Please delete drjimle...@gmail.com from your mailing lists. He passed away
a mknth ago.
Regards,
Juel
Wife
On Tue, 17 Oct 2023, 22:58 Sahil Sharma -- Forwarded message -
> From: Sahil Sharma
> Date: Tue, Oct 17, 2023 at 12:10 PM
> Subject: r-stats: Geometric Distribution
> To:
>
Please delete drjimle...@bitwrit.com from your mailing list. He passed away
a month ago.
Regards,
Juel (wife)
On Thu, 19 Oct 2023, 02:09 Ben Bolker There are some answers on Stack Overflow:
>
>
> https://stackoverflow.com/questions/14984989/how-to-avoid-warning-when-introducing-nas-by-coercio
Hello,
I am very sad to let you know that my husband Jim died on 18th September. I
apologise for not letting you know earlier but I had trouble finding the
password for his phone.
Kind regards,
Juel
On Fri, 29 Sep 2023, 01:48 Shu Fai Cheung Hi All,
>
> There is a thread about the use of save(), l
Hello,
I am very sad to let you know that my husband Jim died in 18th September. I
apologise for not letting you know earlier but I had trouble finding the
password for his phone.
If you wish to do an obituary please let me know by emailing
juelsallybri...@gmail.com, I can send info through.
Kind r
Hello,
I am very sad to let you know that my husband Jim died in 18th September. I
apologise for not letting you know earlier but I had trouble finding the
password for his phone.
Kind regards,
Juel Briggs
On Thu, 5 Oct 2023, 02:07 Ivan Krylov В Wed, 4 Oct 2023 14:32:49 +
> John Neset пишет:
HI Jeff,
This might give you a start.
add_stuff<-function(x) {
x<-xinc<-NA
finished<-FALSE
while(is.na(x))
x<-as.numeric(readline("What number do you want to start? "))
while(is.na(xinc) || !finished) {
xinc<-as.numeric(readline("What number do you want to add? "))
if(is.numeric(xinc)) x
Hi Bert,
The article notes that chatGPT often gets the concept wrong, rather
than the facts. I think this can be traced to the one who poses the
question. I have often encountered requests for help that did not ask
for what was really wanted. I was recently asked if I could
graphically concatenate
Hi Kostas,
The function vectorField in the plotrix package may do what you want.
See the example.
Jim
On Tue, Jul 25, 2023 at 9:30 PM konstantinos christodoulou
wrote:
>
> Dear Rcommunity,
>
> I hope this email finds you well. I am writing to seek your assistance with
> a data visualization prob
I haven't really focused on the statistical capabilities of AI, that
marriage of massive memory and associative learning. I am impressed by
its ability to perform text-to-image conversion, something I have
recently needed. My artistic ability is that of the average three year
old, yet I can employ
Hi John,
I'm not sure how to do this with ggplot, but:
Time<- c("Age.25","Age.35","Age.45","Age.55")
Medians<-c(128.25,148.75,158.5,168.75)
> is.character(Time)
# [1] TRUE - thus it has no intrinsic numeric value to plot
> is.numeric(Medians)
# [1] TRUE
# coerce Medians to factor and then plot aga
2 3 4 5 9
> None 1 3.05 2.29 2.24 1.71 1.30 2.83
> Equity 2 29.76 28.79 29.51 28.90 31.67 36.77
> Debt 3 31.18 32.64 34.31 35.65 37.59 33.15
> Hybrid 4 36.00 36.27 33.94 33.74 29.44 27.25
> Bank AC
> None 1 46.54 54.01 59.1 62.17 67.67 60.87
> Current 2 24.75 24.4 25 24.61 24
Hi Anupam,
Haven't heard from you in a long time. Perhaps you want something like this:
at_df<-read.table(text=
"Income MF MF_None MF_Equity MF_Debt MF_Hybrid Bank_None Bank_Current
Bank_Savings Bank_NA
$10 1 3.05 29.76 31.18 36.0 46.54 24.75 25.4 3.307
$25 2 2.29 28.79 32.64 36.27 54.01 24.4 1
Hi Mohsin,
I must have hit the wrong key and sent the last email. The last
paragraph should read:
To answer your question, I used the "laxlab" and "raxlab" arguments. I
also extended them to 0-200 to cover the range of the largest counts.
You can use 0-150 for both, but it is not a good idea to r
Hi Mohsin,
As I don't have your data, I had to fake it, so there are probably
some mistakes in the example below:
# my suggestion
x<-c(143,108,95,72,70,85,125,123,64,67,144,55,60,200,70,100,65,140,49,45,77,58,66,50,77)
y<-c(41,32,28,13,15,29,72,71,17,180,9,13,145,29,56,22,97,13,9,42,20,7,30,10,41)
Hi Bruce,
Reading your message, I get the idea that you want a radial.plot with
arcs to indicate "at least one bat is in this state'.This can be done
with an addition to the rp.type= argument. If you already have what
you want in this format, it may not be worth programming it. However,
if you want
t;> ... in which case they should simply email the author directly, no?
>>
>> -- Bert
>>
>> On Fri, Apr 21, 2023 at 3:22 PM Jim Lemon wrote:
>> >
>> > Hi Yeswanth,
>> > You seem to be referring to a specific publication by a specific
>> &g
Hi Yeswanth,
You seem to be referring to a specific publication by a specific
author. Unless someone in R-help knows who and what you are referring
to, it seems very difficult. Perhaps you could supply a reference to
the work you are using?
JIm
On Sat, Apr 22, 2023 at 7:03 AM ADIGARLA YESWANTH NA
Also see the "arctext" function in the plotrix package.
Jim
On Fri, Mar 31, 2023 at 11:12 AM Jim Lemon wrote:
>
> Hi Jinsong,
> Maybe "srt" will do what you want. As you noted non-orthogonal
> rotations may not work on some devices. You may be able to download
Hi Jinsong,
Maybe "srt" will do what you want. As you noted non-orthogonal
rotations may not work on some devices. You may be able to download
mirror fonts from places like fontmirror.com, but it more complicated.
Jim
On Thu, Mar 30, 2023 at 7:25 PM Jinsong Zhao wrote:
>
> Hi there,
>
>
> I just
Hi all,
I was quite intrigued by George's question, for I thought this might
be a problem faced by many. The solution attached is only useful for a
monotonically increasing x vector, a paired vector of y values, and a
criterial value above which a polygon will be displayed. More work
would needed f
Hi Gavin,
I can't work through this right now, but I would start by looking at
the 'hetcor' package to get the correlations, or if they are already
in the return object, build a plot from these.
Jim
On Wed, Feb 22, 2023 at 4:24 AM gavin duley wrote:
>
> Hi!
>
> Apologies if this is not the corre
Hi Nicole,
plotrix is intended to be modular, that is, it builds plots step by step.
This makes it easier to understand code that you haven't written or haven't
seen for a while. Here is an example showing how to change the font using
par():
library(plotrix)
plot(0,type="n",xlim=c(0,1),ylim=c(-1,0
Hi Bogdan,
Try this:
A<-data.frame(x=c(1,7,9,20),
y=c(39,91,100,3))
B<-data.frame(x=c(10,21,67,99,200),
y=c(9,89,1000,90,1001)) # one value omitted to equalize the rows
xrange<-range(c(unlist(A$x),unlist(B$x)))
yrange<-range(c(unlist(A$y),unlist(B$y)))
plot(A,type="l",xlim=xrange,ylim=yrange,col
Hi Upananda,
As a couple of respondents noted, you only need the logical statement,
not subset().
You did "frame the logical condition" in your example, for if you use
the extraction operator "[" this will work:
subset(p,(1:length(p)) <= 20)
as Jeff already pointed out. Obviously it is easier to w
Hi Upananda,
First, the date sequence you are using doesn't match the dates you
specify in your post. The code below may give you what you want:
# make up some prices
price<-c(seq(60,25,length.out=25),seq(25,70,length.out=54))+rnorm(79)
pricet <- ts(price, start = as.Date("2020-01-27"),end=as.Date
Hi Steven,
I thought that the problem might be in the two large numbers, but
using a subset (I didn't want to edit out all the line numbers), I get
what I expected:
sydf<-read.table(text="Mean Std.dev
[1,] 0.3107966 0.462820
[2,] 0.1880302 0.390736
[3,] 45.3185794 16.313635
[4,] 0.50663
Hi Erin,
If you want a realistic 3D prism, I would use something like POVRay or
other rendering software. You have to know your geometry, but you can
get a very realistic image. I suspect that you want more than just a
picture of a prism, so you can then generate a PNG image and use it as
a layer i
Hi Eva,
As it says in the footer, go here:
https://stat.ethz.ch/mailman/listinfo/r-help
Jim
On Wed, Nov 2, 2022 at 6:51 AM Eva Maria Leunissen
wrote:
>
> Hi,
>
> Could I please unsubscribe from the R-help mailing list?
>
> Thanks
>
> Eva
>
> [[alternative HTML version deleted]]
>
>
Hi Thomas,
I have assumed the format of your p-value matrix. This may require
some adjustment.
A B C D E F
A 1 0.7464 0.01870.0865 0.0122 0.4693
B 0.7464 1 0.03580.1502 0.0173 0.3240
C 0.0187
Hi Mary,
I didn't see any answers to your post, but doing something like this
is quite easy in base graphics. If you are still stuck, I may be able
to suggest something.
Jim
On Mon, Oct 10, 2022 at 6:05 PM Putt, Mary wrote:
>
>
> I have created several plots using the forestplot package and the
dered Logit /
> Probit Probabilities", :
>unused arguments (fortytwo, "\n")
>
> On 10/13/2022 4:46 PM, Jim Lemon wrote:
> > Hi Steven & Erin,
> > This works:
> >
> > fortytwo<-42
> > cat("\nMarginal and Discrete Effects of Ge
Hi Steven & Erin,
This works:
fortytwo<-42
cat("\nMarginal and Discrete Effects of Gen Ordered Logit / Probit
Probabilities","logisitic =",fortytwo,"\n")
j<-grep(".one\\b",c(".one\\a",".one\\b"))
Marginal and Discrete Effects of Gen Ordered Logit / Probit
Probabilities logisitic = 42
If I don't
Hi Steven,
I think Erin is right, unless there is a variable named "logistic"
visible within the function, "cat" will think it is either an argument
or an R object. If you have the "psych" package loaded, it may see it
as a closure. There is also a "Logistic" in the stats package, but
that shouldn'
Hi Marine,
I'm not sure that I have the right idea, but this worked for me and may help.
# I had to fix this line
df<-data.frame(id=rep(1:10,each=10),item1=sample(1:20, 100, replace=TRUE))
df2<-data.frame(a=c(8, 8,10,9, 5, 1,2,1),b=c(16,18,11, 19,18, 11,17,12))
result<-data.frame(id=df[,1],rown=1:
Hi Tariq,
There were a couple of glitches in your data structure. Here's an
example of a simple plot:
dat<-structure(list(year = c(2018, 2019, 2019, 2019, 2019, 2019, 2019,
2019, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017, 2017,
2017, 2017, 2018, 2018, 2018, 2018, 2018, 2018, 2018, 2018,
Given some of the questions that are posted to this list, I am not
sure that there is an upper bound to the estimate.
Jim
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read th
Hi Admire,
Your attachment didn't get through, although CSV format should. The
code you included seems a very roundabout way to extract a series of
dates as character strings and as there is no assignment of return
values in some lines, is unlikely to work. Perhaps if you send just a
few of the ori
Hi David,
No, read.table converts a text representation of data into a data frame object.
Jim
On Sat, Sep 24, 2022 at 2:29 AM DFP wrote:
>
> Do I need that read.table if the tst dataframe already exists in my
> system? If so, why?
>
> --
>
> Hello
Sorry, line 9 should be:
if(substr(air[airline],1,1) == " ")
Jim
On Thu, Sep 22, 2022 at 8:51 AM Jim Lemon wrote:
>
> Hi Javad,
> The example text file you sent doesn't appear to have the two
> "trailer" lines that you describe. I would try this brute forc
tiply by specific number).
> 3- Insert the removed first 8 rows of the original text file as header in the
> dataframe.
> 4- Insert the last 2 rows of the original text file at the end of dataframe.
> 5- Write the dataframe as a new text file exactly similar to the original
> text f
Hi,
There was a .txt attachment that is some type of data file. Maybe what
you mean is can the header be stripped and the rest written out in a
format that can be input with a FORTRAN read routine. Yes, you just
have to read it into a data frame and write it out so that it is in
either free or fixe
Hi David,
I'm back home again. Try this:
b<-read.table(text=
"Dtime DNO2 DVOC Dpm10Dpm2.5 Dpm1 Mtime MNO2 MVOCMpm10 Mpm2.5 Mpm1
18:00 28 164 81.34773 24.695435 14 18:00 19 151 3.00 21
18:01 27 163 74.44034 23.751198 14 18:01 20 148 3.00 21
2022 at 7:41 AM Parkhurst, David wrote:
>
> I just sent a subset of the data, with a dataframe called test. Can you see
> that? It may not have been approved by the moderator yet.
>
> DFP (iPad)
>
> > On Sep 19, 2022, at 5:29 PM, Jim Lemon wrote:
> >
> > Hi
Hi David,
Since you used read.csv to get the data frame, the file must be i text
format. If you can include a few lines of the input (with made up NO2
values if necessary), it would be easy to respond with the required
commands and a plot.
Jim
On Mon, Sep 19, 2022 at 9:12 PM Parkhurst, David wro
Hi Stefano,
The bar x centers are returned by the barplot function. You can also
use the barp function (plotrix package) that places the bars at unit
intervals by default.
Jim
On Thu, Sep 15, 2022 at 3:47 PM Stefano Sofia
wrote:
>
> Dear R-list users,
>
> I have a silly problem with plot that I
Hi Subhamitra,
I think the fact that you are passing a vector of values rather than a
matrix is part of the problem. As you have only one value for each
country, The points plotted will be the index on the x-axis and the
value for each country on the y-axis. Passing a value for ylim= means
that you
Hi Javad,
In that case, just modify the function to extract the rows with both
the minimum and maximum Q from each station
df1<-read.table(text="Code Y M D Q N O
41003 81 1 19 0.16 7.17 2.5
41003 77 9 22 0.197 6.8 2.2
41003 79 7 28 0.21 4.7 6.2
41005 79 8 17 0.21 5.5 7.2
41005 80 10 30 0
HI Erin,
Just index out the lines in the result vector.
Jim
On Sun, Aug 7, 2022 at 10:16 AM Erin Hodgess wrote:
>
> Hello!
>
> Is there a way to read the first line of a CSV file, then skip 4 lines,
> then continue reading, please?
>
> I know you can skip from the top, but I don't know if you ca
Hi Roslina,
I think you have changed the code as "bc_start" in my code is
"BCStartTime" in yours. When I run the attached code, I get a data
frame "hourly_SoC" that looks right, and a matrix "result" (hour by
SoC) that checks against the data frame. I have tried to comment the
code so that you an s
Hi Chishti,
Try this:
dim(x)[2]
length(dn)
>From your error message, the two will be different. They should be the
same. A wild guess is that the offending line of code should be:
dimnames[2]<-1:dn
Jim
On Tue, Jun 21, 2022 at 11:10 PM Muhammad Zubair Chishti
wrote:
>
> Hi, Dear Professor,
> W
Hi Kalaivani,
The N.cohen.kappa function was written by Matthais Gamer, the
maintainer of the irr package. Both that function and N2.cohen.kappa
(written by Puspendra Singh) involve corrections that are described in
the references on the respective help pages. It is likely that there
will be small
> 2-1
> 2-2 2- 2
> "snp003""C" "A" 11.03
> 2
> 0 1
> "snp004""G" &q
.
> For instance i am looking the data
> mydf
> IDnumber OA EA beta
> 11 A C 0.050
> 22 G A 0.098
> 33 T G 0.789
>
> Best,
> Hana
>
>
>
> Original message
> From: Jim Lemon
> Date: 6/12/22 1:59 AM (GMT+03:
Hi Hana,
I think this is what you want:
# first read in your example
mydf<-read.table(text=
"IDnumber OA EA beta
1 C A -0.05
2 GA0.098
3 GT-0.789",
header=TRUE,stringsAsFactors=FALSE)
# check it
mydf
IDnumber OA EA beta
11 C A -0.05
Hi Erin,
Here's a kinda clunky way to get your plot title. It can be modified
to do fancier things like intersperse symbols with letters but you may
need no more than this. Have fun.
par(mar=c(5,4,5,2))
plot(0,xlim=c(-1,1),ylim=c(-1,1),type="n",xlab="Nonsense",ylab="Intensity")
points(runif(4,-1,1
Hi Richard,
Thinking about this, you might also find intersectDiagram, also in
plotrix, to be useful.
Jim
On Mon, May 30, 2022 at 4:37 PM Jim Lemon wrote:
>
> Hi Richard,
> Some years ago I had a try at illustrating Multiple Causes of Death
> (MCoD) data. I settled on what is someti
Hi Richard,
Some years ago I had a try at illustrating Multiple Causes of Death
(MCoD) data. I settled on what is sometimes called a "sizetree". You
can see some examples in the sizetree function help page in "plotrix".
Unfortunately I can't use the original data as it was confidential.
Jim
On Mo
Hi Neha,
As you have a distinguishing feature in the variable names, here is
one way to do it:
RF<- c(4.7, 1.52, 1.46, 4.5, 0.62, 1.12)
RF_LOO<- c(5.2, 1.52, 1.44, 4.3, 0.64, 1.11)
RF_boot<- c(5.8, 1.5, 1.23, 4.3, 0.64, 1.12)
Ranger<- c(4.5, 1.57, 1.25, 3.75, 0.56, 1.09)
Ranger_LOO<- c(5, 1.56, 1.
I haven't used the plotrix
> before
>
> On Sun, May 15, 2022 at 10:56 AM Jim Lemon wrote:
>>
>> Hi,
>> There are a number of functions that will transform numeric values
>> into colors. One is color.scale in the plotrix package. This accepts a
>> vect
Hi,
There are a number of functions that will transform numeric values
into colors. One is color.scale in the plotrix package. This accepts a
vector of numeric values and linearly transforms them into one or more
ranges of colors. The resulting colors can then be passed to the
appropriate arguments
Hi Paul,
Based on my guess that all values have been normalized, I would say:
mat<-(matrix(runif(16,-5,5),4))
df<-as.data.frame(mat)
df[abs(df) < 3]<-NA
df
V1 V2 V3V4
1 NA 4.675699 3.166625NA
2 NA NA NA 3.463660
3 4.288831 NA 4.0329
HI Paul,
I had a problem a bit like this when trying to implement the Lim-Wolfe
imputation for ranks. The size of the output matrix increases
exponentially with the size of the initial matrix and it goes into
disk-swapping slow motion. It works for small matrices, but rapidly
runs out of memory. I
Hi Neha,
The error message is about not having _factors_ with two or more
levels. Apart from using stringsAsFactors=FALSE (meaning that you
probably won't get any factors in "d"), your sample data doesn't look
like CSV format. Perhaps the lines have been truncated. You may get
something with string
Hi Ani,
It seems to work for me:
a<-c(20, 20, 14.2375646029948, 19.9, 20, 20, 16.3092078677214,
20, 20, 20, 20, 20, 20, 20, 20, 14.8590932408795, 16.178935255298,
20, 20, 20, 20, 27.6404077886079, 20, 20, 20, 20, 20, 21.9857063037444,
20, 20, 20, 20)
> a==20
[1] TRUE TRUE FALSE FALS
Hi Nick,
If you can bear using R base graphics, the plotrix package has a
function named "getYmult" that allows you to adjust for the aspect
ratio of any plot area.
Jim
On Sun, Apr 3, 2022 at 11:14 PM Nick Wray wrote:
>
> Hello If you plot a square in the default R studio window you see a
> rec
Hi Kelly,
Perhaps the best place to look is the "car" package. There is a
somewhat confusing reference in the "cookd" function help page to the
"cooks.distance" function in the "base" package that doesn't seem to
be there. Whether this is the case or not, I think you can still use
the "cookd" alia
Hi Eliza,
It sure was:
YY$datetime<-strptime(YY$TIMESTAMP,"%Y/%m/%d %I:%M:%S %p")
dt5min<-seq(ISOdate(2021,5,1,0,5),ISOdate(2021,5,31,12,55),by="5 min")
newdt<-data.frame(datetime=dt5min)
newyy<-merge(newdt,YY,by="datetime",all=TRUE)
newyy$RAINFALL[is.na(newyy$RAINFALL)]<-0
plot(newyy$datetime,new
Hi Avi,
I just sent in an answer to a very simple question. In many cases it
seems to me that the real problem isn't apparent from the request.
ektaraK appears to have almost no experience with R (sorry if I'm
wrong). A person in this position may sort of know what they want to
do but do not know h
Hi ektaraK,
Here is a step by step way to create an example and get your plot:
# make up a lot of dates
dates<-as.Date("2021-1-1")+sample(0:364,100)
# make up the temperatures
temps<-runif(100,0,40)
# create a data frame
mydf<-data.frame(date=dates,temp=temps)
# create a month variable
mydf$month<
Hi Bogdan,
If we take the error message seriously, it may be that the initial X11
image was never displayed. When this very suspicious black box
function tried to transfer the image to a PNG file, it wasn't there or
the function couldn't find it.
Jim
On Sun, Feb 27, 2022 at 2:51 AM Bogdan Tanasa
Hi Love,
I have finally had a chance to look at this more closely. I think that
the following link:
https://cran.r-project.org/web/packages/survival/vignettes/adjcurve.pdf
may be useful. See section 4.2.
This is not my area of expertise, but it seems to be a known problem.
Perhaps by posting to t
Hi Neha,
One sure cure for divide by zero is to omit zeros in the denominator variable.
num<-sample(0:10,20,TRUE)
denom<-sample(0:10,20,TRUE)
zeros<-denom == 0
num[!zeros]/denom[!zeros]
If you don't want to lose those data and there are no negative values,
you could add a small number to all deno
Hi Neha,
You're using the argument "na.omit" in what function? My blind guess
is that there's a divide by zero shooting you from behind.
Jim
On Sat, Jan 15, 2022 at 6:32 AM Neha gupta wrote:
>
> Hi everyone
>
> I use na.omit to remove NAs but still it gives me error
>
> Error in if (fraction <=
Hi,
I wasn't going to contribute to this, but I've got a couple of minutes
and the morning caffeine has hit me.
My 5 Point Plan for taking life as it comes:
1) I don't like to help people, I'd rather trick them into doing it themselves.
2) I'm lazy and intolerant. If somebody wants me to do their w
Hi Jeff,
A completely obscure question deserves a completely obscure answer:
jrdf<-read.table(text="Time Event_AEvent_B Lag_B
1 1 10
2 0 11
3 0 00
4 1 00
5 0 11
6
aya wrote:
>
> Hi Jim,
>
> Thank you for the alternative. Absolutely will try it.
> Can you explain a bit about "Maps draws an approximately 2x1 plot"?
> Is it the size proportion 2 in x-axis and 1 in y-axis?
>
> On Fri, Jan 7, 2022 at 4:41 PM Jim Lemon wrote:
>
Hi Ani,
Blame Mercator. Maps draws an approximately 2x1 plot. Maybe this:
mappar<-par("usr")
rect(mappar[1],mappar[3],mappar[2],mappar[4])
Jim
On Fri, Jan 7, 2022 at 6:25 PM ani jaya wrote:
>
> Dear R expert,
>
> I try to box a figure using box(). However it box the default margin,
> not the sp
Thanks, Bert. I will.
Jim
On Fri, Jan 7, 2022 at 3:44 PM Bert Gunter wrote:
>
> Ask on r-sig-fedora rather than here, no?
>
> On Thu, Jan 6, 2022, 8:18 PM Jim Lemon wrote:
>>
>> Hi,
>> I'm facing the usual challenge of building the latest release of R on
Hi,
I'm facing the usual challenge of building the latest release of R on
a new install of Fedora 35 Linux. Is there a list of dependencies that
have to be installed (or even better, a package) to avoid the
necessity of running ./configure many times and installing them
piecemeal? I've just been r
Hi George,
Same to you. I fooled around with the plot a bit after I sent the email.
Jim
On Mon, Jan 3, 2022 at 8:36 AM george brida wrote:
>
> Thanks a lot Jim. I really appreciate your help. Happy new year 2022.
> George
>
> On Wed, Dec 29, 2021 at 10:10 PM Jim Lemon wrote:
Hi George,
This example is obviously a mess, but it shows the basic elements. The
labels may be placed manually using something like boxed.labels
(plotrix) with lines connecting the labels to the smaller countries.
If you want the labels within the countries you will have to use a big
graphics devi
w it.
Jim
On Wed, Dec 22, 2021 at 9:56 AM Bert Gunter wrote:
>
> But you appear to be missing something, Jim -- see inline below (and
> the original post):
>
> Bert
>
>
> On Tue, Dec 21, 2021 at 2:00 PM Jim Lemon wrote:
> >
> > Please pardon a comment that may
Please pardon a comment that may be off-target as well as off-topic.
This appears similar to a number of things like fuzzy logic, where an
instance can take incompatible truth values.
It is known that an instance may have an attribute with a numeric
value, but that value cannot be determined.
It
Hi Akshay,
It depends upon how the circles are calculated. If each circle
encloses all of the members of each group, yes. I doubt you would get
perfect separation in any real example, though. At the moment:
Hanukkah is finished,
Margashirsha Punima has just happened and
Christmas is coming up.
No m
Hi Winod,
Your first error message seems to be saying that you are passing a
function that returns an "ohic" object rather than the object. Maybe:
ohic<-get.ohlc.yahoo("GOOG",start="2020-12-18",end="2021-12-17")
candlestickChart(ohic,..)
would get you a bit further. Also it's obvious that the fun
Hi Rich,
>From what you sent, it seems like you want to find where the change in
_measurement interval_ occurred. That looks to me as though it is the
first datetime in each row. In the first row, there is a week gap
between the ten and fifteen minute intervals. This may indicate that
no measuremen
Hi mehdi,
Try this (first example in the help page):
ref<-rnorm(30,sd=2)
# add a little noise
model1<-ref+rnorm(30)/2
# add more noise
model2<-ref+rnorm(30)
# display the diagram with the better model
oldpar<-taylor.diagram(ref,model1)
# now add the worse model
taylor.diagram(ref,model2,ad
Hi,
Petr is right. Apparently as.POSIXct drops the smallest increments if
all are zero:
ssdf<-read.csv(text="data_POSIX,Sensor_code,value
2002-11-01 00:00:01,1694,7.2
2002-11-01 00:00:00,1723,10.8",
stringsAsFactors=FALSE)
ssdf$data_POSIX<-as.POSIXct(ssdf$data_POSIX,"%Y-%m-%d HH:MM:SS")
ssdf
Hi Amanze,
The package is apparently "apsurvival", hosted on GitHub:
https://rdrr.io/github/carolinewei/apsurvival/
There seem to be instructions on how to install this, but the
maintainer (Caroline Wei?) doesn't seem to have an email address
listed. Perhaps the easiest thing for you to do is ask
Hi RosalinaZakaria,
Talk about using a sledgehammer to crack a nut. In your example the
two objects are character vectors. How about:
dt_comb1gd <-paste0(dtpaigd,dtpmgd)
Jim
On Fri, Nov 19, 2021 at 2:15 AM ROSLINAZAIRIMAH BINTI ZAKARIA .
wrote:
>
> Dear all,
>
> I try to merge two columns consi
Hi Luigi,
Maybe multinomial regression?
https://www.r-bloggers.com/2020/05/multinomial-logistic-regression-with-r/
Jim
On Tue, Nov 16, 2021 at 7:33 PM Luigi Marongiu wrote:
>
> Hello,
> I have a large database with a column containing a factor:
> ```
> > str(df)
> 'data.frame': 500 obs. of
Hi Abou,
Perhaps this will be helpful. Be aware that you will cop some flak for
putting error bars on a bar plot.
aadat<-data.frame(group=c(rep("Exp",50),rep("Con",50)),
v1=sample(0:1,100,TRUE),
v2=sample(0:1,100,TRUE),
v3=sample(0:1,100,TRUE),
v4=sample(0:1,100,TRUE),
v5=sample(0:1,100,TRUE)
Hi Steve,
That plot looks to me as though a value-to-color transformation is
performed on the logarithm of gene expression. The scale bar can be
roughly reproduced like this:
library(plotrix)
plot(0,xlim=c(0,3))
gradient.rect(0,-0.1,3,0.1,
col=color.scale(seq(0,3,0.1),
c(0.7,1,1,1,0.7,0.2),
c(0
Hi Val,
Try this:
dat=read.csv("myfile.csv",stringsAsFactors=FALSE)
However, the apparently silent conversion of format is a mystery to
me. The only time I have struck something like this was when exporting
dates from Excel some years ago, and there was a silent conversion to
mm/dd/ format if
Hi Gabrielle,
I get the feeling that you are trying to merge data in which each file
contains different variables, but the same subjects have contributed
the data. This a very wild guess, but it may provide some insight.
# assume that subjects are identified by a variable named "subjectID"
# creat
Hi Val,
I think you answered your own question:
by(dat$wt,dat[,c("Sex","Year")],mean)
Jim
On Tue, Nov 2, 2021 at 8:09 AM Val wrote:
>
> Hi All,
>
> How can I generate mean by group. The sample data looks like as follow,
> dat<-read.table(text="Year Sex wt
> 2001 M 15
> 2001 M 14
> 2001 M 16
> 2
Hi bharat,
There are a number of ways to do this in R. One is:
library(plotrix)
example(size_n_color)
Jim
On Tue, Nov 2, 2021 at 6:43 AM bharat rawlley via R-help
wrote:
>
> Thank you very much, for your time and response!
> This did resolve my issue and I apologize if the question was a littl
Hi Alice,
I can see from your two questions that your English is a bit shaky.
This is not a criticism, I couldn't speak Chinese to save my life. I
looked around for a Chinese R help mailing list and couldn't find one.
Perhaps someone else knows of one. Not only would it make your life
easier at the
Hi Cleber,
Looks like Deja Vu Sans Bold to me. If you have the GIMP, check it out.
Jim
On Sun, Oct 31, 2021 at 1:35 PM Cleber Borges via R-help
wrote:
>
> I once saw an internet article someone who made all the letters of the
> alphabet with the R logo style (font type, blue color and bow).
> I
ol],"\n")
}
}
On Thu, Oct 28, 2021 at 8:01 PM Anas Jamshed wrote:
>
> where should I place cat(row,col,mat_1[row,col],"\n")?
>
> On Thu, Oct 28, 2021 at 1:58 PM Jim Lemon wrote:
>>
>> Hi Anas,
>> How about:
>>
>> cat(row,col,mat_1
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