Given your "input: data frame, with variables "V1" and "V2", here's a solution.
This might not be the most "R-like" solution, since I'm still more of a Python
refugee than a native R coder.
-John
# analyze input, using run-length encoding
runs_table = rle(input$V1)
number_of_runs = length(runs
I'm using the dplyr package to perform one-row-at-a-time processing of a data
frame:
> rnd6 = function() sample(1:300, 6)
> frm = data.frame(AA=rnd6(), BB=rnd6(), CC=rnd6())
> frm
AA BB CC
1 123 50 45
2 12 30 231
3 127 147 100
4 133 32 129
5 66 235 71
6 38 264 261
The interface is
In the course of slicing-and-dicing some data, I had occasion to create a list
like this:
list(
subset(my_dataframe, GR1=="XX1"),
subset(my_dataframe, GR1=="XX2"),
subset(my_dataframe, GR1=="YY"),
subset(my_dataframe, GR1 %in% c("XX1", "XX2")),
subset(my_dataframe, GR2=="Remi
Kate, here's a solution that uses regular expressions, rather than vector
manipulation:
> mystr = "ID1 A A T G C T G C G T C G T A"
> gsub(" ([ACGT]) ([ACGT])", " \\1\\2", mystr)
[1] "ID1 AA TG CT GC GT CG TA"
-John
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.o
I'm coming to R from Python, so I coded a Python3 solution:
#
data = """alabama
bates
tuscaloosa
smith
arkansas
fayette
little rock
alaska
juneau
nome
""".split()
state_list = ["alabama", "arkansas", "alaska"] # etc.
return_list = []
for word in data:
if word in state_l
e-
> From: Jeff Newmiller [mailto:jdnew...@dcn.davis.ca.us]
> Sent: Sunday, December 07, 2014 3:14 PM
> To: John Posner
> Cc: 'Chel Hee Lee'; Morway, Eric; R mailing list
> Subject: Re: [R] Condensing data.frame
>
> dplyr version (good for large datasets):
>
> l
Here's a solution using the plyr library:
library(plyr)
dat <- read.table(header=TRUE, sep=",", as.is=TRUE, ## < as.is=TRUE
text="site,tax_name,count,countTotal,countPercentage
CID_1,Cyanobacteria,46295,123509,37.483098398
CID_1,Proteobacteria,36120,123509,29.244832
structure(list(Id = structure(1:10, .Label = c("P01", "P02",
"P03", "P04", "P05", "P06", "P07", "P08", "P09", "P10"), class = "factor"),
Sex = structure(c(2L, 1L, 1L, 2L, 2L, 2L, 1L, 2L
I got an error when trying to extract a 1-column subset of a data frame (called
"my.output") created by dplyr/summarize. The ncol() function says that
my.output has 4 columns, but "my.output[4]" fails. Note that converting
my.output using as.data.frame() makes for a happy ending.
Is this the in
> -Original Message-
> From: David L Carlson [mailto:dcarl...@tamu.edu]
> Sent: Friday, November 14, 2014 10:25 AM
> To: John Posner; 'r-help@r-project.org'
> Subject: RE: Help with ddply/summarize
>
> I think this is what you want:
>
> > MyVar &l
I have a straightforward application of ddply() and summarize():
ddply(MyFrame, .(Treatment, Week), summarize, MeanValue=mean(MyVar))
This works just fine:
Treatment Week MeanValue
1MyDrug BASELINE 5.91
2MyDrugWEEK 1 4.68
3MyDrugWEEK 2 4.08
4MyDr
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