Hi John,
Thanks for the reply; I'm pasting here the output from dput, with a
'df <-' added in front:
df <- structure(list(rowNum = c(1, 2, 3), first = structure(c(NA, 1L,
2L), .Label = c("AD=2;BA=8", "AD=9;BA=1"), class = "factor"),
second = structure(c(2L, 1L, NA), .Label = c("AD=1;BA=2"
Hi all,
I've read in a large data frame that has formatting similar to the one
in the small example below:
df <-
data.frame(c(1,2,3),c(NA,"AD=2;BA=8","AD=9;BA=1"),c("AD=13;BA=49","AD=1;BA=2",NA));
names(df) <- c("rowNum","first","second")
> df
rowNum first second
1 1 AD=
Hello all,
I would like to take a data frame such as the following one:
> df <-
data.frame(id=c("A","A","B","B"),first=c("BX",NA,NA,"LF"),second=c(NA,"TD","BZ",NA),third=c(NA,NA,"RB","BT"),fourth=c("LG","QR",NA,NA))
> df
id first second third fourth
1 ABX LG
2 A TD
David,
I do appreciate your help, if not the dose of contempt. I hope you
feel OK.
Thanks for the tips,
-Jonathan
On Wed, Jul 29, 2015 at 11:14 PM, David Winsemius
wrote:
>
> On Jul 29, 2015, at 7:37 PM, Jon BR wrote:
>
> > Hello,
> >I've recently discovered
gt; select(name, drink, cost, sex)
>
> The last select statement puts the output in the column order you wanted
> in your result.
>
> I hope this helps.
>
> Brian
>
>
>
> On Wed, Jul 29, 2015 at 9:37 PM, Jon BR wrote:
>
>> Hello,
>> I've r
Hello,
I've recently discovered the helpful dplyr package. I'm using the
'aggregate' function as such:
bevs <- data.frame(cbind(name = c("Bill", "Mary"), drink = c("coffee",
"tea", "cocoa", "water"), cost = seq(1:8), sex = c("male","female")));
bevs$cost <- seq(1:8)
> bevs
name drink cos
304.02
7 A_1 A bc2 319.79
8 A_2 A bc2 186.84
9 A_3 A bc2 125.80
10 A_4 A bc294.87
11 B_1 B bc2 1008.19
12 B_2 B bc2 314.02
Thanks.
On Wed, Jun 3, 2015 at 5:44 PM, Jon BR wrote:
> Hello,
>
> I would like to ask for so
Hello,
I would like to ask for some advice in reformatting a data frame such as
the following one:
gIN <- c("A_1","A_2","A_3","A_4","B_1","B_2")
bc1 <- c(1219.79, 1486.84, 1255.80, 941.87, 588.19, 304.02)
bc2 <- c(319.79, 186.84, 125.80, 94.87, 1008.19, 314.02)
group <- c("A","A","A","A","B","B"
Hi R-help,
Although I know that variations of this question are frequently asked,
I searched and haven't found an answer for this specific variant, and
wonder if any of you know this off the top of your head:
df1 <- data.frame(a = 1:5,
row.names = letters[1:5]) # letters a to
Hello,
I'm having fun exploring the pretty graphing options in R, although
I'm struggling to figure out how to do some simple things; would be
thankful if someone could point me toward relevant sections of the manual
or provide some starter code to get me going.
I'd like to extend what is offer
ot;) #should work
>
> But, if you wanted to use ?write.table() and also to substitute zeros,
> perhaps:
>
>
> res[,2:4] <- lapply(res[,2:4],function(x) {x1
> <-unlist(lapply(x,paste,collapse=","));x1[x1==""] <- 0; x1})
>
>
> str(res)
> #&#x
actors=FALSE)
> res <- dcast(df,gene~case,value.var="issue",list)
> res
> # genecase_1 case_2 case_3
> #1 gene1 nsyn, ampdel
> #2 gene2 UTR
>
>
> A.K.
>
>
> On Wednesday, October 23, 2013 7:38 PM, Jon BR
> wrote:
> H
Hello,
I've been running several programs in the unix shell, and it's time to
combine results from several different pipelines. I've been writing shell
scripts with heavy use of awk and grep to make big text files, but I'm
thinking it would be better to have all my data in one big structure in
Hi All,
I'm trying to use the "sample" function within a loop where the
vector being sampled from (the first argument in the function) will
vary in length and composition. When the vector is down in size to
containing only one element, I run into the "undesired behaviour"
acknowledged in the ?
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