
scale_colour_gradient(low="yellow", high="green")+
geom_point(aes(y = cyl, colour = qsec))+
scale_colour_gradient(low=
m(100)
d1 <- data.frame(x1,y1,z1)
dg1 <-qplot(x1,y1,colour=z1,data=d1)
dg1 + scale_colour_gradient(low="green", high="yellow")
I've been trying to get long format working but it just doesn't make
any sense to me.
Thanks,
kb
On Oct 17, 3:10 pm, Kerry wrote:
>
n,
kb
On Oct 2, 10:42 pm, Ben Bolker wrote:
> Duncan Murdoch gmail.com> writes:
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> > On 11-10-02 1:11 PM, Kerry wrote:
> > > I have 3 columns of data and want to plot each row as a point in a
> > > scatter plot
ata=d1)
dg1 + scale_colour_gradient(low="green", high="yellow")
Thanks,
kb
On Oct 2, 10:42 pm, Ben Bolker wrote:
> Duncan Murdoch gmail.com> writes:
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> > On 11-10-02 1:11 PM, Kerry wrote:
> > > I hav
Murdoch gmail.com> writes:
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> > On 11-10-02 1:11 PM, Kerry wrote:
> > > I have 3 columns of data and want to plot each row as a point in a
> > > scatter plot and want one column to be represented as a color gradient
&g
Thanks, I consider all of those options and tried some, but the
z=color gradient seems the best option for my data.
kb
On Oct 2, 10:42 pm, Ben Bolker wrote:
> Duncan Murdoch gmail.com> writes:
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Yes, perfect! This I can work with.
Thanks,
KB
On Oct 2, 3:55 pm, Duncan Murdoch wrote:
> On 11-10-02 1:11 PM, Kerry wrote:
>
> > I have 3 columns of data and want to plot each row as a point in a
> > scatter plot and want one column to be represented as a color gradien
I have 3 columns of data and want to plot each row as a point in a
scatter plot and want one column to be represented as a color gradient
(e.g. larger values being more red). Anyone know the command or
package for this?
Thanks,
KB
__
R-help@r-project.o
I have weather data that was recorded every hour, and location data (X,Y) that
was recorded every 4 hours. I want to know what the temperature was at
location X,Y. The weather data isn't exactly at the same time. So, I have
written this loop for every location to scan through the weather
ut it, but I didn't want to assume any steps that the
R version of k-s test takes). I plan to explore the ideas and run the
simulations you sent in full over the weekend.
Thanks again!
Kerry
On Nov 11, 12:05 pm, Greg Snow wrote:
> Consider the following simulations (also fixing the pno
>
>
>
> > -Original Message-
> > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> > project.org] On Behalf Of Kerry
> > Sent: Wednesday, November 10, 2010 9:23 PM
> > To: r-h...@r-project.org
> > Subject: [R] Kolmogorov Smirnov Test
&g
I'm using ks.test (mydata, dnorm) on my data. I know some of my
different variable samples (mydata1, mydata2, etc) must be normally
distributed but the p value is always < 2.0^-16 (the 2.0 can change
but not the exponent).
I want to test mydata against a normal distribution. What could I be
doing
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