[R] scaling of nonbinROC penalties - accurate classification with random data?

x sum to some multiple of the number of categories), or (c) is one free to use arbitrarily-scaled penalty matrices? I apologise if I am wasting your by making an obvious mistake. I am a clinician, not a statistician. So, I do not understand the m

[R] scaling of nonbinROC penalties - accurate classification with random data?

[[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and

[R] scaling of nonbinROC penalties

or (c) is one free to use arbitrarily-scaled penalty matrices for estimates of the accuracy of an ordinal gold standard? Thanks, in advance, for your help, Jonathan Williams

[R] FW: NaN from function

turn(y)} ). Thanks, in advance, for your help, Jonathan Williams [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/m

[R] (no subject)

turn(y)} ). Thanks, in advance, for your help, Jonathan Williams __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal

[R] repository of earlier Windows versions of R packages

Dear Helpers, I was trying to find a repository of earlier Windows versions of R packages. However, while I can find the Archives for Linux versions (in the "Old Sources" section of each package's Downloads) , I cannot find one for Windows versions. Does such a repository exist? If so, where ca

[R] nested factors different with/out brackets - is this a design feature?

mparing m1 with m2 or when comparing m3 with m4. With many thanks, in anticipation of your help in explaining this, Jonathan Williams Here is a simple sample code to generate the discrepancies:- set.seed(1) A=factor(rep(c(1:5),600)) B=factor(rep(c(0:2),each=1000)) b=as.numeric(as.character(B)

[R] subtracting 100 from strptime year vector generates missing values in POSIXct where none appear to exist in strptime year vector

Thanks Don MacQueen for this reply to my initial query - please SEE MY REPLIES TO THESE IDEAS AND FURTHER INFORMATION BELOW >From: Don MacQueen [m...@llnl.gov] >Sent: 23 February 2010 21:25 >To: Jonathan Williams; r-help@r-project.org > >Subject: Re: [R] Problem with strptime gen

[R] Problem with strptime generating missing values where none appear to exist

4-05" "1927-04-05" "1927-04-05" "1927-04-05" "1939-04-08" "1939-04-08" "1939-04-08" "1939-04-08" "1938-10-24" "1938-10-24" "1938-10-24" [35] "1938-10-24

[R] Mixed Latin, Greek and subscript characters in axis label

2])), but this prints "A (beta[1-42])". Anything else that I try returns an error (e.g. xlab=expression(A beta[1]42]) returns 'Error: unexpected symbol'). So, I would be very grateful if someone can tell me how to write my label. Thanks, Jonathan Williams

[R] is there a way generate correlated binomial data in R?

Dear R Helpers, Is there a way to generate multivariate correlated binomial data in R, similar to how the rmvbin procedure in package bindata can generate multivariate correlated binary data? Thanks for your help, Jonathan Williams __ R-help@r

[R] AICs from lmer different with summary and anova

s 73.965. There are similar changes for the values of BIC and logLik. Am I doing something wrong, here? If not, which are the real AIC and logLik values for the different models? Thanks for your help, Jonathan Williams Output:- > fit0=lmer(y~x1+x2+(1|id), data=datx); print(summary(fit0),co

[R] lmer overdispersion

family=quasi... But, I may be wrong. If you get more information about this from the great man, then would you please let me know? Thanks, Jonathan Williams __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read

[R] why does regexpr not work with '.'

ch.length") #[1] 1 regexpr('.',f) #find the occurrences '.' in f - should be one at location 4 # but regexpr gives 1 at location 1 #[1] 1 #attr(,"match.length") #[1] 1 Sorry if I am missing something obvious. I'd be very grateful i